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Description: Part of proof of Lemma E in Crawley p. 113, 2nd paragraph on p. 114. D represents s_2. In their notation, we prove s \/ s_2 = s \/ r. (Contributed by NM, 9-Jun-2012)
| Ref | Expression | ||
|---|---|---|---|
| Hypotheses | cdleme10.l | ⊢ ≤ = ( le ‘ 𝐾 ) | |
| cdleme10.j | ⊢ ∨ = ( join ‘ 𝐾 ) | ||
| cdleme10.m | ⊢ ∧ = ( meet ‘ 𝐾 ) | ||
| cdleme10.a | ⊢ 𝐴 = ( Atoms ‘ 𝐾 ) | ||
| cdleme10.h | ⊢ 𝐻 = ( LHyp ‘ 𝐾 ) | ||
| cdleme10.d | ⊢ 𝐷 = ( ( 𝑅 ∨ 𝑆 ) ∧ 𝑊 ) | ||
| Assertion | cdleme10 | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ 𝑅 ∈ 𝐴 ∧ ( 𝑆 ∈ 𝐴 ∧ ¬ 𝑆 ≤ 𝑊 ) ) → ( 𝑆 ∨ 𝐷 ) = ( 𝑆 ∨ 𝑅 ) ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | cdleme10.l | ⊢ ≤ = ( le ‘ 𝐾 ) | |
| 2 | cdleme10.j | ⊢ ∨ = ( join ‘ 𝐾 ) | |
| 3 | cdleme10.m | ⊢ ∧ = ( meet ‘ 𝐾 ) | |
| 4 | cdleme10.a | ⊢ 𝐴 = ( Atoms ‘ 𝐾 ) | |
| 5 | cdleme10.h | ⊢ 𝐻 = ( LHyp ‘ 𝐾 ) | |
| 6 | cdleme10.d | ⊢ 𝐷 = ( ( 𝑅 ∨ 𝑆 ) ∧ 𝑊 ) | |
| 7 | 6 | oveq2i | ⊢ ( 𝑆 ∨ 𝐷 ) = ( 𝑆 ∨ ( ( 𝑅 ∨ 𝑆 ) ∧ 𝑊 ) ) |
| 8 | simp1l | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ 𝑅 ∈ 𝐴 ∧ ( 𝑆 ∈ 𝐴 ∧ ¬ 𝑆 ≤ 𝑊 ) ) → 𝐾 ∈ HL ) | |
| 9 | simp3l | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ 𝑅 ∈ 𝐴 ∧ ( 𝑆 ∈ 𝐴 ∧ ¬ 𝑆 ≤ 𝑊 ) ) → 𝑆 ∈ 𝐴 ) | |
| 10 | simp2 | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ 𝑅 ∈ 𝐴 ∧ ( 𝑆 ∈ 𝐴 ∧ ¬ 𝑆 ≤ 𝑊 ) ) → 𝑅 ∈ 𝐴 ) | |
| 11 | eqid | ⊢ ( Base ‘ 𝐾 ) = ( Base ‘ 𝐾 ) | |
| 12 | 11 2 4 | hlatjcl | ⊢ ( ( 𝐾 ∈ HL ∧ 𝑅 ∈ 𝐴 ∧ 𝑆 ∈ 𝐴 ) → ( 𝑅 ∨ 𝑆 ) ∈ ( Base ‘ 𝐾 ) ) |
| 13 | 8 10 9 12 | syl3anc | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ 𝑅 ∈ 𝐴 ∧ ( 𝑆 ∈ 𝐴 ∧ ¬ 𝑆 ≤ 𝑊 ) ) → ( 𝑅 ∨ 𝑆 ) ∈ ( Base ‘ 𝐾 ) ) |
