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Description: Alternate proof of sbc5 . This proof helps show how clelab works, since it is equivalent but shorter thanks to now-available library theorems like vtoclbg and isset . (Contributed by NM, 23-Aug-1993) (Revised by Mario Carneiro, 12-Oct-2016) (New usage is discouraged.) (Proof modification is discouraged.)
| Ref | Expression | ||
|---|---|---|---|
| Assertion | sbc5ALT | ⊢ ( [ 𝐴 / 𝑥 ] 𝜑 ↔ ∃ 𝑥 ( 𝑥 = 𝐴 ∧ 𝜑 ) ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | sbcex | ⊢ ( [ 𝐴 / 𝑥 ] 𝜑 → 𝐴 ∈ V ) | |
| 2 | exsimpl | ⊢ ( ∃ 𝑥 ( 𝑥 = 𝐴 ∧ 𝜑 ) → ∃ 𝑥 𝑥 = 𝐴 ) | |
| 3 | isset | ⊢ ( 𝐴 ∈ V ↔ ∃ 𝑥 𝑥 = 𝐴 ) | |
| 4 | 2 3 | sylibr | ⊢ ( ∃ 𝑥 ( 𝑥 = 𝐴 ∧ 𝜑 ) → 𝐴 ∈ V ) |
| 5 | dfsbcq2 | ⊢ ( 𝑦 = 𝐴 → ( [ 𝑦 / 𝑥 ] 𝜑 ↔ [ 𝐴 / 𝑥 ] 𝜑 ) ) | |
| 6 | eqeq2 | ⊢ ( 𝑦 = 𝐴 → ( 𝑥 = 𝑦 ↔ 𝑥 = 𝐴 ) ) | |
| 7 | 6 | anbi1d | ⊢ ( 𝑦 = 𝐴 → ( ( 𝑥 = 𝑦 ∧ 𝜑 ) ↔ ( 𝑥 = 𝐴 ∧ 𝜑 ) ) ) |
| 8 | 7 | exbidv | ⊢ ( 𝑦 = 𝐴 → ( ∃ 𝑥 ( 𝑥 = 𝑦 ∧ 𝜑 ) ↔ ∃ 𝑥 ( 𝑥 = 𝐴 ∧ 𝜑 ) ) ) |
| 9 | sb5 | ⊢ ( [ 𝑦 / 𝑥 ] 𝜑 ↔ ∃ 𝑥 ( 𝑥 = 𝑦 ∧ 𝜑 ) ) | |
| 10 | 5 8 9 | vtoclbg | ⊢ ( 𝐴 ∈ V → ( [ 𝐴 / 𝑥 ] 𝜑 ↔ ∃ 𝑥 ( 𝑥 = 𝐴 ∧ 𝜑 ) ) ) |
| 11 | 1 4 10 | pm5.21nii | ⊢ ( [ 𝐴 / 𝑥 ] 𝜑 ↔ ∃ 𝑥 ( 𝑥 = 𝐴 ∧ 𝜑 ) ) |