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Description: Lemma for pythagtrip . Calculate ( sqrt( C + B ) ) . (Contributed by Scott Fenton, 18-Apr-2014) (Revised by Mario Carneiro, 19-Apr-2014)
| Ref | Expression | ||
|---|---|---|---|
| Assertion | pythagtriplem7 | ⊢ ( ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) ∧ ( ( 𝐴 ↑ 2 ) + ( 𝐵 ↑ 2 ) ) = ( 𝐶 ↑ 2 ) ∧ ( ( 𝐴 gcd 𝐵 ) = 1 ∧ ¬ 2 ∥ 𝐴 ) ) → ( √ ‘ ( 𝐶 + 𝐵 ) ) = ( ( 𝐶 + 𝐵 ) gcd 𝐴 ) ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | simp3 | ⊢ ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) → 𝐶 ∈ ℕ ) | |
| 2 | 1 | nnzd | ⊢ ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) → 𝐶 ∈ ℤ ) |
| 3 | simp2 | ⊢ ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) → 𝐵 ∈ ℕ ) | |
| 4 | 3 | nnzd | ⊢ ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) → 𝐵 ∈ ℤ ) |
| 5 | 2 4 | zsubcld | ⊢ ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) → ( 𝐶 − 𝐵 ) ∈ ℤ ) |
| 6 | 5 | 3ad2ant1 | ⊢ ( ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) ∧ ( ( 𝐴 ↑ 2 ) + ( 𝐵 ↑ 2 ) ) = ( 𝐶 ↑ 2 ) ∧ ( ( 𝐴 gcd 𝐵 ) = 1 ∧ ¬ 2 ∥ 𝐴 ) ) → ( 𝐶 − 𝐵 ) ∈ ℤ ) |
| 7 | 1 3 | nnaddcld | ⊢ ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) → ( 𝐶 + 𝐵 ) ∈ ℕ ) |
| 8 | 7 | nnnn0d | ⊢ ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) → ( 𝐶 + 𝐵 ) ∈ ℕ0 ) |
| 9 | 8 | 3ad2ant1 | ⊢ ( ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) ∧ ( ( 𝐴 ↑ 2 ) + ( 𝐵 ↑ 2 ) ) = ( 𝐶 ↑ 2 ) ∧ ( ( 𝐴 gcd 𝐵 ) = 1 ∧ ¬ 2 ∥ 𝐴 ) ) → ( 𝐶 + 𝐵 ) ∈ ℕ0 ) |
| 10 | nnnn0 | ⊢ ( 𝐴 ∈ ℕ → 𝐴 ∈ ℕ0 ) | |
| 11 | 10 | 3ad2ant1 | ⊢ ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) → 𝐴 ∈ ℕ0 ) |
| 12 | 11 | 3ad2ant1 | ⊢ ( ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) ∧ ( ( 𝐴 ↑ 2 ) + ( 𝐵 ↑ 2 ) ) = ( 𝐶 ↑ 2 ) ∧ ( ( 𝐴 gcd 𝐵 ) = 1 ∧ ¬ 2 ∥ 𝐴 ) ) → 𝐴 ∈ ℕ0 ) |
| 13 | 6 9 12 | 3jca | ⊢ ( ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) ∧ ( ( 𝐴 ↑ 2 ) + ( 𝐵 ↑ 2 ) ) = ( 𝐶 ↑ 2 ) ∧ ( ( 𝐴 gcd 𝐵 ) = 1 ∧ ¬ 2 ∥ 𝐴 ) ) → ( ( 𝐶 − 𝐵 ) ∈ ℤ ∧ ( 𝐶 + 𝐵 ) ∈ ℕ0 ∧ 𝐴 ∈ ℕ0 ) ) |
