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Description: Lemma for pexmidN . (Contributed by NM, 2-Feb-2012) (New usage is discouraged.)
| Ref | Expression | ||
|---|---|---|---|
| Hypotheses | pexmidlem.l | ⊢ ≤ = ( le ‘ 𝐾 ) | |
| pexmidlem.j | ⊢ ∨ = ( join ‘ 𝐾 ) | ||
| pexmidlem.a | ⊢ 𝐴 = ( Atoms ‘ 𝐾 ) | ||
| pexmidlem.p | ⊢ + = ( +𝑃 ‘ 𝐾 ) | ||
| pexmidlem.o | ⊢ ⊥ = ( ⊥𝑃 ‘ 𝐾 ) | ||
| pexmidlem.m | ⊢ 𝑀 = ( 𝑋 + { 𝑝 } ) | ||
| Assertion | pexmidlem2N | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑋 ⊆ 𝐴 ∧ 𝑝 ∈ 𝐴 ) ∧ ( 𝑟 ∈ 𝑋 ∧ 𝑞 ∈ ( ⊥ ‘ 𝑋 ) ∧ 𝑝 ≤ ( 𝑟 ∨ 𝑞 ) ) ) → 𝑝 ∈ ( 𝑋 + ( ⊥ ‘ 𝑋 ) ) ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | pexmidlem.l | ⊢ ≤ = ( le ‘ 𝐾 ) | |
| 2 | pexmidlem.j | ⊢ ∨ = ( join ‘ 𝐾 ) | |
| 3 | pexmidlem.a | ⊢ 𝐴 = ( Atoms ‘ 𝐾 ) | |
| 4 | pexmidlem.p | ⊢ + = ( +𝑃 ‘ 𝐾 ) | |
| 5 | pexmidlem.o | ⊢ ⊥ = ( ⊥𝑃 ‘ 𝐾 ) | |
| 6 | pexmidlem.m | ⊢ 𝑀 = ( 𝑋 + { 𝑝 } ) | |
| 7 | simpl1 | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑋 ⊆ 𝐴 ∧ 𝑝 ∈ 𝐴 ) ∧ ( 𝑟 ∈ 𝑋 ∧ 𝑞 ∈ ( ⊥ ‘ 𝑋 ) ∧ 𝑝 ≤ ( 𝑟 ∨ 𝑞 ) ) ) → 𝐾 ∈ HL ) | |
| 8 | 7 | hllatd | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑋 ⊆ 𝐴 ∧ 𝑝 ∈ 𝐴 ) ∧ ( 𝑟 ∈ 𝑋 ∧ 𝑞 ∈ ( ⊥ ‘ 𝑋 ) ∧ 𝑝 ≤ ( 𝑟 ∨ 𝑞 ) ) ) → 𝐾 ∈ Lat ) |
| 9 | simpl2 | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑋 ⊆ 𝐴 ∧ 𝑝 ∈ 𝐴 ) ∧ ( 𝑟 ∈ 𝑋 ∧ 𝑞 ∈ ( ⊥ ‘ 𝑋 ) ∧ 𝑝 ≤ ( 𝑟 ∨ 𝑞 ) ) ) → 𝑋 ⊆ 𝐴 ) | |
| 10 | 3 5 | polssatN | ⊢ ( ( 𝐾 ∈ HL ∧ 𝑋 ⊆ 𝐴 ) → ( ⊥ ‘ 𝑋 ) ⊆ 𝐴 ) |
| 11 | 7 9 10 | syl2anc | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑋 ⊆ 𝐴 ∧ 𝑝 ∈ 𝐴 ) ∧ ( 𝑟 ∈ 𝑋 ∧ 𝑞 ∈ ( ⊥ ‘ 𝑋 ) ∧ 𝑝 ≤ ( 𝑟 ∨ 𝑞 ) ) ) → ( ⊥ ‘ 𝑋 ) ⊆ 𝐴 ) |
| 12 | simpr1 | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑋 ⊆ 𝐴 ∧ 𝑝 ∈ 𝐴 ) ∧ ( 𝑟 ∈ 𝑋 ∧ 𝑞 ∈ ( ⊥ ‘ 𝑋 ) ∧ 𝑝 ≤ ( 𝑟 ∨ 𝑞 ) ) ) → 𝑟 ∈ 𝑋 ) | |
| 13 | simpr2 | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑋 ⊆ 𝐴 ∧ 𝑝 ∈ 𝐴 ) ∧ ( 𝑟 ∈ 𝑋 ∧ 𝑞 ∈ ( ⊥ ‘ 𝑋 ) ∧ 𝑝 ≤ ( 𝑟 ∨ 𝑞 ) ) ) → 𝑞 ∈ ( ⊥ ‘ 𝑋 ) ) | |
| 14 | simpl3 | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑋 ⊆ 𝐴 ∧ 𝑝 ∈ 𝐴 ) ∧ ( 𝑟 ∈ 𝑋 ∧ 𝑞 ∈ ( ⊥ ‘ 𝑋 ) ∧ 𝑝 ≤ ( 𝑟 ∨ 𝑞 ) ) ) → 𝑝 ∈ 𝐴 ) | |
| 15 | simpr3 | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑋 ⊆ 𝐴 ∧ 𝑝 ∈ 𝐴 ) ∧ ( 𝑟 ∈ 𝑋 ∧ 𝑞 ∈ ( ⊥ ‘ 𝑋 ) ∧ 𝑝 ≤ ( 𝑟 ∨ 𝑞 ) ) ) → 𝑝 ≤ ( 𝑟 ∨ 𝑞 ) ) | |
| 16 | 1 2 3 4 | elpaddri | ⊢ ( ( ( 𝐾 ∈ Lat ∧ 𝑋 ⊆ 𝐴 ∧ ( ⊥ ‘ 𝑋 ) ⊆ 𝐴 ) ∧ ( 𝑟 ∈ 𝑋 ∧ 𝑞 ∈ ( ⊥ ‘ 𝑋 ) ) ∧ ( 𝑝 ∈ 𝐴 ∧ 𝑝 ≤ ( 𝑟 ∨ 𝑞 ) ) ) → 𝑝 ∈ ( 𝑋 + ( ⊥ ‘ 𝑋 ) ) ) |
| 17 | 8 9 11 12 13 14 15 16 | syl322anc | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑋 ⊆ 𝐴 ∧ 𝑝 ∈ 𝐴 ) ∧ ( 𝑟 ∈ 𝑋 ∧ 𝑞 ∈ ( ⊥ ‘ 𝑋 ) ∧ 𝑝 ≤ ( 𝑟 ∨ 𝑞 ) ) ) → 𝑝 ∈ ( 𝑋 + ( ⊥ ‘ 𝑋 ) ) ) |