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Description: Equinumerosity law for set exponentiation of a Cartesian product. Exercise 4.47 of Mendelson p. 255. (Contributed by NM, 23-Feb-2004) (Proof shortened by Mario Carneiro, 16-Nov-2014)
| Ref | Expression | ||
|---|---|---|---|
| Hypotheses | xpmapen.1 | ⊢ 𝐴 ∈ V | |
| xpmapen.2 | ⊢ 𝐵 ∈ V | ||
| xpmapen.3 | ⊢ 𝐶 ∈ V | ||
| Assertion | xpmapen | ⊢ ( ( 𝐴 × 𝐵 ) ↑m 𝐶 ) ≈ ( ( 𝐴 ↑m 𝐶 ) × ( 𝐵 ↑m 𝐶 ) ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | xpmapen.1 | ⊢ 𝐴 ∈ V | |
| 2 | xpmapen.2 | ⊢ 𝐵 ∈ V | |
| 3 | xpmapen.3 | ⊢ 𝐶 ∈ V | |
| 4 | 2fveq3 | ⊢ ( 𝑤 = 𝑧 → ( 1st ‘ ( 𝑥 ‘ 𝑤 ) ) = ( 1st ‘ ( 𝑥 ‘ 𝑧 ) ) ) | |
| 5 | 4 | cbvmptv | ⊢ ( 𝑤 ∈ 𝐶 ↦ ( 1st ‘ ( 𝑥 ‘ 𝑤 ) ) ) = ( 𝑧 ∈ 𝐶 ↦ ( 1st ‘ ( 𝑥 ‘ 𝑧 ) ) ) |
| 6 | 2fveq3 | ⊢ ( 𝑤 = 𝑧 → ( 2nd ‘ ( 𝑥 ‘ 𝑤 ) ) = ( 2nd ‘ ( 𝑥 ‘ 𝑧 ) ) ) | |
| 7 | 6 | cbvmptv | ⊢ ( 𝑤 ∈ 𝐶 ↦ ( 2nd ‘ ( 𝑥 ‘ 𝑤 ) ) ) = ( 𝑧 ∈ 𝐶 ↦ ( 2nd ‘ ( 𝑥 ‘ 𝑧 ) ) ) |
| 8 | fveq2 | ⊢ ( 𝑤 = 𝑧 → ( ( 1st ‘ 𝑦 ) ‘ 𝑤 ) = ( ( 1st ‘ 𝑦 ) ‘ 𝑧 ) ) | |
| 9 | fveq2 | ⊢ ( 𝑤 = 𝑧 → ( ( 2nd ‘ 𝑦 ) ‘ 𝑤 ) = ( ( 2nd ‘ 𝑦 ) ‘ 𝑧 ) ) | |
| 10 | 8 9 | opeq12d | ⊢ ( 𝑤 = 𝑧 → 〈 ( ( 1st ‘ 𝑦 ) ‘ 𝑤 ) , ( ( 2nd ‘ 𝑦 ) ‘ 𝑤 ) 〉 = 〈 ( ( 1st ‘ 𝑦 ) ‘ 𝑧 ) , ( ( 2nd ‘ 𝑦 ) ‘ 𝑧 ) 〉 ) |
| 11 | 10 | cbvmptv | ⊢ ( 𝑤 ∈ 𝐶 ↦ 〈 ( ( 1st ‘ 𝑦 ) ‘ 𝑤 ) , ( ( 2nd ‘ 𝑦 ) ‘ 𝑤 ) 〉 ) = ( 𝑧 ∈ 𝐶 ↦ 〈 ( ( 1st ‘ 𝑦 ) ‘ 𝑧 ) , ( ( 2nd ‘ 𝑦 ) ‘ 𝑧 ) 〉 ) |
| 12 | 1 2 3 5 7 11 | xpmapenlem | ⊢ ( ( 𝐴 × 𝐵 ) ↑m 𝐶 ) ≈ ( ( 𝐴 ↑m 𝐶 ) × ( 𝐵 ↑m 𝐶 ) ) |