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Description: Deduction form of trel . In a transitive class, the membership relation is transitive. (Contributed by Alan Sare, 3-Dec-2015) (Proof modification is discouraged.) (New usage is discouraged.)
| Ref | Expression | ||
|---|---|---|---|
| Hypotheses | trelded.1 | ⊢ ( 𝜑 → Tr 𝐴 ) | |
| trelded.2 | ⊢ ( 𝜓 → 𝐵 ∈ 𝐶 ) | ||
| trelded.3 | ⊢ ( 𝜒 → 𝐶 ∈ 𝐴 ) | ||
| Assertion | trelded | ⊢ ( ( 𝜑 ∧ 𝜓 ∧ 𝜒 ) → 𝐵 ∈ 𝐴 ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | trelded.1 | ⊢ ( 𝜑 → Tr 𝐴 ) | |
| 2 | trelded.2 | ⊢ ( 𝜓 → 𝐵 ∈ 𝐶 ) | |
| 3 | trelded.3 | ⊢ ( 𝜒 → 𝐶 ∈ 𝐴 ) | |
| 4 | trel | ⊢ ( Tr 𝐴 → ( ( 𝐵 ∈ 𝐶 ∧ 𝐶 ∈ 𝐴 ) → 𝐵 ∈ 𝐴 ) ) | |
| 5 | 4 | 3impib | ⊢ ( ( Tr 𝐴 ∧ 𝐵 ∈ 𝐶 ∧ 𝐶 ∈ 𝐴 ) → 𝐵 ∈ 𝐴 ) |
| 6 | 1 2 3 5 | syl3an | ⊢ ( ( 𝜑 ∧ 𝜓 ∧ 𝜒 ) → 𝐵 ∈ 𝐴 ) |