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Description: Function value in an image. (Contributed by NM, 20-Jan-2007) (Proof shortened by Andrew Salmon, 22-Oct-2011) (Revised by David Abernethy, 17-Dec-2011)
| Ref | Expression | ||
|---|---|---|---|
| Assertion | fvelimab | ⊢ ( ( 𝐹 Fn 𝐴 ∧ 𝐵 ⊆ 𝐴 ) → ( 𝐶 ∈ ( 𝐹 “ 𝐵 ) ↔ ∃ 𝑥 ∈ 𝐵 ( 𝐹 ‘ 𝑥 ) = 𝐶 ) ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | elex | ⊢ ( 𝐶 ∈ ( 𝐹 “ 𝐵 ) → 𝐶 ∈ V ) | |
| 2 | 1 | anim2i | ⊢ ( ( ( 𝐹 Fn 𝐴 ∧ 𝐵 ⊆ 𝐴 ) ∧ 𝐶 ∈ ( 𝐹 “ 𝐵 ) ) → ( ( 𝐹 Fn 𝐴 ∧ 𝐵 ⊆ 𝐴 ) ∧ 𝐶 ∈ V ) ) |
| 3 | fvex | ⊢ ( 𝐹 ‘ 𝑥 ) ∈ V | |
| 4 | eleq1 | ⊢ ( ( 𝐹 ‘ 𝑥 ) = 𝐶 → ( ( 𝐹 ‘ 𝑥 ) ∈ V ↔ 𝐶 ∈ V ) ) | |
| 5 | 3 4 | mpbii | ⊢ ( ( 𝐹 ‘ 𝑥 ) = 𝐶 → 𝐶 ∈ V ) |
| 6 | 5 | rexlimivw | ⊢ ( ∃ 𝑥 ∈ 𝐵 ( 𝐹 ‘ 𝑥 ) = 𝐶 → 𝐶 ∈ V ) |
| 7 | 6 | anim2i | ⊢ ( ( ( 𝐹 Fn 𝐴 ∧ 𝐵 ⊆ 𝐴 ) ∧ ∃ 𝑥 ∈ 𝐵 ( 𝐹 ‘ 𝑥 ) = 𝐶 ) → ( ( 𝐹 Fn 𝐴 ∧ 𝐵 ⊆ 𝐴 ) ∧ 𝐶 ∈ V ) ) |
| 8 | eleq1 | ⊢ ( 𝑦 = 𝐶 → ( 𝑦 ∈ ( 𝐹 “ 𝐵 ) ↔ 𝐶 ∈ ( 𝐹 “ 𝐵 ) ) ) | |
| 9 | eqeq2 | ⊢ ( 𝑦 = 𝐶 → ( ( 𝐹 ‘ 𝑥 ) = 𝑦 ↔ ( 𝐹 ‘ 𝑥 ) = 𝐶 ) ) | |
| 10 | 9 | rexbidv | ⊢ ( 𝑦 = 𝐶 → ( ∃ 𝑥 ∈ 𝐵 ( 𝐹 ‘ 𝑥 ) = 𝑦 ↔ ∃ 𝑥 ∈ 𝐵 ( 𝐹 ‘ 𝑥 ) = 𝐶 ) ) |
| 11 | 8 10 | bibi12d | ⊢ ( 𝑦 = 𝐶 → ( ( 𝑦 ∈ ( 𝐹 “ 𝐵 ) ↔ ∃ 𝑥 ∈ 𝐵 ( 𝐹 ‘ 𝑥 ) = 𝑦 ) ↔ ( 𝐶 ∈ ( 𝐹 “ 𝐵 ) ↔ ∃ 𝑥 ∈ 𝐵 ( 𝐹 ‘ 𝑥 ) = 𝐶 ) ) ) |
| 12 | 11 | imbi2d | ⊢ ( 𝑦 = 𝐶 → ( ( ( 𝐹 Fn 𝐴 ∧ 𝐵 ⊆ 𝐴 ) → ( 𝑦 ∈ ( 𝐹 “ 𝐵 ) ↔ ∃ 𝑥 ∈ 𝐵 ( 𝐹 ‘ 𝑥 ) = 𝑦 ) ) ↔ ( ( 𝐹 Fn 𝐴 ∧ 𝐵 ⊆ 𝐴 ) → ( 𝐶 ∈ ( 𝐹 “ 𝐵 ) ↔ ∃ 𝑥 ∈ 𝐵 ( 𝐹 ‘ 𝑥 ) = 𝐶 ) ) ) ) |
| 13 | fnfun | ⊢ ( 𝐹 Fn 𝐴 → Fun 𝐹 ) | |
| 14 | fndm | ⊢ ( 𝐹 Fn 𝐴 → dom 𝐹 = 𝐴 ) | |
| 15 | 14 | sseq2d | ⊢ ( 𝐹 Fn 𝐴 → ( 𝐵 ⊆ dom 𝐹 ↔ 𝐵 ⊆ 𝐴 ) ) |
| 16 | 15 | biimpar | ⊢ ( ( 𝐹 Fn 𝐴 ∧ 𝐵 ⊆ 𝐴 ) → 𝐵 ⊆ dom 𝐹 ) |
| 17 | dfimafn | ⊢ ( ( Fun 𝐹 ∧ 𝐵 ⊆ dom 𝐹 ) → ( 𝐹 “ 𝐵 ) = { 𝑦 ∣ ∃ 𝑥 ∈ 𝐵 ( 𝐹 ‘ 𝑥 ) = 𝑦 } ) | |
| 18 | 13 16 17 | syl2an2r | ⊢ ( ( 𝐹 Fn 𝐴 ∧ 𝐵 ⊆ 𝐴 ) → ( 𝐹 “ 𝐵 ) = { 𝑦 ∣ ∃ 𝑥 ∈ 𝐵 ( 𝐹 ‘ 𝑥 ) = 𝑦 } ) |
| 19 | 18 | eqabrd | ⊢ ( ( 𝐹 Fn 𝐴 ∧ 𝐵 ⊆ 𝐴 ) → ( 𝑦 ∈ ( 𝐹 “ 𝐵 ) ↔ ∃ 𝑥 ∈ 𝐵 ( 𝐹 ‘ 𝑥 ) = 𝑦 ) ) |
| 20 | 12 19 | vtoclg | ⊢ ( 𝐶 ∈ V → ( ( 𝐹 Fn 𝐴 ∧ 𝐵 ⊆ 𝐴 ) → ( 𝐶 ∈ ( 𝐹 “ 𝐵 ) ↔ ∃ 𝑥 ∈ 𝐵 ( 𝐹 ‘ 𝑥 ) = 𝐶 ) ) ) |
| 21 | 20 | impcom | ⊢ ( ( ( 𝐹 Fn 𝐴 ∧ 𝐵 ⊆ 𝐴 ) ∧ 𝐶 ∈ V ) → ( 𝐶 ∈ ( 𝐹 “ 𝐵 ) ↔ ∃ 𝑥 ∈ 𝐵 ( 𝐹 ‘ 𝑥 ) = 𝐶 ) ) |
| 22 | 2 7 21 | pm5.21nd | ⊢ ( ( 𝐹 Fn 𝐴 ∧ 𝐵 ⊆ 𝐴 ) → ( 𝐶 ∈ ( 𝐹 “ 𝐵 ) ↔ ∃ 𝑥 ∈ 𝐵 ( 𝐹 ‘ 𝑥 ) = 𝐶 ) ) |