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Description: If every vertex in a simple graph has degree 0, there is no edge in the graph. (Contributed by Alexander van der Vekens, 12-Jul-2018) (Revised by AV, 17-Dec-2020) (Proof shortened by AV, 23-Dec-2020)
| Ref | Expression | ||
|---|---|---|---|
| Hypotheses | vtxdusgradjvtx.v | ⊢ 𝑉 = ( Vtx ‘ 𝐺 ) | |
| vtxdusgradjvtx.e | ⊢ 𝐸 = ( Edg ‘ 𝐺 ) | ||
| Assertion | usgrvd00 | ⊢ ( 𝐺 ∈ USGraph → ( ∀ 𝑣 ∈ 𝑉 ( ( VtxDeg ‘ 𝐺 ) ‘ 𝑣 ) = 0 → 𝐸 = ∅ ) ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | vtxdusgradjvtx.v | ⊢ 𝑉 = ( Vtx ‘ 𝐺 ) | |
| 2 | vtxdusgradjvtx.e | ⊢ 𝐸 = ( Edg ‘ 𝐺 ) | |
| 3 | usgruhgr | ⊢ ( 𝐺 ∈ USGraph → 𝐺 ∈ UHGraph ) | |
| 4 | 1 2 | uhgrvd00 | ⊢ ( 𝐺 ∈ UHGraph → ( ∀ 𝑣 ∈ 𝑉 ( ( VtxDeg ‘ 𝐺 ) ‘ 𝑣 ) = 0 → 𝐸 = ∅ ) ) |
| 5 | 3 4 | syl | ⊢ ( 𝐺 ∈ USGraph → ( ∀ 𝑣 ∈ 𝑉 ( ( VtxDeg ‘ 𝐺 ) ‘ 𝑣 ) = 0 → 𝐸 = ∅ ) ) |