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Description: Two ways to say that A and B partition C (when A and B don't overlap and A is a part of C ). (Contributed by FL, 17-Nov-2008) (Proof shortened by JJ, 14-Jul-2021)
| Ref | Expression | ||
|---|---|---|---|
| Assertion | uneqdifeq | ⊢ ( ( 𝐴 ⊆ 𝐶 ∧ ( 𝐴 ∩ 𝐵 ) = ∅ ) → ( ( 𝐴 ∪ 𝐵 ) = 𝐶 ↔ ( 𝐶 ∖ 𝐴 ) = 𝐵 ) ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | uncom | ⊢ ( 𝐵 ∪ 𝐴 ) = ( 𝐴 ∪ 𝐵 ) | |
| 2 | eqtr | ⊢ ( ( ( 𝐵 ∪ 𝐴 ) = ( 𝐴 ∪ 𝐵 ) ∧ ( 𝐴 ∪ 𝐵 ) = 𝐶 ) → ( 𝐵 ∪ 𝐴 ) = 𝐶 ) | |
| 3 | 2 | eqcomd | ⊢ ( ( ( 𝐵 ∪ 𝐴 ) = ( 𝐴 ∪ 𝐵 ) ∧ ( 𝐴 ∪ 𝐵 ) = 𝐶 ) → 𝐶 = ( 𝐵 ∪ 𝐴 ) ) |
| 4 | difeq1 | ⊢ ( 𝐶 = ( 𝐵 ∪ 𝐴 ) → ( 𝐶 ∖ 𝐴 ) = ( ( 𝐵 ∪ 𝐴 ) ∖ 𝐴 ) ) | |
| 5 | difun2 | ⊢ ( ( 𝐵 ∪ 𝐴 ) ∖ 𝐴 ) = ( 𝐵 ∖ 𝐴 ) | |
| 6 | eqtr | ⊢ ( ( ( 𝐶 ∖ 𝐴 ) = ( ( 𝐵 ∪ 𝐴 ) ∖ 𝐴 ) ∧ ( ( 𝐵 ∪ 𝐴 ) ∖ 𝐴 ) = ( 𝐵 ∖ 𝐴 ) ) → ( 𝐶 ∖ 𝐴 ) = ( 𝐵 ∖ 𝐴 ) ) | |
| 7 | incom | ⊢ ( 𝐴 ∩ 𝐵 ) = ( 𝐵 ∩ 𝐴 ) | |
| 8 | 7 | eqeq1i | ⊢ ( ( 𝐴 ∩ 𝐵 ) = ∅ ↔ ( 𝐵 ∩ 𝐴 ) = ∅ ) |
| 9 | disj3 | ⊢ ( ( 𝐵 ∩ 𝐴 ) = ∅ ↔ 𝐵 = ( 𝐵 ∖ 𝐴 ) ) | |
| 10 | 8 9 | bitri | ⊢ ( ( 𝐴 ∩ 𝐵 ) = ∅ ↔ 𝐵 = ( 𝐵 ∖ 𝐴 ) ) |
| 11 | eqtr | ⊢ ( ( ( 𝐶 ∖ 𝐴 ) = ( 𝐵 ∖ 𝐴 ) ∧ ( 𝐵 ∖ 𝐴 ) = 𝐵 ) → ( 𝐶 ∖ 𝐴 ) = 𝐵 ) | |
| 12 | 11 | expcom | ⊢ ( ( 𝐵 ∖ 𝐴 ) = 𝐵 → ( ( 𝐶 ∖ 𝐴 ) = ( 𝐵 ∖ 𝐴 ) → ( 𝐶 ∖ 𝐴 ) = 𝐵 ) ) |
| 13 | 12 | eqcoms | ⊢ ( 𝐵 = ( 𝐵 ∖ 𝐴 ) → ( ( 𝐶 ∖ 𝐴 ) = ( 𝐵 ∖ 𝐴 ) → ( 𝐶 ∖ 𝐴 ) = 𝐵 ) ) |
| 14 | 10 13 | sylbi | ⊢ ( ( 𝐴 ∩ 𝐵 ) = ∅ → ( ( 𝐶 ∖ 𝐴 ) = ( 𝐵 ∖ 𝐴 ) → ( 𝐶 ∖ 𝐴 ) = 𝐵 ) ) |
