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Metamath Proof Explorer

Theorem mulgt0con2d

Description: Lemma for mulgt0b1d and contrapositive of mulgt0 . (Contributed by SN, 26-Jun-2024)

Ref Expression
Hypotheses mulgt0con2d.a ⊢ ( 𝜑 → 𝐴 ∈ ℝ )
mulgt0con2d.b ⊢ ( 𝜑 → 𝐵 ∈ ℝ )
mulgt0con2d.1 ⊢ ( 𝜑 → 0 < 𝐴 )
mulgt0con2d.2 ⊢ ( 𝜑 → ( 𝐴 · 𝐵 ) < 0 )
Assertion mulgt0con2d ( 𝜑 → 𝐵 < 0 )

Proof

Step Hyp Ref Expression
1 mulgt0con2d.a ⊢ ( 𝜑 → 𝐴 ∈ ℝ )
2 mulgt0con2d.b ⊢ ( 𝜑 → 𝐵 ∈ ℝ )
3 mulgt0con2d.1 ⊢ ( 𝜑 → 0 < 𝐴 )
4 mulgt0con2d.2 ⊢ ( 𝜑 → ( 𝐴 · 𝐵 ) < 0 )
5 1 2 remulcld ⊢ ( 𝜑 → ( 𝐴 · 𝐵 ) ∈ ℝ )
6 1 adantr ⊢ ( ( 𝜑 ∧ 0 < 𝐵 ) → 𝐴 ∈ ℝ )
7 2 adantr ⊢ ( ( 𝜑 ∧ 0 < 𝐵 ) → 𝐵 ∈ ℝ )
8 3 adantr ⊢ ( ( 𝜑 ∧ 0 < 𝐵 ) → 0 < 𝐴 )
9 simpr ⊢ ( ( 𝜑 ∧ 0 < 𝐵 ) → 0 < 𝐵 )
10 6 7 8 9 mulgt0d ⊢ ( ( 𝜑 ∧ 0 < 𝐵 ) → 0 < ( 𝐴 · 𝐵 ) )
11 10 ex ⊢ ( 𝜑 → ( 0 < 𝐵 → 0 < ( 𝐴 · 𝐵 ) ) )
12 remul01 ⊢ ( 𝐴 ∈ ℝ → ( 𝐴 · 0 ) = 0 )
13 1 12 syl ⊢ ( 𝜑 → ( 𝐴 · 0 ) = 0 )
14 oveq2 ⊢ ( 𝐵 = 0 → ( 𝐴 · 𝐵 ) = ( 𝐴 · 0 ) )
15 14 eqeq1d ⊢ ( 𝐵 = 0 → ( ( 𝐴 · 𝐵 ) = 0 ↔ ( 𝐴 · 0 ) = 0 ) )
16 13 15 syl5ibrcom ⊢ ( 𝜑 → ( 𝐵 = 0 → ( 𝐴 · 𝐵 ) = 0 ) )
17 2 5 11 16 mulgt0con1dlem ⊢ ( 𝜑 → ( ( 𝐴 · 𝐵 ) < 0 → 𝐵 < 0 ) )
18 4 17 mpd ⊢ ( 𝜑 → 𝐵 < 0 )