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Description: There is a vector that is outside the span of another. (Contributed by NM, 25-Apr-2015)
| Ref | Expression | ||
|---|---|---|---|
| Hypotheses | dvh3dim.h | ⊢ 𝐻 = ( LHyp ‘ 𝐾 ) | |
| dvh3dim.u | ⊢ 𝑈 = ( ( DVecH ‘ 𝐾 ) ‘ 𝑊 ) | ||
| dvh3dim.v | ⊢ 𝑉 = ( Base ‘ 𝑈 ) | ||
| dvh3dim.n | ⊢ 𝑁 = ( LSpan ‘ 𝑈 ) | ||
| dvh3dim.k | ⊢ ( 𝜑 → ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ) | ||
| dvh3dim.x | ⊢ ( 𝜑 → 𝑋 ∈ 𝑉 ) | ||
| Assertion | dvh2dim | ⊢ ( 𝜑 → ∃ 𝑧 ∈ 𝑉 ¬ 𝑧 ∈ ( 𝑁 ‘ { 𝑋 } ) ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | dvh3dim.h | ⊢ 𝐻 = ( LHyp ‘ 𝐾 ) | |
| 2 | dvh3dim.u | ⊢ 𝑈 = ( ( DVecH ‘ 𝐾 ) ‘ 𝑊 ) | |
| 3 | dvh3dim.v | ⊢ 𝑉 = ( Base ‘ 𝑈 ) | |
| 4 | dvh3dim.n | ⊢ 𝑁 = ( LSpan ‘ 𝑈 ) | |
| 5 | dvh3dim.k | ⊢ ( 𝜑 → ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ) | |
| 6 | dvh3dim.x | ⊢ ( 𝜑 → 𝑋 ∈ 𝑉 ) | |
| 7 | eqid | ⊢ ( 0g ‘ 𝑈 ) = ( 0g ‘ 𝑈 ) | |
| 8 | 1 2 3 7 5 | dvh1dim | ⊢ ( 𝜑 → ∃ 𝑧 ∈ 𝑉 𝑧 ≠ ( 0g ‘ 𝑈 ) ) |
| 9 | 8 | adantr | ⊢ ( ( 𝜑 ∧ 𝑋 = ( 0g ‘ 𝑈 ) ) → ∃ 𝑧 ∈ 𝑉 𝑧 ≠ ( 0g ‘ 𝑈 ) ) |
| 10 | simpr | ⊢ ( ( 𝜑 ∧ 𝑋 = ( 0g ‘ 𝑈 ) ) → 𝑋 = ( 0g ‘ 𝑈 ) ) | |
| 11 | 10 | sneqd | ⊢ ( ( 𝜑 ∧ 𝑋 = ( 0g ‘ 𝑈 ) ) → { 𝑋 } = { ( 0g ‘ 𝑈 ) } ) |
| 12 | 11 | fveq2d | ⊢ ( ( 𝜑 ∧ 𝑋 = ( 0g ‘ 𝑈 ) ) → ( 𝑁 ‘ { 𝑋 } ) = ( 𝑁 ‘ { ( 0g ‘ 𝑈 ) } ) ) |
| 13 | 1 2 5 | dvhlmod | ⊢ ( 𝜑 → 𝑈 ∈ LMod ) |
| 14 | 7 4 | lspsn0 | ⊢ ( 𝑈 ∈ LMod → ( 𝑁 ‘ { ( 0g ‘ 𝑈 ) } ) = { ( 0g ‘ 𝑈 ) } ) |
| 15 | 13 14 | syl | ⊢ ( 𝜑 → ( 𝑁 ‘ { ( 0g ‘ 𝑈 ) } ) = { ( 0g ‘ 𝑈 ) } ) |
