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Description: Double orthocomplement for DVecH vector space. (Contributed by NM, 26-Jul-2014)
| Ref | Expression | ||
|---|---|---|---|
| Hypotheses | doch2val2.h | ⊢ 𝐻 = ( LHyp ‘ 𝐾 ) | |
| doch2val2.i | ⊢ 𝐼 = ( ( DIsoH ‘ 𝐾 ) ‘ 𝑊 ) | ||
| doch2val2.u | ⊢ 𝑈 = ( ( DVecH ‘ 𝐾 ) ‘ 𝑊 ) | ||
| doch2val2.v | ⊢ 𝑉 = ( Base ‘ 𝑈 ) | ||
| doch2val2.o | ⊢ ⊥ = ( ( ocH ‘ 𝐾 ) ‘ 𝑊 ) | ||
| doch2val2.k | ⊢ ( 𝜑 → ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ) | ||
| doch2val2.x | ⊢ ( 𝜑 → 𝑋 ⊆ 𝑉 ) | ||
| Assertion | doch2val2 | ⊢ ( 𝜑 → ( ⊥ ‘ ( ⊥ ‘ 𝑋 ) ) = ∩ { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | doch2val2.h | ⊢ 𝐻 = ( LHyp ‘ 𝐾 ) | |
| 2 | doch2val2.i | ⊢ 𝐼 = ( ( DIsoH ‘ 𝐾 ) ‘ 𝑊 ) | |
| 3 | doch2val2.u | ⊢ 𝑈 = ( ( DVecH ‘ 𝐾 ) ‘ 𝑊 ) | |
| 4 | doch2val2.v | ⊢ 𝑉 = ( Base ‘ 𝑈 ) | |
| 5 | doch2val2.o | ⊢ ⊥ = ( ( ocH ‘ 𝐾 ) ‘ 𝑊 ) | |
| 6 | doch2val2.k | ⊢ ( 𝜑 → ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ) | |
| 7 | doch2val2.x | ⊢ ( 𝜑 → 𝑋 ⊆ 𝑉 ) | |
| 8 | eqid | ⊢ ( oc ‘ 𝐾 ) = ( oc ‘ 𝐾 ) | |
| 9 | 8 1 2 3 4 5 | dochval2 | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ 𝑋 ⊆ 𝑉 ) → ( ⊥ ‘ 𝑋 ) = ( 𝐼 ‘ ( ( oc ‘ 𝐾 ) ‘ ( ◡ 𝐼 ‘ ∩ { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ) ) ) ) |
| 10 | 6 7 9 | syl2anc | ⊢ ( 𝜑 → ( ⊥ ‘ 𝑋 ) = ( 𝐼 ‘ ( ( oc ‘ 𝐾 ) ‘ ( ◡ 𝐼 ‘ ∩ { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ) ) ) ) |
| 11 | 10 | fveq2d | ⊢ ( 𝜑 → ( ⊥ ‘ ( ⊥ ‘ 𝑋 ) ) = ( ⊥ ‘ ( 𝐼 ‘ ( ( oc ‘ 𝐾 ) ‘ ( ◡ 𝐼 ‘ ∩ { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ) ) ) ) ) |
| 12 | 6 | simpld | ⊢ ( 𝜑 → 𝐾 ∈ HL ) |
| 13 | hlop | ⊢ ( 𝐾 ∈ HL → 𝐾 ∈ OP ) | |
| 14 | 12 13 | syl | ⊢ ( 𝜑 → 𝐾 ∈ OP ) |
| 15 | ssrab2 | ⊢ { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ⊆ ran 𝐼 | |
| 16 | 15 | a1i | ⊢ ( 𝜑 → { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ⊆ ran 𝐼 ) |
| 17 | 1 2 3 4 | dih1rn | ⊢ ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) → 𝑉 ∈ ran 𝐼 ) |
| 18 | 6 17 | syl | ⊢ ( 𝜑 → 𝑉 ∈ ran 𝐼 ) |
| 19 | sseq2 | ⊢ ( 𝑧 = 𝑉 → ( 𝑋 ⊆ 𝑧 ↔ 𝑋 ⊆ 𝑉 ) ) | |
| 20 | 19 | elrab | ⊢ ( 𝑉 ∈ { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ↔ ( 𝑉 ∈ ran 𝐼 ∧ 𝑋 ⊆ 𝑉 ) ) |
| 21 | 18 7 20 | sylanbrc | ⊢ ( 𝜑 → 𝑉 ∈ { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ) |
| 22 | 21 | ne0d | ⊢ ( 𝜑 → { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ≠ ∅ ) |
| 23 | 1 2 | dihintcl | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ ( { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ⊆ ran 𝐼 ∧ { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ≠ ∅ ) ) → ∩ { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ∈ ran 𝐼 ) |
| 24 | 6 16 22 23 | syl12anc | ⊢ ( 𝜑 → ∩ { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ∈ ran 𝐼 ) |
| 25 | eqid | ⊢ ( Base ‘ 𝐾 ) = ( Base ‘ 𝐾 ) | |
