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Metamath Proof Explorer

Theorem ssoprab2i

Description: Inference of operation class abstraction subclass from implication. (Contributed by NM, 11-Nov-1995) (Revised by David Abernethy, 19-Jun-2012)

		Ref	Expression
	Hypothesis	ssoprab2i.1	⊢ ( 𝜑 → 𝜓 )
	Assertion	ssoprab2i	⊢ { ⟨ ⟨ 𝑥 , 𝑦 ⟩ , 𝑧 ⟩ ∣ 𝜑 } ⊆ { ⟨ ⟨ 𝑥 , 𝑦 ⟩ , 𝑧 ⟩ ∣ 𝜓 }

Proof

Step	Hyp	Ref	Expression
1		ssoprab2i.1	⊢ ( 𝜑 → 𝜓 )
2	1	anim2i	⊢ ( ( 𝑤 = ⟨ 𝑥 , 𝑦 ⟩ ∧ 𝜑 ) → ( 𝑤 = ⟨ 𝑥 , 𝑦 ⟩ ∧ 𝜓 ) )
3	2	2eximi	⊢ ( ∃ 𝑥 ∃ 𝑦 ( 𝑤 = ⟨ 𝑥 , 𝑦 ⟩ ∧ 𝜑 ) → ∃ 𝑥 ∃ 𝑦 ( 𝑤 = ⟨ 𝑥 , 𝑦 ⟩ ∧ 𝜓 ) )
4	3	ssopab2i	⊢ { ⟨ 𝑤 , 𝑧 ⟩ ∣ ∃ 𝑥 ∃ 𝑦 ( 𝑤 = ⟨ 𝑥 , 𝑦 ⟩ ∧ 𝜑 ) } ⊆ { ⟨ 𝑤 , 𝑧 ⟩ ∣ ∃ 𝑥 ∃ 𝑦 ( 𝑤 = ⟨ 𝑥 , 𝑦 ⟩ ∧ 𝜓 ) }
5		dfoprab2	⊢ { ⟨ ⟨ 𝑥 , 𝑦 ⟩ , 𝑧 ⟩ ∣ 𝜑 } = { ⟨ 𝑤 , 𝑧 ⟩ ∣ ∃ 𝑥 ∃ 𝑦 ( 𝑤 = ⟨ 𝑥 , 𝑦 ⟩ ∧ 𝜑 ) }
6		dfoprab2	⊢ { ⟨ ⟨ 𝑥 , 𝑦 ⟩ , 𝑧 ⟩ ∣ 𝜓 } = { ⟨ 𝑤 , 𝑧 ⟩ ∣ ∃ 𝑥 ∃ 𝑦 ( 𝑤 = ⟨ 𝑥 , 𝑦 ⟩ ∧ 𝜓 ) }
7	4 5 6	3sstr4i	⊢ { ⟨ ⟨ 𝑥 , 𝑦 ⟩ , 𝑧 ⟩ ∣ 𝜑 } ⊆ { ⟨ ⟨ 𝑥 , 𝑦 ⟩ , 𝑧 ⟩ ∣ 𝜓 }