| 16 | 15 | adantr | ⊢ ( ( 𝜑 ∧ 𝑋 = ( 0g ‘ 𝑈 ) ) → ( 𝑁 ‘ { ( 0g ‘ 𝑈 ) } ) = { ( 0g ‘ 𝑈 ) } ) |
| 17 | 12 16 | eqtrd | ⊢ ( ( 𝜑 ∧ 𝑋 = ( 0g ‘ 𝑈 ) ) → ( 𝑁 ‘ { 𝑋 } ) = { ( 0g ‘ 𝑈 ) } ) |
| 18 | 17 | eleq2d | ⊢ ( ( 𝜑 ∧ 𝑋 = ( 0g ‘ 𝑈 ) ) → ( 𝑧 ∈ ( 𝑁 ‘ { 𝑋 } ) ↔ 𝑧 ∈ { ( 0g ‘ 𝑈 ) } ) ) |
| 19 | velsn | ⊢ ( 𝑧 ∈ { ( 0g ‘ 𝑈 ) } ↔ 𝑧 = ( 0g ‘ 𝑈 ) ) | |
| 20 | 18 19 | bitrdi | ⊢ ( ( 𝜑 ∧ 𝑋 = ( 0g ‘ 𝑈 ) ) → ( 𝑧 ∈ ( 𝑁 ‘ { 𝑋 } ) ↔ 𝑧 = ( 0g ‘ 𝑈 ) ) ) |
| 21 | 20 | necon3bbid | ⊢ ( ( 𝜑 ∧ 𝑋 = ( 0g ‘ 𝑈 ) ) → ( ¬ 𝑧 ∈ ( 𝑁 ‘ { 𝑋 } ) ↔ 𝑧 ≠ ( 0g ‘ 𝑈 ) ) ) |
| 22 | 21 | rexbidv | ⊢ ( ( 𝜑 ∧ 𝑋 = ( 0g ‘ 𝑈 ) ) → ( ∃ 𝑧 ∈ 𝑉 ¬ 𝑧 ∈ ( 𝑁 ‘ { 𝑋 } ) ↔ ∃ 𝑧 ∈ 𝑉 𝑧 ≠ ( 0g ‘ 𝑈 ) ) ) |
| 23 | 9 22 | mpbird | ⊢ ( ( 𝜑 ∧ 𝑋 = ( 0g ‘ 𝑈 ) ) → ∃ 𝑧 ∈ 𝑉 ¬ 𝑧 ∈ ( 𝑁 ‘ { 𝑋 } ) ) |
| 24 | 5 | adantr | ⊢ ( ( 𝜑 ∧ 𝑋 ≠ ( 0g ‘ 𝑈 ) ) → ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ) |
| 25 | 6 | adantr | ⊢ ( ( 𝜑 ∧ 𝑋 ≠ ( 0g ‘ 𝑈 ) ) → 𝑋 ∈ 𝑉 ) |
| 26 | simpr | ⊢ ( ( 𝜑 ∧ 𝑋 ≠ ( 0g ‘ 𝑈 ) ) → 𝑋 ≠ ( 0g ‘ 𝑈 ) ) | |
| 27 | 1 2 3 4 24 25 25 7 26 26 | dvhdimlem | ⊢ ( ( 𝜑 ∧ 𝑋 ≠ ( 0g ‘ 𝑈 ) ) → ∃ 𝑧 ∈ 𝑉 ¬ 𝑧 ∈ ( 𝑁 ‘ { 𝑋 , 𝑋 } ) ) |
| 28 | dfsn2 | ⊢ { 𝑋 } = { 𝑋 , 𝑋 } | |
| 29 | 28 | fveq2i | ⊢ ( 𝑁 ‘ { 𝑋 } ) = ( 𝑁 ‘ { 𝑋 , 𝑋 } ) |
| 30 | 29 | eleq2i | ⊢ ( 𝑧 ∈ ( 𝑁 ‘ { 𝑋 } ) ↔ 𝑧 ∈ ( 𝑁 ‘ { 𝑋 , 𝑋 } ) ) |
| 31 | 30 | notbii | ⊢ ( ¬ 𝑧 ∈ ( 𝑁 ‘ { 𝑋 } ) ↔ ¬ 𝑧 ∈ ( 𝑁 ‘ { 𝑋 , 𝑋 } ) ) |
| 32 | 31 | rexbii | ⊢ ( ∃ 𝑧 ∈ 𝑉 ¬ 𝑧 ∈ ( 𝑁 ‘ { 𝑋 } ) ↔ ∃ 𝑧 ∈ 𝑉 ¬ 𝑧 ∈ ( 𝑁 ‘ { 𝑋 , 𝑋 } ) ) |
| 33 | 27 32 | sylibr | ⊢ ( ( 𝜑 ∧ 𝑋 ≠ ( 0g ‘ 𝑈 ) ) → ∃ 𝑧 ∈ 𝑉 ¬ 𝑧 ∈ ( 𝑁 ‘ { 𝑋 } ) ) |
| 34 | 23 33 | pm2.61dane | ⊢ ( 𝜑 → ∃ 𝑧 ∈ 𝑉 ¬ 𝑧 ∈ ( 𝑁 ‘ { 𝑋 } ) ) |