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Description: If two nonnegative integers divide each other, they must be equal. (Contributed by Mario Carneiro, 30-May-2014) (Proof shortened by AV, 7-Aug-2021)
| Ref | Expression | ||
|---|---|---|---|
| Assertion | dvdseq | ⊢ ( ( ( 𝑀 ∈ ℕ0 ∧ 𝑁 ∈ ℕ0 ) ∧ ( 𝑀 ∥ 𝑁 ∧ 𝑁 ∥ 𝑀 ) ) → 𝑀 = 𝑁 ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | dvdsabseq | ⊢ ( ( 𝑀 ∥ 𝑁 ∧ 𝑁 ∥ 𝑀 ) → ( abs ‘ 𝑀 ) = ( abs ‘ 𝑁 ) ) | |
| 2 | nn0re | ⊢ ( 𝑀 ∈ ℕ0 → 𝑀 ∈ ℝ ) | |
| 3 | nn0ge0 | ⊢ ( 𝑀 ∈ ℕ0 → 0 ≤ 𝑀 ) | |
| 4 | 2 3 | absidd | ⊢ ( 𝑀 ∈ ℕ0 → ( abs ‘ 𝑀 ) = 𝑀 ) |
| 5 | 4 | adantr | ⊢ ( ( 𝑀 ∈ ℕ0 ∧ 𝑁 ∈ ℕ0 ) → ( abs ‘ 𝑀 ) = 𝑀 ) |
| 6 | 5 | eqcomd | ⊢ ( ( 𝑀 ∈ ℕ0 ∧ 𝑁 ∈ ℕ0 ) → 𝑀 = ( abs ‘ 𝑀 ) ) |
| 7 | 6 | adantr | ⊢ ( ( ( 𝑀 ∈ ℕ0 ∧ 𝑁 ∈ ℕ0 ) ∧ ( abs ‘ 𝑀 ) = ( abs ‘ 𝑁 ) ) → 𝑀 = ( abs ‘ 𝑀 ) ) |
| 8 | simpr | ⊢ ( ( ( 𝑀 ∈ ℕ0 ∧ 𝑁 ∈ ℕ0 ) ∧ ( abs ‘ 𝑀 ) = ( abs ‘ 𝑁 ) ) → ( abs ‘ 𝑀 ) = ( abs ‘ 𝑁 ) ) | |
| 9 | nn0re | ⊢ ( 𝑁 ∈ ℕ0 → 𝑁 ∈ ℝ ) | |
| 10 | nn0ge0 | ⊢ ( 𝑁 ∈ ℕ0 → 0 ≤ 𝑁 ) | |
| 11 | 9 10 | absidd | ⊢ ( 𝑁 ∈ ℕ0 → ( abs ‘ 𝑁 ) = 𝑁 ) |
| 12 | 11 | ad2antlr | ⊢ ( ( ( 𝑀 ∈ ℕ0 ∧ 𝑁 ∈ ℕ0 ) ∧ ( abs ‘ 𝑀 ) = ( abs ‘ 𝑁 ) ) → ( abs ‘ 𝑁 ) = 𝑁 ) |
| 13 | 7 8 12 | 3eqtrd | ⊢ ( ( ( 𝑀 ∈ ℕ0 ∧ 𝑁 ∈ ℕ0 ) ∧ ( abs ‘ 𝑀 ) = ( abs ‘ 𝑁 ) ) → 𝑀 = 𝑁 ) |
| 14 | 1 13 | sylan2 | ⊢ ( ( ( 𝑀 ∈ ℕ0 ∧ 𝑁 ∈ ℕ0 ) ∧ ( 𝑀 ∥ 𝑁 ∧ 𝑁 ∥ 𝑀 ) ) → 𝑀 = 𝑁 ) |