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Description: A stronger form of pwuninel . We can use pwuninel , 2pwuninel to create one or two sets disjoint from a given set A , but here we show that in fact such constructions exist for arbitrarily large disjoint extensions, which is to say that for any set B we can construct a set x that is equinumerous to it and disjoint from A . (Contributed by Mario Carneiro, 7-Feb-2015)
| Ref | Expression | ||
|---|---|---|---|
| Assertion | disjen | ⊢ ( ( 𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ) → ( ( 𝐴 ∩ ( 𝐵 × { 𝒫 ∪ ran 𝐴 } ) ) = ∅ ∧ ( 𝐵 × { 𝒫 ∪ ran 𝐴 } ) ≈ 𝐵 ) ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | 1st2nd2 | ⊢ ( 𝑥 ∈ ( 𝐵 × { 𝒫 ∪ ran 𝐴 } ) → 𝑥 = 〈 ( 1st ‘ 𝑥 ) , ( 2nd ‘ 𝑥 ) 〉 ) | |
| 2 | 1 | ad2antll | ⊢ ( ( ( 𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ) ∧ ( 𝑥 ∈ 𝐴 ∧ 𝑥 ∈ ( 𝐵 × { 𝒫 ∪ ran 𝐴 } ) ) ) → 𝑥 = 〈 ( 1st ‘ 𝑥 ) , ( 2nd ‘ 𝑥 ) 〉 ) |
| 3 | simprl | ⊢ ( ( ( 𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ) ∧ ( 𝑥 ∈ 𝐴 ∧ 𝑥 ∈ ( 𝐵 × { 𝒫 ∪ ran 𝐴 } ) ) ) → 𝑥 ∈ 𝐴 ) | |
| 4 | 2 3 | eqeltrrd | ⊢ ( ( ( 𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ) ∧ ( 𝑥 ∈ 𝐴 ∧ 𝑥 ∈ ( 𝐵 × { 𝒫 ∪ ran 𝐴 } ) ) ) → 〈 ( 1st ‘ 𝑥 ) , ( 2nd ‘ 𝑥 ) 〉 ∈ 𝐴 ) |
| 5 | fvex | ⊢ ( 1st ‘ 𝑥 ) ∈ V | |
| 6 | fvex | ⊢ ( 2nd ‘ 𝑥 ) ∈ V | |
| 7 | 5 6 | opelrn | ⊢ ( 〈 ( 1st ‘ 𝑥 ) , ( 2nd ‘ 𝑥 ) 〉 ∈ 𝐴 → ( 2nd ‘ 𝑥 ) ∈ ran 𝐴 ) |
| 8 | 4 7 | syl | ⊢ ( ( ( 𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ) ∧ ( 𝑥 ∈ 𝐴 ∧ 𝑥 ∈ ( 𝐵 × { 𝒫 ∪ ran 𝐴 } ) ) ) → ( 2nd ‘ 𝑥 ) ∈ ran 𝐴 ) |
| 9 | pwuninel | ⊢ ¬ 𝒫 ∪ ran 𝐴 ∈ ran 𝐴 | |
| 10 | xp2nd | ⊢ ( 𝑥 ∈ ( 𝐵 × { 𝒫 ∪ ran 𝐴 } ) → ( 2nd ‘ 𝑥 ) ∈ { 𝒫 ∪ ran 𝐴 } ) | |
| 11 | 10 | ad2antll | ⊢ ( ( ( 𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ) ∧ ( 𝑥 ∈ 𝐴 ∧ 𝑥 ∈ ( 𝐵 × { 𝒫 ∪ ran 𝐴 } ) ) ) → ( 2nd ‘ 𝑥 ) ∈ { 𝒫 ∪ ran 𝐴 } ) |
