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Description: Membership in a finite set of sequential integers. We use the fact that an operation's value is empty outside of its domain to show M e. ZZ and N e. ZZ . (Contributed by NM, 6-Sep-2005) (Revised by Mario Carneiro, 28-Apr-2015)
| Ref | Expression | ||
|---|---|---|---|
| Assertion | elfz2 | ⊢ ( 𝐾 ∈ ( 𝑀 ... 𝑁 ) ↔ ( ( 𝑀 ∈ ℤ ∧ 𝑁 ∈ ℤ ∧ 𝐾 ∈ ℤ ) ∧ ( 𝑀 ≤ 𝐾 ∧ 𝐾 ≤ 𝑁 ) ) ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | anass | ⊢ ( ( ( ( 𝑀 ∈ ℤ ∧ 𝑁 ∈ ℤ ) ∧ 𝐾 ∈ ℤ ) ∧ ( 𝑀 ≤ 𝐾 ∧ 𝐾 ≤ 𝑁 ) ) ↔ ( ( 𝑀 ∈ ℤ ∧ 𝑁 ∈ ℤ ) ∧ ( 𝐾 ∈ ℤ ∧ ( 𝑀 ≤ 𝐾 ∧ 𝐾 ≤ 𝑁 ) ) ) ) | |
| 2 | df-3an | ⊢ ( ( 𝑀 ∈ ℤ ∧ 𝑁 ∈ ℤ ∧ 𝐾 ∈ ℤ ) ↔ ( ( 𝑀 ∈ ℤ ∧ 𝑁 ∈ ℤ ) ∧ 𝐾 ∈ ℤ ) ) | |
| 3 | 2 | anbi1i | ⊢ ( ( ( 𝑀 ∈ ℤ ∧ 𝑁 ∈ ℤ ∧ 𝐾 ∈ ℤ ) ∧ ( 𝑀 ≤ 𝐾 ∧ 𝐾 ≤ 𝑁 ) ) ↔ ( ( ( 𝑀 ∈ ℤ ∧ 𝑁 ∈ ℤ ) ∧ 𝐾 ∈ ℤ ) ∧ ( 𝑀 ≤ 𝐾 ∧ 𝐾 ≤ 𝑁 ) ) ) |
| 4 | elfz1 | ⊢ ( ( 𝑀 ∈ ℤ ∧ 𝑁 ∈ ℤ ) → ( 𝐾 ∈ ( 𝑀 ... 𝑁 ) ↔ ( 𝐾 ∈ ℤ ∧ 𝑀 ≤ 𝐾 ∧ 𝐾 ≤ 𝑁 ) ) ) | |
| 5 | 3anass | ⊢ ( ( 𝐾 ∈ ℤ ∧ 𝑀 ≤ 𝐾 ∧ 𝐾 ≤ 𝑁 ) ↔ ( 𝐾 ∈ ℤ ∧ ( 𝑀 ≤ 𝐾 ∧ 𝐾 ≤ 𝑁 ) ) ) | |
| 6 | ibar | ⊢ ( ( 𝑀 ∈ ℤ ∧ 𝑁 ∈ ℤ ) → ( ( 𝐾 ∈ ℤ ∧ ( 𝑀 ≤ 𝐾 ∧ 𝐾 ≤ 𝑁 ) ) ↔ ( ( 𝑀 ∈ ℤ ∧ 𝑁 ∈ ℤ ) ∧ ( 𝐾 ∈ ℤ ∧ ( 𝑀 ≤ 𝐾 ∧ 𝐾 ≤ 𝑁 ) ) ) ) ) | |