| 14 | pythagtriplem4 | ⊢ ( ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) ∧ ( ( 𝐴 ↑ 2 ) + ( 𝐵 ↑ 2 ) ) = ( 𝐶 ↑ 2 ) ∧ ( ( 𝐴 gcd 𝐵 ) = 1 ∧ ¬ 2 ∥ 𝐴 ) ) → ( ( 𝐶 − 𝐵 ) gcd ( 𝐶 + 𝐵 ) ) = 1 ) | |
| 15 | 14 | oveq1d | ⊢ ( ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) ∧ ( ( 𝐴 ↑ 2 ) + ( 𝐵 ↑ 2 ) ) = ( 𝐶 ↑ 2 ) ∧ ( ( 𝐴 gcd 𝐵 ) = 1 ∧ ¬ 2 ∥ 𝐴 ) ) → ( ( ( 𝐶 − 𝐵 ) gcd ( 𝐶 + 𝐵 ) ) gcd 𝐴 ) = ( 1 gcd 𝐴 ) ) |
| 16 | nnz | ⊢ ( 𝐴 ∈ ℕ → 𝐴 ∈ ℤ ) | |
| 17 | 16 | 3ad2ant1 | ⊢ ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) → 𝐴 ∈ ℤ ) |
| 18 | 17 | 3ad2ant1 | ⊢ ( ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) ∧ ( ( 𝐴 ↑ 2 ) + ( 𝐵 ↑ 2 ) ) = ( 𝐶 ↑ 2 ) ∧ ( ( 𝐴 gcd 𝐵 ) = 1 ∧ ¬ 2 ∥ 𝐴 ) ) → 𝐴 ∈ ℤ ) |
| 19 | 1gcd | ⊢ ( 𝐴 ∈ ℤ → ( 1 gcd 𝐴 ) = 1 ) | |
| 20 | 18 19 | syl | ⊢ ( ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) ∧ ( ( 𝐴 ↑ 2 ) + ( 𝐵 ↑ 2 ) ) = ( 𝐶 ↑ 2 ) ∧ ( ( 𝐴 gcd 𝐵 ) = 1 ∧ ¬ 2 ∥ 𝐴 ) ) → ( 1 gcd 𝐴 ) = 1 ) |
| 21 | 15 20 | eqtrd | ⊢ ( ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) ∧ ( ( 𝐴 ↑ 2 ) + ( 𝐵 ↑ 2 ) ) = ( 𝐶 ↑ 2 ) ∧ ( ( 𝐴 gcd 𝐵 ) = 1 ∧ ¬ 2 ∥ 𝐴 ) ) → ( ( ( 𝐶 − 𝐵 ) gcd ( 𝐶 + 𝐵 ) ) gcd 𝐴 ) = 1 ) |
| 22 | 13 21 | jca | ⊢ ( ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) ∧ ( ( 𝐴 ↑ 2 ) + ( 𝐵 ↑ 2 ) ) = ( 𝐶 ↑ 2 ) ∧ ( ( 𝐴 gcd 𝐵 ) = 1 ∧ ¬ 2 ∥ 𝐴 ) ) → ( ( ( 𝐶 − 𝐵 ) ∈ ℤ ∧ ( 𝐶 + 𝐵 ) ∈ ℕ0 ∧ 𝐴 ∈ ℕ0 ) ∧ ( ( ( 𝐶 − 𝐵 ) gcd ( 𝐶 + 𝐵 ) ) gcd 𝐴 ) = 1 ) ) |
| 23 | oveq1 | ⊢ ( ( ( 𝐴 ↑ 2 ) + ( 𝐵 ↑ 2 ) ) = ( 𝐶 ↑ 2 ) → ( ( ( 𝐴 ↑ 2 ) + ( 𝐵 ↑ 2 ) ) − ( 𝐵 ↑ 2 ) ) = ( ( 𝐶 ↑ 2 ) − ( 𝐵 ↑ 2 ) ) ) | |
| 24 | 23 | 3ad2ant2 | ⊢ ( ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) ∧ ( ( 𝐴 ↑ 2 ) + ( 𝐵 ↑ 2 ) ) = ( 𝐶 ↑ 2 ) ∧ ( ( 𝐴 gcd 𝐵 ) = 1 ∧ ¬ 2 ∥ 𝐴 ) ) → ( ( ( 𝐴 ↑ 2 ) + ( 𝐵 ↑ 2 ) ) − ( 𝐵 ↑ 2 ) ) = ( ( 𝐶 ↑ 2 ) − ( 𝐵 ↑ 2 ) ) ) |
| 25 | nncn | ⊢ ( 𝐴 ∈ ℕ → 𝐴 ∈ ℂ ) | |
