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Description: mul02 without ax-mulcom . See https://github.com/icecream17/Stuff/blob/main/math/0A%3D0.md for an outline. (Contributed by SN, 30-Jun-2024)
| Ref | Expression | ||
|---|---|---|---|
| Assertion | sn-mul02 | ⊢ ( 𝐴 ∈ ℂ → ( 0 · 𝐴 ) = 0 ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | cnre | ⊢ ( 𝐴 ∈ ℂ → ∃ 𝑥 ∈ ℝ ∃ 𝑦 ∈ ℝ 𝐴 = ( 𝑥 + ( i · 𝑦 ) ) ) | |
| 2 | 0cnd | ⊢ ( ( 𝑥 ∈ ℝ ∧ 𝑦 ∈ ℝ ) → 0 ∈ ℂ ) | |
| 3 | recn | ⊢ ( 𝑥 ∈ ℝ → 𝑥 ∈ ℂ ) | |
| 4 | 3 | adantr | ⊢ ( ( 𝑥 ∈ ℝ ∧ 𝑦 ∈ ℝ ) → 𝑥 ∈ ℂ ) |
| 5 | ax-icn | ⊢ i ∈ ℂ | |
| 6 | 5 | a1i | ⊢ ( ( 𝑥 ∈ ℝ ∧ 𝑦 ∈ ℝ ) → i ∈ ℂ ) |
| 7 | recn | ⊢ ( 𝑦 ∈ ℝ → 𝑦 ∈ ℂ ) | |
| 8 | 7 | adantl | ⊢ ( ( 𝑥 ∈ ℝ ∧ 𝑦 ∈ ℝ ) → 𝑦 ∈ ℂ ) |
| 9 | 6 8 | mulcld | ⊢ ( ( 𝑥 ∈ ℝ ∧ 𝑦 ∈ ℝ ) → ( i · 𝑦 ) ∈ ℂ ) |
| 10 | 2 4 9 | adddid | ⊢ ( ( 𝑥 ∈ ℝ ∧ 𝑦 ∈ ℝ ) → ( 0 · ( 𝑥 + ( i · 𝑦 ) ) ) = ( ( 0 · 𝑥 ) + ( 0 · ( i · 𝑦 ) ) ) ) |
| 11 | remul02 | ⊢ ( 𝑥 ∈ ℝ → ( 0 · 𝑥 ) = 0 ) | |
| 12 | 11 | adantr | ⊢ ( ( 𝑥 ∈ ℝ ∧ 𝑦 ∈ ℝ ) → ( 0 · 𝑥 ) = 0 ) |
| 13 | sn-0tie0 | ⊢ ( 0 · i ) = 0 | |
| 14 | 13 | oveq1i | ⊢ ( ( 0 · i ) · 𝑦 ) = ( 0 · 𝑦 ) |
| 15 | 2 6 8 | mulassd | ⊢ ( ( 𝑥 ∈ ℝ ∧ 𝑦 ∈ ℝ ) → ( ( 0 · i ) · 𝑦 ) = ( 0 · ( i · 𝑦 ) ) ) |
| 16 | remul02 | ⊢ ( 𝑦 ∈ ℝ → ( 0 · 𝑦 ) = 0 ) | |
| 17 | 16 | adantl | ⊢ ( ( 𝑥 ∈ ℝ ∧ 𝑦 ∈ ℝ ) → ( 0 · 𝑦 ) = 0 ) |
| 18 | 14 15 17 | 3eqtr3a | ⊢ ( ( 𝑥 ∈ ℝ ∧ 𝑦 ∈ ℝ ) → ( 0 · ( i · 𝑦 ) ) = 0 ) |
| 19 | 12 18 | oveq12d | ⊢ ( ( 𝑥 ∈ ℝ ∧ 𝑦 ∈ ℝ ) → ( ( 0 · 𝑥 ) + ( 0 · ( i · 𝑦 ) ) ) = ( 0 + 0 ) ) |
| 20 | sn-00id | ⊢ ( 0 + 0 ) = 0 | |
| 21 | 19 20 | eqtrdi | ⊢ ( ( 𝑥 ∈ ℝ ∧ 𝑦 ∈ ℝ ) → ( ( 0 · 𝑥 ) + ( 0 · ( i · 𝑦 ) ) ) = 0 ) |
| 22 | 10 21 | eqtrd | ⊢ ( ( 𝑥 ∈ ℝ ∧ 𝑦 ∈ ℝ ) → ( 0 · ( 𝑥 + ( i · 𝑦 ) ) ) = 0 ) |
| 23 | oveq2 | ⊢ ( 𝐴 = ( 𝑥 + ( i · 𝑦 ) ) → ( 0 · 𝐴 ) = ( 0 · ( 𝑥 + ( i · 𝑦 ) ) ) ) | |
| 24 | 23 | eqeq1d | ⊢ ( 𝐴 = ( 𝑥 + ( i · 𝑦 ) ) → ( ( 0 · 𝐴 ) = 0 ↔ ( 0 · ( 𝑥 + ( i · 𝑦 ) ) ) = 0 ) ) |
| 25 | 22 24 | syl5ibrcom | ⊢ ( ( 𝑥 ∈ ℝ ∧ 𝑦 ∈ ℝ ) → ( 𝐴 = ( 𝑥 + ( i · 𝑦 ) ) → ( 0 · 𝐴 ) = 0 ) ) |
| 26 | 25 | rexlimivv | ⊢ ( ∃ 𝑥 ∈ ℝ ∃ 𝑦 ∈ ℝ 𝐴 = ( 𝑥 + ( i · 𝑦 ) ) → ( 0 · 𝐴 ) = 0 ) |
| 27 | 1 26 | syl | ⊢ ( 𝐴 ∈ ℂ → ( 0 · 𝐴 ) = 0 ) |