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Description: Subspace H of a Hilbert space. A subspace is a subset of Hilbert space which contains the zero vector and is closed under vector addition and scalar multiplication. (Contributed by Mario Carneiro, 23-Dec-2013) (New usage is discouraged.)
| Ref | Expression | ||
|---|---|---|---|
| Assertion | issh | ⊢ ( 𝐻 ∈ Sℋ ↔ ( ( 𝐻 ⊆ ℋ ∧ 0ℎ ∈ 𝐻 ) ∧ ( ( +ℎ “ ( 𝐻 × 𝐻 ) ) ⊆ 𝐻 ∧ ( ·ℎ “ ( ℂ × 𝐻 ) ) ⊆ 𝐻 ) ) ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | ax-hilex | ⊢ ℋ ∈ V | |
| 2 | 1 | elpw2 | ⊢ ( 𝐻 ∈ 𝒫 ℋ ↔ 𝐻 ⊆ ℋ ) |
| 3 | 3anass | ⊢ ( ( 0ℎ ∈ 𝐻 ∧ ( +ℎ “ ( 𝐻 × 𝐻 ) ) ⊆ 𝐻 ∧ ( ·ℎ “ ( ℂ × 𝐻 ) ) ⊆ 𝐻 ) ↔ ( 0ℎ ∈ 𝐻 ∧ ( ( +ℎ “ ( 𝐻 × 𝐻 ) ) ⊆ 𝐻 ∧ ( ·ℎ “ ( ℂ × 𝐻 ) ) ⊆ 𝐻 ) ) ) | |
| 4 | 2 3 | anbi12i | ⊢ ( ( 𝐻 ∈ 𝒫 ℋ ∧ ( 0ℎ ∈ 𝐻 ∧ ( +ℎ “ ( 𝐻 × 𝐻 ) ) ⊆ 𝐻 ∧ ( ·ℎ “ ( ℂ × 𝐻 ) ) ⊆ 𝐻 ) ) ↔ ( 𝐻 ⊆ ℋ ∧ ( 0ℎ ∈ 𝐻 ∧ ( ( +ℎ “ ( 𝐻 × 𝐻 ) ) ⊆ 𝐻 ∧ ( ·ℎ “ ( ℂ × 𝐻 ) ) ⊆ 𝐻 ) ) ) ) |
| 5 | eleq2 | ⊢ ( ℎ = 𝐻 → ( 0ℎ ∈ ℎ ↔ 0ℎ ∈ 𝐻 ) ) | |
| 6 | id | ⊢ ( ℎ = 𝐻 → ℎ = 𝐻 ) | |
| 7 | 6 | sqxpeqd | ⊢ ( ℎ = 𝐻 → ( ℎ × ℎ ) = ( 𝐻 × 𝐻 ) ) |
| 8 | 7 | imaeq2d | ⊢ ( ℎ = 𝐻 → ( +ℎ “ ( ℎ × ℎ ) ) = ( +ℎ “ ( 𝐻 × 𝐻 ) ) ) |
| 9 | 8 6 | sseq12d | ⊢ ( ℎ = 𝐻 → ( ( +ℎ “ ( ℎ × ℎ ) ) ⊆ ℎ ↔ ( +ℎ “ ( 𝐻 × 𝐻 ) ) ⊆ 𝐻 ) ) |
| 10 | xpeq2 | ⊢ ( ℎ = 𝐻 → ( ℂ × ℎ ) = ( ℂ × 𝐻 ) ) | |
| 11 | 10 | imaeq2d | ⊢ ( ℎ = 𝐻 → ( ·ℎ “ ( ℂ × ℎ ) ) = ( ·ℎ “ ( ℂ × 𝐻 ) ) ) |
| 12 | 11 6 | sseq12d | ⊢ ( ℎ = 𝐻 → ( ( ·ℎ “ ( ℂ × ℎ ) ) ⊆ ℎ ↔ ( ·ℎ “ ( ℂ × 𝐻 ) ) ⊆ 𝐻 ) ) |
| 13 | 5 9 12 | 3anbi123d | ⊢ ( ℎ = 𝐻 → ( ( 0ℎ ∈ ℎ ∧ ( +ℎ “ ( ℎ × ℎ ) ) ⊆ ℎ ∧ ( ·ℎ “ ( ℂ × ℎ ) ) ⊆ ℎ ) ↔ ( 0ℎ ∈ 𝐻 ∧ ( +ℎ “ ( 𝐻 × 𝐻 ) ) ⊆ 𝐻 ∧ ( ·ℎ “ ( ℂ × 𝐻 ) ) ⊆ 𝐻 ) ) ) |
| 14 | df-sh | ⊢ Sℋ = { ℎ ∈ 𝒫 ℋ ∣ ( 0ℎ ∈ ℎ ∧ ( +ℎ “ ( ℎ × ℎ ) ) ⊆ ℎ ∧ ( ·ℎ “ ( ℂ × ℎ ) ) ⊆ ℎ ) } | |
| 15 | 13 14 | elrab2 | ⊢ ( 𝐻 ∈ Sℋ ↔ ( 𝐻 ∈ 𝒫 ℋ ∧ ( 0ℎ ∈ 𝐻 ∧ ( +ℎ “ ( 𝐻 × 𝐻 ) ) ⊆ 𝐻 ∧ ( ·ℎ “ ( ℂ × 𝐻 ) ) ⊆ 𝐻 ) ) ) |
| 16 | anass | ⊢ ( ( ( 𝐻 ⊆ ℋ ∧ 0ℎ ∈ 𝐻 ) ∧ ( ( +ℎ “ ( 𝐻 × 𝐻 ) ) ⊆ 𝐻 ∧ ( ·ℎ “ ( ℂ × 𝐻 ) ) ⊆ 𝐻 ) ) ↔ ( 𝐻 ⊆ ℋ ∧ ( 0ℎ ∈ 𝐻 ∧ ( ( +ℎ “ ( 𝐻 × 𝐻 ) ) ⊆ 𝐻 ∧ ( ·ℎ “ ( ℂ × 𝐻 ) ) ⊆ 𝐻 ) ) ) ) | |
| 17 | 4 15 16 | 3bitr4i | ⊢ ( 𝐻 ∈ Sℋ ↔ ( ( 𝐻 ⊆ ℋ ∧ 0ℎ ∈ 𝐻 ) ∧ ( ( +ℎ “ ( 𝐻 × 𝐻 ) ) ⊆ 𝐻 ∧ ( ·ℎ “ ( ℂ × 𝐻 ) ) ⊆ 𝐻 ) ) ) |