| 26 | 25 | 3ad2ant1 | ⊢ ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) → 𝐴 ∈ ℂ ) |
| 27 | 26 | sqcld | ⊢ ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) → ( 𝐴 ↑ 2 ) ∈ ℂ ) |
| 28 | 3 | nncnd | ⊢ ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) → 𝐵 ∈ ℂ ) |
| 29 | 28 | sqcld | ⊢ ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) → ( 𝐵 ↑ 2 ) ∈ ℂ ) |
| 30 | 27 29 | pncand | ⊢ ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) → ( ( ( 𝐴 ↑ 2 ) + ( 𝐵 ↑ 2 ) ) − ( 𝐵 ↑ 2 ) ) = ( 𝐴 ↑ 2 ) ) |
| 31 | 30 | 3ad2ant1 | ⊢ ( ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) ∧ ( ( 𝐴 ↑ 2 ) + ( 𝐵 ↑ 2 ) ) = ( 𝐶 ↑ 2 ) ∧ ( ( 𝐴 gcd 𝐵 ) = 1 ∧ ¬ 2 ∥ 𝐴 ) ) → ( ( ( 𝐴 ↑ 2 ) + ( 𝐵 ↑ 2 ) ) − ( 𝐵 ↑ 2 ) ) = ( 𝐴 ↑ 2 ) ) |
| 32 | 1 | nncnd | ⊢ ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) → 𝐶 ∈ ℂ ) |
| 33 | subsq | ⊢ ( ( 𝐶 ∈ ℂ ∧ 𝐵 ∈ ℂ ) → ( ( 𝐶 ↑ 2 ) − ( 𝐵 ↑ 2 ) ) = ( ( 𝐶 + 𝐵 ) · ( 𝐶 − 𝐵 ) ) ) | |
| 34 | 32 28 33 | syl2anc | ⊢ ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) → ( ( 𝐶 ↑ 2 ) − ( 𝐵 ↑ 2 ) ) = ( ( 𝐶 + 𝐵 ) · ( 𝐶 − 𝐵 ) ) ) |
| 35 | 7 | nncnd | ⊢ ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) → ( 𝐶 + 𝐵 ) ∈ ℂ ) |
| 36 | 5 | zcnd | ⊢ ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) → ( 𝐶 − 𝐵 ) ∈ ℂ ) |
| 37 | 35 36 | mulcomd | ⊢ ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) → ( ( 𝐶 + 𝐵 ) · ( 𝐶 − 𝐵 ) ) = ( ( 𝐶 − 𝐵 ) · ( 𝐶 + 𝐵 ) ) ) |
| 38 | 34 37 | eqtrd | ⊢ ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) → ( ( 𝐶 ↑ 2 ) − ( 𝐵 ↑ 2 ) ) = ( ( 𝐶 − 𝐵 ) · ( 𝐶 + 𝐵 ) ) ) |
| 39 | 38 | 3ad2ant1 | ⊢ ( ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) ∧ ( ( 𝐴 ↑ 2 ) + ( 𝐵 ↑ 2 ) ) = ( 𝐶 ↑ 2 ) ∧ ( ( 𝐴 gcd 𝐵 ) = 1 ∧ ¬ 2 ∥ 𝐴 ) ) → ( ( 𝐶 ↑ 2 ) − ( 𝐵 ↑ 2 ) ) = ( ( 𝐶 − 𝐵 ) · ( 𝐶 + 𝐵 ) ) ) |
| 40 | 24 31 39 | 3eqtr3d | ⊢ ( ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) ∧ ( ( 𝐴 ↑ 2 ) + ( 𝐵 ↑ 2 ) ) = ( 𝐶 ↑ 2 ) ∧ ( ( 𝐴 gcd 𝐵 ) = 1 ∧ ¬ 2 ∥ 𝐴 ) ) → ( 𝐴 ↑ 2 ) = ( ( 𝐶 − 𝐵 ) · ( 𝐶 + 𝐵 ) ) ) |
