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Description: Alternate proof for lidl1 not using rnglidl1 : Every ring contains a unit ideal. (Contributed by Stefan O'Rear, 3-Jan-2015) (Proof modification is discouraged.) (New usage is discouraged.)
| Ref | Expression | ||
|---|---|---|---|
| Hypotheses | rnglidl0.u | ⊢ 𝑈 = ( LIdeal ‘ 𝑅 ) | |
| rnglidl1.b | ⊢ 𝐵 = ( Base ‘ 𝑅 ) | ||
| Assertion | lidl1ALT | ⊢ ( 𝑅 ∈ Ring → 𝐵 ∈ 𝑈 ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | rnglidl0.u | ⊢ 𝑈 = ( LIdeal ‘ 𝑅 ) | |
| 2 | rnglidl1.b | ⊢ 𝐵 = ( Base ‘ 𝑅 ) | |
| 3 | rlmlmod | ⊢ ( 𝑅 ∈ Ring → ( ringLMod ‘ 𝑅 ) ∈ LMod ) | |
| 4 | rlmbas | ⊢ ( Base ‘ 𝑅 ) = ( Base ‘ ( ringLMod ‘ 𝑅 ) ) | |
| 5 | 2 4 | eqtri | ⊢ 𝐵 = ( Base ‘ ( ringLMod ‘ 𝑅 ) ) |
| 6 | eqid | ⊢ ( LSubSp ‘ ( ringLMod ‘ 𝑅 ) ) = ( LSubSp ‘ ( ringLMod ‘ 𝑅 ) ) | |
| 7 | 5 6 | lss1 | ⊢ ( ( ringLMod ‘ 𝑅 ) ∈ LMod → 𝐵 ∈ ( LSubSp ‘ ( ringLMod ‘ 𝑅 ) ) ) |
| 8 | 3 7 | syl | ⊢ ( 𝑅 ∈ Ring → 𝐵 ∈ ( LSubSp ‘ ( ringLMod ‘ 𝑅 ) ) ) |
| 9 | lidlval | ⊢ ( LIdeal ‘ 𝑅 ) = ( LSubSp ‘ ( ringLMod ‘ 𝑅 ) ) | |
| 10 | 1 9 | eqtri | ⊢ 𝑈 = ( LSubSp ‘ ( ringLMod ‘ 𝑅 ) ) |
| 11 | 8 10 | eleqtrrdi | ⊢ ( 𝑅 ∈ Ring → 𝐵 ∈ 𝑈 ) |