| 26 | 25 1 2 | dihcnvcl | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ ∩ { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ∈ ran 𝐼 ) → ( ◡ 𝐼 ‘ ∩ { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ) ∈ ( Base ‘ 𝐾 ) ) |
| 27 | 6 24 26 | syl2anc | ⊢ ( 𝜑 → ( ◡ 𝐼 ‘ ∩ { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ) ∈ ( Base ‘ 𝐾 ) ) |
| 28 | 25 8 | opoccl | ⊢ ( ( 𝐾 ∈ OP ∧ ( ◡ 𝐼 ‘ ∩ { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ) ∈ ( Base ‘ 𝐾 ) ) → ( ( oc ‘ 𝐾 ) ‘ ( ◡ 𝐼 ‘ ∩ { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ) ) ∈ ( Base ‘ 𝐾 ) ) |
| 29 | 14 27 28 | syl2anc | ⊢ ( 𝜑 → ( ( oc ‘ 𝐾 ) ‘ ( ◡ 𝐼 ‘ ∩ { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ) ) ∈ ( Base ‘ 𝐾 ) ) |
| 30 | 25 8 1 2 5 | dochvalr2 | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ ( ( oc ‘ 𝐾 ) ‘ ( ◡ 𝐼 ‘ ∩ { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ) ) ∈ ( Base ‘ 𝐾 ) ) → ( ⊥ ‘ ( 𝐼 ‘ ( ( oc ‘ 𝐾 ) ‘ ( ◡ 𝐼 ‘ ∩ { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ) ) ) ) = ( 𝐼 ‘ ( ( oc ‘ 𝐾 ) ‘ ( ( oc ‘ 𝐾 ) ‘ ( ◡ 𝐼 ‘ ∩ { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ) ) ) ) ) |
| 31 | 6 29 30 | syl2anc | ⊢ ( 𝜑 → ( ⊥ ‘ ( 𝐼 ‘ ( ( oc ‘ 𝐾 ) ‘ ( ◡ 𝐼 ‘ ∩ { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ) ) ) ) = ( 𝐼 ‘ ( ( oc ‘ 𝐾 ) ‘ ( ( oc ‘ 𝐾 ) ‘ ( ◡ 𝐼 ‘ ∩ { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ) ) ) ) ) |
| 32 | 25 8 | opococ | ⊢ ( ( 𝐾 ∈ OP ∧ ( ◡ 𝐼 ‘ ∩ { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ) ∈ ( Base ‘ 𝐾 ) ) → ( ( oc ‘ 𝐾 ) ‘ ( ( oc ‘ 𝐾 ) ‘ ( ◡ 𝐼 ‘ ∩ { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ) ) ) = ( ◡ 𝐼 ‘ ∩ { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ) ) |
| 33 | 14 27 32 | syl2anc | ⊢ ( 𝜑 → ( ( oc ‘ 𝐾 ) ‘ ( ( oc ‘ 𝐾 ) ‘ ( ◡ 𝐼 ‘ ∩ { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ) ) ) = ( ◡ 𝐼 ‘ ∩ { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ) ) |
| 34 | 33 | fveq2d | ⊢ ( 𝜑 → ( 𝐼 ‘ ( ( oc ‘ 𝐾 ) ‘ ( ( oc ‘ 𝐾 ) ‘ ( ◡ 𝐼 ‘ ∩ { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ) ) ) ) = ( 𝐼 ‘ ( ◡ 𝐼 ‘ ∩ { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ) ) ) |
| 35 | 1 2 | dihcnvid2 | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ ∩ { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ∈ ran 𝐼 ) → ( 𝐼 ‘ ( ◡ 𝐼 ‘ ∩ { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ) ) = ∩ { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ) |
| 36 | 6 24 35 | syl2anc | ⊢ ( 𝜑 → ( 𝐼 ‘ ( ◡ 𝐼 ‘ ∩ { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ) ) = ∩ { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ) |
| 37 | 34 36 | eqtrd | ⊢ ( 𝜑 → ( 𝐼 ‘ ( ( oc ‘ 𝐾 ) ‘ ( ( oc ‘ 𝐾 ) ‘ ( ◡ 𝐼 ‘ ∩ { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ) ) ) ) = ∩ { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ) |
| 38 | 11 31 37 | 3eqtrd | ⊢ ( 𝜑 → ( ⊥ ‘ ( ⊥ ‘ 𝑋 ) ) = ∩ { 𝑧 ∈ ran 𝐼 ∣ 𝑋 ⊆ 𝑧 } ) |