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Description: Prove a subgroup by closure. (Contributed by Stefan O'Rear, 7-Dec-2014)
| Ref | Expression | ||
|---|---|---|---|
| Hypotheses | issubgrpd.s | ⊢ ( 𝜑 → 𝑆 = ( 𝐼 ↾s 𝐷 ) ) | |
| issubgrpd.z | ⊢ ( 𝜑 → 0 = ( 0g ‘ 𝐼 ) ) | ||
| issubgrpd.p | ⊢ ( 𝜑 → + = ( +g ‘ 𝐼 ) ) | ||
| issubgrpd.ss | ⊢ ( 𝜑 → 𝐷 ⊆ ( Base ‘ 𝐼 ) ) | ||
| issubgrpd.zcl | ⊢ ( 𝜑 → 0 ∈ 𝐷 ) | ||
| issubgrpd.acl | ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐷 ∧ 𝑦 ∈ 𝐷 ) → ( 𝑥 + 𝑦 ) ∈ 𝐷 ) | ||
| issubgrpd.ncl | ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐷 ) → ( ( invg ‘ 𝐼 ) ‘ 𝑥 ) ∈ 𝐷 ) | ||
| issubgrpd.g | ⊢ ( 𝜑 → 𝐼 ∈ Grp ) | ||
| Assertion | issubgrpd | ⊢ ( 𝜑 → 𝑆 ∈ Grp ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | issubgrpd.s | ⊢ ( 𝜑 → 𝑆 = ( 𝐼 ↾s 𝐷 ) ) | |
| 2 | issubgrpd.z | ⊢ ( 𝜑 → 0 = ( 0g ‘ 𝐼 ) ) | |
| 3 | issubgrpd.p | ⊢ ( 𝜑 → + = ( +g ‘ 𝐼 ) ) | |
| 4 | issubgrpd.ss | ⊢ ( 𝜑 → 𝐷 ⊆ ( Base ‘ 𝐼 ) ) | |
| 5 | issubgrpd.zcl | ⊢ ( 𝜑 → 0 ∈ 𝐷 ) | |
| 6 | issubgrpd.acl | ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐷 ∧ 𝑦 ∈ 𝐷 ) → ( 𝑥 + 𝑦 ) ∈ 𝐷 ) | |
| 7 | issubgrpd.ncl | ⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐷 ) → ( ( invg ‘ 𝐼 ) ‘ 𝑥 ) ∈ 𝐷 ) | |
| 8 | issubgrpd.g | ⊢ ( 𝜑 → 𝐼 ∈ Grp ) | |
| 9 | 1 2 3 4 5 6 7 8 | issubgrpd2 | ⊢ ( 𝜑 → 𝐷 ∈ ( SubGrp ‘ 𝐼 ) ) |
| 10 | eqid | ⊢ ( 𝐼 ↾s 𝐷 ) = ( 𝐼 ↾s 𝐷 ) | |
| 11 | 10 | subggrp | ⊢ ( 𝐷 ∈ ( SubGrp ‘ 𝐼 ) → ( 𝐼 ↾s 𝐷 ) ∈ Grp ) |
| 12 | 9 11 | syl | ⊢ ( 𝜑 → ( 𝐼 ↾s 𝐷 ) ∈ Grp ) |
| 13 | 1 12 | eqeltrd | ⊢ ( 𝜑 → 𝑆 ∈ Grp ) |