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Description: If a vertex in a simple graph has degree 0, the vertex is not adjacent to another vertex via an edge. (Contributed by Alexander van der Vekens, 20-Dec-2017) (Revised by AV, 16-Dec-2020) (Proof shortened by AV, 23-Dec-2020)
| Ref | Expression | ||
|---|---|---|---|
| Hypotheses | vtxdusgradjvtx.v | ⊢ 𝑉 = ( Vtx ‘ 𝐺 ) | |
| vtxdusgradjvtx.e | ⊢ 𝐸 = ( Edg ‘ 𝐺 ) | ||
| Assertion | usgrvd0nedg | ⊢ ( ( 𝐺 ∈ USGraph ∧ 𝑈 ∈ 𝑉 ) → ( ( ( VtxDeg ‘ 𝐺 ) ‘ 𝑈 ) = 0 → ¬ ∃ 𝑣 ∈ 𝑉 { 𝑈 , 𝑣 } ∈ 𝐸 ) ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | vtxdusgradjvtx.v | ⊢ 𝑉 = ( Vtx ‘ 𝐺 ) | |
| 2 | vtxdusgradjvtx.e | ⊢ 𝐸 = ( Edg ‘ 𝐺 ) | |
| 3 | 1 2 | vtxdusgradjvtx | ⊢ ( ( 𝐺 ∈ USGraph ∧ 𝑈 ∈ 𝑉 ) → ( ( VtxDeg ‘ 𝐺 ) ‘ 𝑈 ) = ( ♯ ‘ { 𝑣 ∈ 𝑉 ∣ { 𝑈 , 𝑣 } ∈ 𝐸 } ) ) |
| 4 | 3 | eqeq1d | ⊢ ( ( 𝐺 ∈ USGraph ∧ 𝑈 ∈ 𝑉 ) → ( ( ( VtxDeg ‘ 𝐺 ) ‘ 𝑈 ) = 0 ↔ ( ♯ ‘ { 𝑣 ∈ 𝑉 ∣ { 𝑈 , 𝑣 } ∈ 𝐸 } ) = 0 ) ) |
| 5 | 1 | fvexi | ⊢ 𝑉 ∈ V |
| 6 | 5 | rabex | ⊢ { 𝑣 ∈ 𝑉 ∣ { 𝑈 , 𝑣 } ∈ 𝐸 } ∈ V |
| 7 | hasheq0 | ⊢ ( { 𝑣 ∈ 𝑉 ∣ { 𝑈 , 𝑣 } ∈ 𝐸 } ∈ V → ( ( ♯ ‘ { 𝑣 ∈ 𝑉 ∣ { 𝑈 , 𝑣 } ∈ 𝐸 } ) = 0 ↔ { 𝑣 ∈ 𝑉 ∣ { 𝑈 , 𝑣 } ∈ 𝐸 } = ∅ ) ) | |
| 8 | 6 7 | ax-mp | ⊢ ( ( ♯ ‘ { 𝑣 ∈ 𝑉 ∣ { 𝑈 , 𝑣 } ∈ 𝐸 } ) = 0 ↔ { 𝑣 ∈ 𝑉 ∣ { 𝑈 , 𝑣 } ∈ 𝐸 } = ∅ ) |
| 9 | rabeq0 | ⊢ ( { 𝑣 ∈ 𝑉 ∣ { 𝑈 , 𝑣 } ∈ 𝐸 } = ∅ ↔ ∀ 𝑣 ∈ 𝑉 ¬ { 𝑈 , 𝑣 } ∈ 𝐸 ) | |
| 10 | ralnex | ⊢ ( ∀ 𝑣 ∈ 𝑉 ¬ { 𝑈 , 𝑣 } ∈ 𝐸 ↔ ¬ ∃ 𝑣 ∈ 𝑉 { 𝑈 , 𝑣 } ∈ 𝐸 ) | |
| 11 | 10 | biimpi | ⊢ ( ∀ 𝑣 ∈ 𝑉 ¬ { 𝑈 , 𝑣 } ∈ 𝐸 → ¬ ∃ 𝑣 ∈ 𝑉 { 𝑈 , 𝑣 } ∈ 𝐸 ) |
| 12 | 11 | a1i | ⊢ ( ( 𝐺 ∈ USGraph ∧ 𝑈 ∈ 𝑉 ) → ( ∀ 𝑣 ∈ 𝑉 ¬ { 𝑈 , 𝑣 } ∈ 𝐸 → ¬ ∃ 𝑣 ∈ 𝑉 { 𝑈 , 𝑣 } ∈ 𝐸 ) ) |
| 13 | 9 12 | biimtrid | ⊢ ( ( 𝐺 ∈ USGraph ∧ 𝑈 ∈ 𝑉 ) → ( { 𝑣 ∈ 𝑉 ∣ { 𝑈 , 𝑣 } ∈ 𝐸 } = ∅ → ¬ ∃ 𝑣 ∈ 𝑉 { 𝑈 , 𝑣 } ∈ 𝐸 ) ) |
| 14 | 8 13 | biimtrid | ⊢ ( ( 𝐺 ∈ USGraph ∧ 𝑈 ∈ 𝑉 ) → ( ( ♯ ‘ { 𝑣 ∈ 𝑉 ∣ { 𝑈 , 𝑣 } ∈ 𝐸 } ) = 0 → ¬ ∃ 𝑣 ∈ 𝑉 { 𝑈 , 𝑣 } ∈ 𝐸 ) ) |
| 15 | 4 14 | sylbid | ⊢ ( ( 𝐺 ∈ USGraph ∧ 𝑈 ∈ 𝑉 ) → ( ( ( VtxDeg ‘ 𝐺 ) ‘ 𝑈 ) = 0 → ¬ ∃ 𝑣 ∈ 𝑉 { 𝑈 , 𝑣 } ∈ 𝐸 ) ) |