| 14 | simp1r | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ 𝑅 ∈ 𝐴 ∧ ( 𝑆 ∈ 𝐴 ∧ ¬ 𝑆 ≤ 𝑊 ) ) → 𝑊 ∈ 𝐻 ) | |
| 15 | 11 5 | lhpbase | ⊢ ( 𝑊 ∈ 𝐻 → 𝑊 ∈ ( Base ‘ 𝐾 ) ) |
| 16 | 14 15 | syl | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ 𝑅 ∈ 𝐴 ∧ ( 𝑆 ∈ 𝐴 ∧ ¬ 𝑆 ≤ 𝑊 ) ) → 𝑊 ∈ ( Base ‘ 𝐾 ) ) |
| 17 | 8 | hllatd | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ 𝑅 ∈ 𝐴 ∧ ( 𝑆 ∈ 𝐴 ∧ ¬ 𝑆 ≤ 𝑊 ) ) → 𝐾 ∈ Lat ) |
| 18 | 11 4 | atbase | ⊢ ( 𝑅 ∈ 𝐴 → 𝑅 ∈ ( Base ‘ 𝐾 ) ) |
| 19 | 18 | 3ad2ant2 | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ 𝑅 ∈ 𝐴 ∧ ( 𝑆 ∈ 𝐴 ∧ ¬ 𝑆 ≤ 𝑊 ) ) → 𝑅 ∈ ( Base ‘ 𝐾 ) ) |
| 20 | 11 4 | atbase | ⊢ ( 𝑆 ∈ 𝐴 → 𝑆 ∈ ( Base ‘ 𝐾 ) ) |
| 21 | 9 20 | syl | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ 𝑅 ∈ 𝐴 ∧ ( 𝑆 ∈ 𝐴 ∧ ¬ 𝑆 ≤ 𝑊 ) ) → 𝑆 ∈ ( Base ‘ 𝐾 ) ) |
| 22 | 11 1 2 | latlej2 | ⊢ ( ( 𝐾 ∈ Lat ∧ 𝑅 ∈ ( Base ‘ 𝐾 ) ∧ 𝑆 ∈ ( Base ‘ 𝐾 ) ) → 𝑆 ≤ ( 𝑅 ∨ 𝑆 ) ) |
| 23 | 17 19 21 22 | syl3anc | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ 𝑅 ∈ 𝐴 ∧ ( 𝑆 ∈ 𝐴 ∧ ¬ 𝑆 ≤ 𝑊 ) ) → 𝑆 ≤ ( 𝑅 ∨ 𝑆 ) ) |
| 24 | 11 1 2 3 4 | atmod3i1 | ⊢ ( ( 𝐾 ∈ HL ∧ ( 𝑆 ∈ 𝐴 ∧ ( 𝑅 ∨ 𝑆 ) ∈ ( Base ‘ 𝐾 ) ∧ 𝑊 ∈ ( Base ‘ 𝐾 ) ) ∧ 𝑆 ≤ ( 𝑅 ∨ 𝑆 ) ) → ( 𝑆 ∨ ( ( 𝑅 ∨ 𝑆 ) ∧ 𝑊 ) ) = ( ( 𝑅 ∨ 𝑆 ) ∧ ( 𝑆 ∨ 𝑊 ) ) ) |
| 25 | 8 9 13 16 23 24 | syl131anc | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ 𝑅 ∈ 𝐴 ∧ ( 𝑆 ∈ 𝐴 ∧ ¬ 𝑆 ≤ 𝑊 ) ) → ( 𝑆 ∨ ( ( 𝑅 ∨ 𝑆 ) ∧ 𝑊 ) ) = ( ( 𝑅 ∨ 𝑆 ) ∧ ( 𝑆 ∨ 𝑊 ) ) ) |
| 26 | 11 2 | latjcom | ⊢ ( ( 𝐾 ∈ Lat ∧ 𝑅 ∈ ( Base ‘ 𝐾 ) ∧ 𝑆 ∈ ( Base ‘ 𝐾 ) ) → ( 𝑅 ∨ 𝑆 ) = ( 𝑆 ∨ 𝑅 ) ) |
