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Metamath Proof Explorer

Theorem hvsubeq0

Description: If the difference between two vectors is zero, they are equal. (Contributed by NM, 23-Oct-1999) (New usage is discouraged.)

		Ref	Expression
	Assertion	hvsubeq0	⊢ ( ( 𝐴 ∈ ℋ ∧ 𝐵 ∈ ℋ ) → ( ( 𝐴 −_ℎ 𝐵 ) = 0_ℎ ↔ 𝐴 = 𝐵 ) )

Proof

Step	Hyp	Ref	Expression
1		oveq1	⊢ ( 𝐴 = if ( 𝐴 ∈ ℋ , 𝐴 , 0_ℎ ) → ( 𝐴 −_ℎ 𝐵 ) = ( if ( 𝐴 ∈ ℋ , 𝐴 , 0_ℎ ) −_ℎ 𝐵 ) )
2	1	eqeq1d	⊢ ( 𝐴 = if ( 𝐴 ∈ ℋ , 𝐴 , 0_ℎ ) → ( ( 𝐴 −_ℎ 𝐵 ) = 0_ℎ ↔ ( if ( 𝐴 ∈ ℋ , 𝐴 , 0_ℎ ) −_ℎ 𝐵 ) = 0_ℎ ) )
3		eqeq1	⊢ ( 𝐴 = if ( 𝐴 ∈ ℋ , 𝐴 , 0_ℎ ) → ( 𝐴 = 𝐵 ↔ if ( 𝐴 ∈ ℋ , 𝐴 , 0_ℎ ) = 𝐵 ) )
4	2 3	bibi12d	⊢ ( 𝐴 = if ( 𝐴 ∈ ℋ , 𝐴 , 0_ℎ ) → ( ( ( 𝐴 −_ℎ 𝐵 ) = 0_ℎ ↔ 𝐴 = 𝐵 ) ↔ ( ( if ( 𝐴 ∈ ℋ , 𝐴 , 0_ℎ ) −_ℎ 𝐵 ) = 0_ℎ ↔ if ( 𝐴 ∈ ℋ , 𝐴 , 0_ℎ ) = 𝐵 ) ) )
5		oveq2	⊢ ( 𝐵 = if ( 𝐵 ∈ ℋ , 𝐵 , 0_ℎ ) → ( if ( 𝐴 ∈ ℋ , 𝐴 , 0_ℎ ) −_ℎ 𝐵 ) = ( if ( 𝐴 ∈ ℋ , 𝐴 , 0_ℎ ) −_ℎ if ( 𝐵 ∈ ℋ , 𝐵 , 0_ℎ ) ) )
6	5	eqeq1d	⊢ ( 𝐵 = if ( 𝐵 ∈ ℋ , 𝐵 , 0_ℎ ) → ( ( if ( 𝐴 ∈ ℋ , 𝐴 , 0_ℎ ) −_ℎ 𝐵 ) = 0_ℎ ↔ ( if ( 𝐴 ∈ ℋ , 𝐴 , 0_ℎ ) −_ℎ if ( 𝐵 ∈ ℋ , 𝐵 , 0_ℎ ) ) = 0_ℎ ) )
7		eqeq2	⊢ ( 𝐵 = if ( 𝐵 ∈ ℋ , 𝐵 , 0_ℎ ) → ( if ( 𝐴 ∈ ℋ , 𝐴 , 0_ℎ ) = 𝐵 ↔ if ( 𝐴 ∈ ℋ , 𝐴 , 0_ℎ ) = if ( 𝐵 ∈ ℋ , 𝐵 , 0_ℎ ) ) )
8	6 7	bibi12d	⊢ ( 𝐵 = if ( 𝐵 ∈ ℋ , 𝐵 , 0_ℎ ) → ( ( ( if ( 𝐴 ∈ ℋ , 𝐴 , 0_ℎ ) −_ℎ 𝐵 ) = 0_ℎ ↔ if ( 𝐴 ∈ ℋ , 𝐴 , 0_ℎ ) = 𝐵 ) ↔ ( ( if ( 𝐴 ∈ ℋ , 𝐴 , 0_ℎ ) −_ℎ if ( 𝐵 ∈ ℋ , 𝐵 , 0_ℎ ) ) = 0_ℎ ↔ if ( 𝐴 ∈ ℋ , 𝐴 , 0_ℎ ) = if ( 𝐵 ∈ ℋ , 𝐵 , 0_ℎ ) ) ) )
9		ifhvhv0	⊢ if ( 𝐴 ∈ ℋ , 𝐴 , 0_ℎ ) ∈ ℋ
10		ifhvhv0	⊢ if ( 𝐵 ∈ ℋ , 𝐵 , 0_ℎ ) ∈ ℋ
11	9 10	hvsubeq0i	⊢ ( ( if ( 𝐴 ∈ ℋ , 𝐴 , 0_ℎ ) −_ℎ if ( 𝐵 ∈ ℋ , 𝐵 , 0_ℎ ) ) = 0_ℎ ↔ if ( 𝐴 ∈ ℋ , 𝐴 , 0_ℎ ) = if ( 𝐵 ∈ ℋ , 𝐵 , 0_ℎ ) )
12	4 8 11	dedth2h	⊢ ( ( 𝐴 ∈ ℋ ∧ 𝐵 ∈ ℋ ) → ( ( 𝐴 −_ℎ 𝐵 ) = 0_ℎ ↔ 𝐴 = 𝐵 ) )