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Description: If every vertex in a simple graph has degree 0, there is no edge in the graph. (Contributed by Alexander van der Vekens, 12-Jul-2018) (Revised by AV, 17-Dec-2020) (Proof shortened by AV, 23-Dec-2020)
| Ref | Expression | ||
|---|---|---|---|
| Hypotheses | vtxdusgradjvtx.v | |- V = ( Vtx ` G ) |
|
| vtxdusgradjvtx.e | |- E = ( Edg ` G ) |
||
| Assertion | usgrvd00 | |- ( G e. USGraph -> ( A. v e. V ( ( VtxDeg ` G ) ` v ) = 0 -> E = (/) ) ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | vtxdusgradjvtx.v | |- V = ( Vtx ` G ) |
|
| 2 | vtxdusgradjvtx.e | |- E = ( Edg ` G ) |
|
| 3 | usgruhgr | |- ( G e. USGraph -> G e. UHGraph ) |
|
| 4 | 1 2 | uhgrvd00 | |- ( G e. UHGraph -> ( A. v e. V ( ( VtxDeg ` G ) ` v ) = 0 -> E = (/) ) ) |
| 5 | 3 4 | syl | |- ( G e. USGraph -> ( A. v e. V ( ( VtxDeg ` G ) ` v ) = 0 -> E = (/) ) ) |