| 27 | 17 19 21 26 | syl3anc | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ 𝑅 ∈ 𝐴 ∧ ( 𝑆 ∈ 𝐴 ∧ ¬ 𝑆 ≤ 𝑊 ) ) → ( 𝑅 ∨ 𝑆 ) = ( 𝑆 ∨ 𝑅 ) ) |
| 28 | eqid | ⊢ ( 1. ‘ 𝐾 ) = ( 1. ‘ 𝐾 ) | |
| 29 | 1 2 28 4 5 | lhpjat2 | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ ( 𝑆 ∈ 𝐴 ∧ ¬ 𝑆 ≤ 𝑊 ) ) → ( 𝑆 ∨ 𝑊 ) = ( 1. ‘ 𝐾 ) ) |
| 30 | 29 | 3adant2 | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ 𝑅 ∈ 𝐴 ∧ ( 𝑆 ∈ 𝐴 ∧ ¬ 𝑆 ≤ 𝑊 ) ) → ( 𝑆 ∨ 𝑊 ) = ( 1. ‘ 𝐾 ) ) |
| 31 | 27 30 | oveq12d | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ 𝑅 ∈ 𝐴 ∧ ( 𝑆 ∈ 𝐴 ∧ ¬ 𝑆 ≤ 𝑊 ) ) → ( ( 𝑅 ∨ 𝑆 ) ∧ ( 𝑆 ∨ 𝑊 ) ) = ( ( 𝑆 ∨ 𝑅 ) ∧ ( 1. ‘ 𝐾 ) ) ) |
| 32 | hlol | ⊢ ( 𝐾 ∈ HL → 𝐾 ∈ OL ) | |
| 33 | 8 32 | syl | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ 𝑅 ∈ 𝐴 ∧ ( 𝑆 ∈ 𝐴 ∧ ¬ 𝑆 ≤ 𝑊 ) ) → 𝐾 ∈ OL ) |
| 34 | 11 2 | latjcl | ⊢ ( ( 𝐾 ∈ Lat ∧ 𝑆 ∈ ( Base ‘ 𝐾 ) ∧ 𝑅 ∈ ( Base ‘ 𝐾 ) ) → ( 𝑆 ∨ 𝑅 ) ∈ ( Base ‘ 𝐾 ) ) |
| 35 | 17 21 19 34 | syl3anc | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ 𝑅 ∈ 𝐴 ∧ ( 𝑆 ∈ 𝐴 ∧ ¬ 𝑆 ≤ 𝑊 ) ) → ( 𝑆 ∨ 𝑅 ) ∈ ( Base ‘ 𝐾 ) ) |
| 36 | 11 3 28 | olm11 | ⊢ ( ( 𝐾 ∈ OL ∧ ( 𝑆 ∨ 𝑅 ) ∈ ( Base ‘ 𝐾 ) ) → ( ( 𝑆 ∨ 𝑅 ) ∧ ( 1. ‘ 𝐾 ) ) = ( 𝑆 ∨ 𝑅 ) ) |
| 37 | 33 35 36 | syl2anc | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ 𝑅 ∈ 𝐴 ∧ ( 𝑆 ∈ 𝐴 ∧ ¬ 𝑆 ≤ 𝑊 ) ) → ( ( 𝑆 ∨ 𝑅 ) ∧ ( 1. ‘ 𝐾 ) ) = ( 𝑆 ∨ 𝑅 ) ) |
| 38 | 25 31 37 | 3eqtrd | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ 𝑅 ∈ 𝐴 ∧ ( 𝑆 ∈ 𝐴 ∧ ¬ 𝑆 ≤ 𝑊 ) ) → ( 𝑆 ∨ ( ( 𝑅 ∨ 𝑆 ) ∧ 𝑊 ) ) = ( 𝑆 ∨ 𝑅 ) ) |
| 39 | 7 38 | eqtrid | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ 𝑅 ∈ 𝐴 ∧ ( 𝑆 ∈ 𝐴 ∧ ¬ 𝑆 ≤ 𝑊 ) ) → ( 𝑆 ∨ 𝐷 ) = ( 𝑆 ∨ 𝑅 ) ) |