| 12 | elsni | ⊢ ( ( 2nd ‘ 𝑥 ) ∈ { 𝒫 ∪ ran 𝐴 } → ( 2nd ‘ 𝑥 ) = 𝒫 ∪ ran 𝐴 ) | |
| 13 | 11 12 | syl | ⊢ ( ( ( 𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ) ∧ ( 𝑥 ∈ 𝐴 ∧ 𝑥 ∈ ( 𝐵 × { 𝒫 ∪ ran 𝐴 } ) ) ) → ( 2nd ‘ 𝑥 ) = 𝒫 ∪ ran 𝐴 ) |
| 14 | 13 | eleq1d | ⊢ ( ( ( 𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ) ∧ ( 𝑥 ∈ 𝐴 ∧ 𝑥 ∈ ( 𝐵 × { 𝒫 ∪ ran 𝐴 } ) ) ) → ( ( 2nd ‘ 𝑥 ) ∈ ran 𝐴 ↔ 𝒫 ∪ ran 𝐴 ∈ ran 𝐴 ) ) |
| 15 | 9 14 | mtbiri | ⊢ ( ( ( 𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ) ∧ ( 𝑥 ∈ 𝐴 ∧ 𝑥 ∈ ( 𝐵 × { 𝒫 ∪ ran 𝐴 } ) ) ) → ¬ ( 2nd ‘ 𝑥 ) ∈ ran 𝐴 ) |
| 16 | 8 15 | pm2.65da | ⊢ ( ( 𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ) → ¬ ( 𝑥 ∈ 𝐴 ∧ 𝑥 ∈ ( 𝐵 × { 𝒫 ∪ ran 𝐴 } ) ) ) |
| 17 | elin | ⊢ ( 𝑥 ∈ ( 𝐴 ∩ ( 𝐵 × { 𝒫 ∪ ran 𝐴 } ) ) ↔ ( 𝑥 ∈ 𝐴 ∧ 𝑥 ∈ ( 𝐵 × { 𝒫 ∪ ran 𝐴 } ) ) ) | |
| 18 | 16 17 | sylnibr | ⊢ ( ( 𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ) → ¬ 𝑥 ∈ ( 𝐴 ∩ ( 𝐵 × { 𝒫 ∪ ran 𝐴 } ) ) ) |
| 19 | 18 | eq0rdv | ⊢ ( ( 𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ) → ( 𝐴 ∩ ( 𝐵 × { 𝒫 ∪ ran 𝐴 } ) ) = ∅ ) |
| 20 | simpr | ⊢ ( ( 𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ) → 𝐵 ∈ 𝑊 ) | |
| 21 | rnexg | ⊢ ( 𝐴 ∈ 𝑉 → ran 𝐴 ∈ V ) | |
| 22 | 21 | adantr | ⊢ ( ( 𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ) → ran 𝐴 ∈ V ) |
| 23 | uniexg | ⊢ ( ran 𝐴 ∈ V → ∪ ran 𝐴 ∈ V ) | |
| 24 | pwexg | ⊢ ( ∪ ran 𝐴 ∈ V → 𝒫 ∪ ran 𝐴 ∈ V ) | |
| 25 | 22 23 24 | 3syl | ⊢ ( ( 𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ) → 𝒫 ∪ ran 𝐴 ∈ V ) |
| 26 | xpsneng | ⊢ ( ( 𝐵 ∈ 𝑊 ∧ 𝒫 ∪ ran 𝐴 ∈ V ) → ( 𝐵 × { 𝒫 ∪ ran 𝐴 } ) ≈ 𝐵 ) | |
| 27 | 20 25 26 | syl2anc | ⊢ ( ( 𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ) → ( 𝐵 × { 𝒫 ∪ ran 𝐴 } ) ≈ 𝐵 ) |
| 28 | 19 27 | jca | ⊢ ( ( 𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ) → ( ( 𝐴 ∩ ( 𝐵 × { 𝒫 ∪ ran 𝐴 } ) ) = ∅ ∧ ( 𝐵 × { 𝒫 ∪ ran 𝐴 } ) ≈ 𝐵 ) ) |