| 15 | 6 14 | syl5com | ⊢ ( ( ( 𝐶 ∖ 𝐴 ) = ( ( 𝐵 ∪ 𝐴 ) ∖ 𝐴 ) ∧ ( ( 𝐵 ∪ 𝐴 ) ∖ 𝐴 ) = ( 𝐵 ∖ 𝐴 ) ) → ( ( 𝐴 ∩ 𝐵 ) = ∅ → ( 𝐶 ∖ 𝐴 ) = 𝐵 ) ) |
| 16 | 4 5 15 | sylancl | ⊢ ( 𝐶 = ( 𝐵 ∪ 𝐴 ) → ( ( 𝐴 ∩ 𝐵 ) = ∅ → ( 𝐶 ∖ 𝐴 ) = 𝐵 ) ) |
| 17 | 3 16 | syl | ⊢ ( ( ( 𝐵 ∪ 𝐴 ) = ( 𝐴 ∪ 𝐵 ) ∧ ( 𝐴 ∪ 𝐵 ) = 𝐶 ) → ( ( 𝐴 ∩ 𝐵 ) = ∅ → ( 𝐶 ∖ 𝐴 ) = 𝐵 ) ) |
| 18 | 1 17 | mpan | ⊢ ( ( 𝐴 ∪ 𝐵 ) = 𝐶 → ( ( 𝐴 ∩ 𝐵 ) = ∅ → ( 𝐶 ∖ 𝐴 ) = 𝐵 ) ) |
| 19 | 18 | com12 | ⊢ ( ( 𝐴 ∩ 𝐵 ) = ∅ → ( ( 𝐴 ∪ 𝐵 ) = 𝐶 → ( 𝐶 ∖ 𝐴 ) = 𝐵 ) ) |
| 20 | 19 | adantl | ⊢ ( ( 𝐴 ⊆ 𝐶 ∧ ( 𝐴 ∩ 𝐵 ) = ∅ ) → ( ( 𝐴 ∪ 𝐵 ) = 𝐶 → ( 𝐶 ∖ 𝐴 ) = 𝐵 ) ) |
| 21 | simpl | ⊢ ( ( 𝐴 ⊆ 𝐶 ∧ ( 𝐶 ∖ 𝐴 ) = 𝐵 ) → 𝐴 ⊆ 𝐶 ) | |
| 22 | difssd | ⊢ ( ( 𝐶 ∖ 𝐴 ) = 𝐵 → ( 𝐶 ∖ 𝐴 ) ⊆ 𝐶 ) | |
| 23 | sseq1 | ⊢ ( ( 𝐶 ∖ 𝐴 ) = 𝐵 → ( ( 𝐶 ∖ 𝐴 ) ⊆ 𝐶 ↔ 𝐵 ⊆ 𝐶 ) ) | |
| 24 | 22 23 | mpbid | ⊢ ( ( 𝐶 ∖ 𝐴 ) = 𝐵 → 𝐵 ⊆ 𝐶 ) |
| 25 | 24 | adantl | ⊢ ( ( 𝐴 ⊆ 𝐶 ∧ ( 𝐶 ∖ 𝐴 ) = 𝐵 ) → 𝐵 ⊆ 𝐶 ) |
| 26 | 21 25 | unssd | ⊢ ( ( 𝐴 ⊆ 𝐶 ∧ ( 𝐶 ∖ 𝐴 ) = 𝐵 ) → ( 𝐴 ∪ 𝐵 ) ⊆ 𝐶 ) |
| 27 | eqimss | ⊢ ( ( 𝐶 ∖ 𝐴 ) = 𝐵 → ( 𝐶 ∖ 𝐴 ) ⊆ 𝐵 ) | |
| 28 | ssundif | ⊢ ( 𝐶 ⊆ ( 𝐴 ∪ 𝐵 ) ↔ ( 𝐶 ∖ 𝐴 ) ⊆ 𝐵 ) | |
| 29 | 27 28 | sylibr | ⊢ ( ( 𝐶 ∖ 𝐴 ) = 𝐵 → 𝐶 ⊆ ( 𝐴 ∪ 𝐵 ) ) |
| 30 | 29 | adantl | ⊢ ( ( 𝐴 ⊆ 𝐶 ∧ ( 𝐶 ∖ 𝐴 ) = 𝐵 ) → 𝐶 ⊆ ( 𝐴 ∪ 𝐵 ) ) |
| 31 | 26 30 | eqssd | ⊢ ( ( 𝐴 ⊆ 𝐶 ∧ ( 𝐶 ∖ 𝐴 ) = 𝐵 ) → ( 𝐴 ∪ 𝐵 ) = 𝐶 ) |
| 32 | 31 | ex | ⊢ ( 𝐴 ⊆ 𝐶 → ( ( 𝐶 ∖ 𝐴 ) = 𝐵 → ( 𝐴 ∪ 𝐵 ) = 𝐶 ) ) |
| 33 | 32 | adantr | ⊢ ( ( 𝐴 ⊆ 𝐶 ∧ ( 𝐴 ∩ 𝐵 ) = ∅ ) → ( ( 𝐶 ∖ 𝐴 ) = 𝐵 → ( 𝐴 ∪ 𝐵 ) = 𝐶 ) ) |
| 34 | 20 33 | impbid | ⊢ ( ( 𝐴 ⊆ 𝐶 ∧ ( 𝐴 ∩ 𝐵 ) = ∅ ) → ( ( 𝐴 ∪ 𝐵 ) = 𝐶 ↔ ( 𝐶 ∖ 𝐴 ) = 𝐵 ) ) |