| 41 | coprimeprodsq2 | ⊢ ( ( ( ( 𝐶 − 𝐵 ) ∈ ℤ ∧ ( 𝐶 + 𝐵 ) ∈ ℕ0 ∧ 𝐴 ∈ ℕ0 ) ∧ ( ( ( 𝐶 − 𝐵 ) gcd ( 𝐶 + 𝐵 ) ) gcd 𝐴 ) = 1 ) → ( ( 𝐴 ↑ 2 ) = ( ( 𝐶 − 𝐵 ) · ( 𝐶 + 𝐵 ) ) → ( 𝐶 + 𝐵 ) = ( ( ( 𝐶 + 𝐵 ) gcd 𝐴 ) ↑ 2 ) ) ) | |
| 42 | 22 40 41 | sylc | ⊢ ( ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) ∧ ( ( 𝐴 ↑ 2 ) + ( 𝐵 ↑ 2 ) ) = ( 𝐶 ↑ 2 ) ∧ ( ( 𝐴 gcd 𝐵 ) = 1 ∧ ¬ 2 ∥ 𝐴 ) ) → ( 𝐶 + 𝐵 ) = ( ( ( 𝐶 + 𝐵 ) gcd 𝐴 ) ↑ 2 ) ) |
| 43 | 42 | fveq2d | ⊢ ( ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) ∧ ( ( 𝐴 ↑ 2 ) + ( 𝐵 ↑ 2 ) ) = ( 𝐶 ↑ 2 ) ∧ ( ( 𝐴 gcd 𝐵 ) = 1 ∧ ¬ 2 ∥ 𝐴 ) ) → ( √ ‘ ( 𝐶 + 𝐵 ) ) = ( √ ‘ ( ( ( 𝐶 + 𝐵 ) gcd 𝐴 ) ↑ 2 ) ) ) |
| 44 | 7 | nnzd | ⊢ ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) → ( 𝐶 + 𝐵 ) ∈ ℤ ) |
| 45 | 44 | 3ad2ant1 | ⊢ ( ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) ∧ ( ( 𝐴 ↑ 2 ) + ( 𝐵 ↑ 2 ) ) = ( 𝐶 ↑ 2 ) ∧ ( ( 𝐴 gcd 𝐵 ) = 1 ∧ ¬ 2 ∥ 𝐴 ) ) → ( 𝐶 + 𝐵 ) ∈ ℤ ) |
| 46 | 45 18 | gcdcld | ⊢ ( ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) ∧ ( ( 𝐴 ↑ 2 ) + ( 𝐵 ↑ 2 ) ) = ( 𝐶 ↑ 2 ) ∧ ( ( 𝐴 gcd 𝐵 ) = 1 ∧ ¬ 2 ∥ 𝐴 ) ) → ( ( 𝐶 + 𝐵 ) gcd 𝐴 ) ∈ ℕ0 ) |
| 47 | 46 | nn0red | ⊢ ( ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) ∧ ( ( 𝐴 ↑ 2 ) + ( 𝐵 ↑ 2 ) ) = ( 𝐶 ↑ 2 ) ∧ ( ( 𝐴 gcd 𝐵 ) = 1 ∧ ¬ 2 ∥ 𝐴 ) ) → ( ( 𝐶 + 𝐵 ) gcd 𝐴 ) ∈ ℝ ) |
| 48 | 46 | nn0ge0d | ⊢ ( ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) ∧ ( ( 𝐴 ↑ 2 ) + ( 𝐵 ↑ 2 ) ) = ( 𝐶 ↑ 2 ) ∧ ( ( 𝐴 gcd 𝐵 ) = 1 ∧ ¬ 2 ∥ 𝐴 ) ) → 0 ≤ ( ( 𝐶 + 𝐵 ) gcd 𝐴 ) ) |
| 49 | 47 48 | sqrtsqd | ⊢ ( ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) ∧ ( ( 𝐴 ↑ 2 ) + ( 𝐵 ↑ 2 ) ) = ( 𝐶 ↑ 2 ) ∧ ( ( 𝐴 gcd 𝐵 ) = 1 ∧ ¬ 2 ∥ 𝐴 ) ) → ( √ ‘ ( ( ( 𝐶 + 𝐵 ) gcd 𝐴 ) ↑ 2 ) ) = ( ( 𝐶 + 𝐵 ) gcd 𝐴 ) ) |
| 50 | 43 49 | eqtrd | ⊢ ( ( ( 𝐴 ∈ ℕ ∧ 𝐵 ∈ ℕ ∧ 𝐶 ∈ ℕ ) ∧ ( ( 𝐴 ↑ 2 ) + ( 𝐵 ↑ 2 ) ) = ( 𝐶 ↑ 2 ) ∧ ( ( 𝐴 gcd 𝐵 ) = 1 ∧ ¬ 2 ∥ 𝐴 ) ) → ( √ ‘ ( 𝐶 + 𝐵 ) ) = ( ( 𝐶 + 𝐵 ) gcd 𝐴 ) ) |