| 7 | 5 6 | bitrid | ⊢ ( ( 𝑀 ∈ ℤ ∧ 𝑁 ∈ ℤ ) → ( ( 𝐾 ∈ ℤ ∧ 𝑀 ≤ 𝐾 ∧ 𝐾 ≤ 𝑁 ) ↔ ( ( 𝑀 ∈ ℤ ∧ 𝑁 ∈ ℤ ) ∧ ( 𝐾 ∈ ℤ ∧ ( 𝑀 ≤ 𝐾 ∧ 𝐾 ≤ 𝑁 ) ) ) ) ) |
| 8 | 4 7 | bitrd | ⊢ ( ( 𝑀 ∈ ℤ ∧ 𝑁 ∈ ℤ ) → ( 𝐾 ∈ ( 𝑀 ... 𝑁 ) ↔ ( ( 𝑀 ∈ ℤ ∧ 𝑁 ∈ ℤ ) ∧ ( 𝐾 ∈ ℤ ∧ ( 𝑀 ≤ 𝐾 ∧ 𝐾 ≤ 𝑁 ) ) ) ) ) |
| 9 | fzf | ⊢ ... : ( ℤ × ℤ ) ⟶ 𝒫 ℤ | |
| 10 | 9 | fdmi | ⊢ dom ... = ( ℤ × ℤ ) |
| 11 | 10 | ndmov | ⊢ ( ¬ ( 𝑀 ∈ ℤ ∧ 𝑁 ∈ ℤ ) → ( 𝑀 ... 𝑁 ) = ∅ ) |
| 12 | 11 | eleq2d | ⊢ ( ¬ ( 𝑀 ∈ ℤ ∧ 𝑁 ∈ ℤ ) → ( 𝐾 ∈ ( 𝑀 ... 𝑁 ) ↔ 𝐾 ∈ ∅ ) ) |
| 13 | noel | ⊢ ¬ 𝐾 ∈ ∅ | |
| 14 | 13 | pm2.21i | ⊢ ( 𝐾 ∈ ∅ → ( 𝑀 ∈ ℤ ∧ 𝑁 ∈ ℤ ) ) |
| 15 | simpl | ⊢ ( ( ( 𝑀 ∈ ℤ ∧ 𝑁 ∈ ℤ ) ∧ ( 𝐾 ∈ ℤ ∧ ( 𝑀 ≤ 𝐾 ∧ 𝐾 ≤ 𝑁 ) ) ) → ( 𝑀 ∈ ℤ ∧ 𝑁 ∈ ℤ ) ) | |
| 16 | 14 15 | pm5.21ni | ⊢ ( ¬ ( 𝑀 ∈ ℤ ∧ 𝑁 ∈ ℤ ) → ( 𝐾 ∈ ∅ ↔ ( ( 𝑀 ∈ ℤ ∧ 𝑁 ∈ ℤ ) ∧ ( 𝐾 ∈ ℤ ∧ ( 𝑀 ≤ 𝐾 ∧ 𝐾 ≤ 𝑁 ) ) ) ) ) |
| 17 | 12 16 | bitrd | ⊢ ( ¬ ( 𝑀 ∈ ℤ ∧ 𝑁 ∈ ℤ ) → ( 𝐾 ∈ ( 𝑀 ... 𝑁 ) ↔ ( ( 𝑀 ∈ ℤ ∧ 𝑁 ∈ ℤ ) ∧ ( 𝐾 ∈ ℤ ∧ ( 𝑀 ≤ 𝐾 ∧ 𝐾 ≤ 𝑁 ) ) ) ) ) |
| 18 | 8 17 | pm2.61i | ⊢ ( 𝐾 ∈ ( 𝑀 ... 𝑁 ) ↔ ( ( 𝑀 ∈ ℤ ∧ 𝑁 ∈ ℤ ) ∧ ( 𝐾 ∈ ℤ ∧ ( 𝑀 ≤ 𝐾 ∧ 𝐾 ≤ 𝑁 ) ) ) ) |
| 19 | 1 3 18 | 3bitr4ri | ⊢ ( 𝐾 ∈ ( 𝑀 ... 𝑁 ) ↔ ( ( 𝑀 ∈ ℤ ∧ 𝑁 ∈ ℤ ∧ 𝐾 ∈ ℤ ) ∧ ( 𝑀 ≤ 𝐾 ∧ 𝐾 ≤ 𝑁 ) ) ) |