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Description: Version of modular law that holds in a Hilbert lattice, when one element is an atom. (Contributed by NM, 10-Jun-2012) (Revised by Mario Carneiro, 10-May-2013)
| Ref | Expression | ||
|---|---|---|---|
| Hypotheses | atmod.b | ⊢ 𝐵 = ( Base ‘ 𝐾 ) | |
| atmod.l | ⊢ ≤ = ( le ‘ 𝐾 ) | ||
| atmod.j | ⊢ ∨ = ( join ‘ 𝐾 ) | ||
| atmod.m | ⊢ ∧ = ( meet ‘ 𝐾 ) | ||
| atmod.a | ⊢ 𝐴 = ( Atoms ‘ 𝐾 ) | ||
| Assertion | atmod3i2 | ⊢ ( ( 𝐾 ∈ HL ∧ ( 𝑃 ∈ 𝐴 ∧ 𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ) ∧ 𝑋 ≤ 𝑌 ) → ( 𝑋 ∨ ( 𝑌 ∧ 𝑃 ) ) = ( 𝑌 ∧ ( 𝑋 ∨ 𝑃 ) ) ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | atmod.b | ⊢ 𝐵 = ( Base ‘ 𝐾 ) | |
| 2 | atmod.l | ⊢ ≤ = ( le ‘ 𝐾 ) | |
| 3 | atmod.j | ⊢ ∨ = ( join ‘ 𝐾 ) | |
| 4 | atmod.m | ⊢ ∧ = ( meet ‘ 𝐾 ) | |
| 5 | atmod.a | ⊢ 𝐴 = ( Atoms ‘ 𝐾 ) | |
| 6 | hllat | ⊢ ( 𝐾 ∈ HL → 𝐾 ∈ Lat ) | |
| 7 | 6 | 3ad2ant1 | ⊢ ( ( 𝐾 ∈ HL ∧ ( 𝑃 ∈ 𝐴 ∧ 𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ) ∧ 𝑋 ≤ 𝑌 ) → 𝐾 ∈ Lat ) |
| 8 | simp23 | ⊢ ( ( 𝐾 ∈ HL ∧ ( 𝑃 ∈ 𝐴 ∧ 𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ) ∧ 𝑋 ≤ 𝑌 ) → 𝑌 ∈ 𝐵 ) | |
| 9 | simp22 | ⊢ ( ( 𝐾 ∈ HL ∧ ( 𝑃 ∈ 𝐴 ∧ 𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ) ∧ 𝑋 ≤ 𝑌 ) → 𝑋 ∈ 𝐵 ) | |
| 10 | simp21 | ⊢ ( ( 𝐾 ∈ HL ∧ ( 𝑃 ∈ 𝐴 ∧ 𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ) ∧ 𝑋 ≤ 𝑌 ) → 𝑃 ∈ 𝐴 ) | |
| 11 | 1 5 | atbase | ⊢ ( 𝑃 ∈ 𝐴 → 𝑃 ∈ 𝐵 ) |
| 12 | 10 11 | syl | ⊢ ( ( 𝐾 ∈ HL ∧ ( 𝑃 ∈ 𝐴 ∧ 𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ) ∧ 𝑋 ≤ 𝑌 ) → 𝑃 ∈ 𝐵 ) |
| 13 | 1 3 | latjcl | ⊢ ( ( 𝐾 ∈ Lat ∧ 𝑋 ∈ 𝐵 ∧ 𝑃 ∈ 𝐵 ) → ( 𝑋 ∨ 𝑃 ) ∈ 𝐵 ) |
| 14 | 7 9 12 13 | syl3anc | ⊢ ( ( 𝐾 ∈ HL ∧ ( 𝑃 ∈ 𝐴 ∧ 𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ) ∧ 𝑋 ≤ 𝑌 ) → ( 𝑋 ∨ 𝑃 ) ∈ 𝐵 ) |
| 15 | 1 4 | latmcom | ⊢ ( ( 𝐾 ∈ Lat ∧ 𝑌 ∈ 𝐵 ∧ ( 𝑋 ∨ 𝑃 ) ∈ 𝐵 ) → ( 𝑌 ∧ ( 𝑋 ∨ 𝑃 ) ) = ( ( 𝑋 ∨ 𝑃 ) ∧ 𝑌 ) ) |
| 16 | 7 8 14 15 | syl3anc | ⊢ ( ( 𝐾 ∈ HL ∧ ( 𝑃 ∈ 𝐴 ∧ 𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ) ∧ 𝑋 ≤ 𝑌 ) → ( 𝑌 ∧ ( 𝑋 ∨ 𝑃 ) ) = ( ( 𝑋 ∨ 𝑃 ) ∧ 𝑌 ) ) |
| 17 | 1 2 3 4 5 | atmod1i2 | ⊢ ( ( 𝐾 ∈ HL ∧ ( 𝑃 ∈ 𝐴 ∧ 𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ) ∧ 𝑋 ≤ 𝑌 ) → ( 𝑋 ∨ ( 𝑃 ∧ 𝑌 ) ) = ( ( 𝑋 ∨ 𝑃 ) ∧ 𝑌 ) ) |
| 18 | 1 4 | latmcom | ⊢ ( ( 𝐾 ∈ Lat ∧ 𝑃 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ) → ( 𝑃 ∧ 𝑌 ) = ( 𝑌 ∧ 𝑃 ) ) |
| 19 | 7 12 8 18 | syl3anc | ⊢ ( ( 𝐾 ∈ HL ∧ ( 𝑃 ∈ 𝐴 ∧ 𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ) ∧ 𝑋 ≤ 𝑌 ) → ( 𝑃 ∧ 𝑌 ) = ( 𝑌 ∧ 𝑃 ) ) |
| 20 | 19 | oveq2d | ⊢ ( ( 𝐾 ∈ HL ∧ ( 𝑃 ∈ 𝐴 ∧ 𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ) ∧ 𝑋 ≤ 𝑌 ) → ( 𝑋 ∨ ( 𝑃 ∧ 𝑌 ) ) = ( 𝑋 ∨ ( 𝑌 ∧ 𝑃 ) ) ) |
| 21 | 16 17 20 | 3eqtr2rd | ⊢ ( ( 𝐾 ∈ HL ∧ ( 𝑃 ∈ 𝐴 ∧ 𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ) ∧ 𝑋 ≤ 𝑌 ) → ( 𝑋 ∨ ( 𝑌 ∧ 𝑃 ) ) = ( 𝑌 ∧ ( 𝑋 ∨ 𝑃 ) ) ) |