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Description: Move class substitution in and out of an operation. (Contributed by NM, 12-Nov-2005) (Revised by NM, 23-Aug-2018)
| Ref | Expression | ||
|---|---|---|---|
| Assertion | csbov123 | ⊢ ⦋ 𝐴 / 𝑥 ⦌ ( 𝐵 𝐹 𝐶 ) = ( ⦋ 𝐴 / 𝑥 ⦌ 𝐵 ⦋ 𝐴 / 𝑥 ⦌ 𝐹 ⦋ 𝐴 / 𝑥 ⦌ 𝐶 ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | csbeq1 | ⊢ ( 𝑦 = 𝐴 → ⦋ 𝑦 / 𝑥 ⦌ ( 𝐵 𝐹 𝐶 ) = ⦋ 𝐴 / 𝑥 ⦌ ( 𝐵 𝐹 𝐶 ) ) | |
| 2 | csbeq1 | ⊢ ( 𝑦 = 𝐴 → ⦋ 𝑦 / 𝑥 ⦌ 𝐹 = ⦋ 𝐴 / 𝑥 ⦌ 𝐹 ) | |
| 3 | csbeq1 | ⊢ ( 𝑦 = 𝐴 → ⦋ 𝑦 / 𝑥 ⦌ 𝐵 = ⦋ 𝐴 / 𝑥 ⦌ 𝐵 ) | |
| 4 | csbeq1 | ⊢ ( 𝑦 = 𝐴 → ⦋ 𝑦 / 𝑥 ⦌ 𝐶 = ⦋ 𝐴 / 𝑥 ⦌ 𝐶 ) | |
| 5 | 2 3 4 | oveq123d | ⊢ ( 𝑦 = 𝐴 → ( ⦋ 𝑦 / 𝑥 ⦌ 𝐵 ⦋ 𝑦 / 𝑥 ⦌ 𝐹 ⦋ 𝑦 / 𝑥 ⦌ 𝐶 ) = ( ⦋ 𝐴 / 𝑥 ⦌ 𝐵 ⦋ 𝐴 / 𝑥 ⦌ 𝐹 ⦋ 𝐴 / 𝑥 ⦌ 𝐶 ) ) |
| 6 | 1 5 | eqeq12d | ⊢ ( 𝑦 = 𝐴 → ( ⦋ 𝑦 / 𝑥 ⦌ ( 𝐵 𝐹 𝐶 ) = ( ⦋ 𝑦 / 𝑥 ⦌ 𝐵 ⦋ 𝑦 / 𝑥 ⦌ 𝐹 ⦋ 𝑦 / 𝑥 ⦌ 𝐶 ) ↔ ⦋ 𝐴 / 𝑥 ⦌ ( 𝐵 𝐹 𝐶 ) = ( ⦋ 𝐴 / 𝑥 ⦌ 𝐵 ⦋ 𝐴 / 𝑥 ⦌ 𝐹 ⦋ 𝐴 / 𝑥 ⦌ 𝐶 ) ) ) |
| 7 | vex | ⊢ 𝑦 ∈ V | |
| 8 | nfcsb1v | ⊢ Ⅎ 𝑥 ⦋ 𝑦 / 𝑥 ⦌ 𝐵 | |
| 9 | nfcsb1v | ⊢ Ⅎ 𝑥 ⦋ 𝑦 / 𝑥 ⦌ 𝐹 | |
| 10 | nfcsb1v | ⊢ Ⅎ 𝑥 ⦋ 𝑦 / 𝑥 ⦌ 𝐶 | |
| 11 | 8 9 10 | nfov | ⊢ Ⅎ 𝑥 ( ⦋ 𝑦 / 𝑥 ⦌ 𝐵 ⦋ 𝑦 / 𝑥 ⦌ 𝐹 ⦋ 𝑦 / 𝑥 ⦌ 𝐶 ) |
| 12 | csbeq1a | ⊢ ( 𝑥 = 𝑦 → 𝐹 = ⦋ 𝑦 / 𝑥 ⦌ 𝐹 ) | |
| 13 | csbeq1a | ⊢ ( 𝑥 = 𝑦 → 𝐵 = ⦋ 𝑦 / 𝑥 ⦌ 𝐵 ) | |
| 14 | csbeq1a | ⊢ ( 𝑥 = 𝑦 → 𝐶 = ⦋ 𝑦 / 𝑥 ⦌ 𝐶 ) | |
| 15 | 12 13 14 | oveq123d | ⊢ ( 𝑥 = 𝑦 → ( 𝐵 𝐹 𝐶 ) = ( ⦋ 𝑦 / 𝑥 ⦌ 𝐵 ⦋ 𝑦 / 𝑥 ⦌ 𝐹 ⦋ 𝑦 / 𝑥 ⦌ 𝐶 ) ) |
| 16 | 7 11 15 | csbief | ⊢ ⦋ 𝑦 / 𝑥 ⦌ ( 𝐵 𝐹 𝐶 ) = ( ⦋ 𝑦 / 𝑥 ⦌ 𝐵 ⦋ 𝑦 / 𝑥 ⦌ 𝐹 ⦋ 𝑦 / 𝑥 ⦌ 𝐶 ) |
| 17 | 6 16 | vtoclg | ⊢ ( 𝐴 ∈ V → ⦋ 𝐴 / 𝑥 ⦌ ( 𝐵 𝐹 𝐶 ) = ( ⦋ 𝐴 / 𝑥 ⦌ 𝐵 ⦋ 𝐴 / 𝑥 ⦌ 𝐹 ⦋ 𝐴 / 𝑥 ⦌ 𝐶 ) ) |
| 18 | csbprc | ⊢ ( ¬ 𝐴 ∈ V → ⦋ 𝐴 / 𝑥 ⦌ ( 𝐵 𝐹 𝐶 ) = ∅ ) | |
| 19 | df-ov | ⊢ ( ⦋ 𝐴 / 𝑥 ⦌ 𝐵 ⦋ 𝐴 / 𝑥 ⦌ 𝐹 ⦋ 𝐴 / 𝑥 ⦌ 𝐶 ) = ( ⦋ 𝐴 / 𝑥 ⦌ 𝐹 ‘ 〈 ⦋ 𝐴 / 𝑥 ⦌ 𝐵 , ⦋ 𝐴 / 𝑥 ⦌ 𝐶 〉 ) | |
| 20 | csbprc | ⊢ ( ¬ 𝐴 ∈ V → ⦋ 𝐴 / 𝑥 ⦌ 𝐹 = ∅ ) | |
| 21 | 20 | fveq1d | ⊢ ( ¬ 𝐴 ∈ V → ( ⦋ 𝐴 / 𝑥 ⦌ 𝐹 ‘ 〈 ⦋ 𝐴 / 𝑥 ⦌ 𝐵 , ⦋ 𝐴 / 𝑥 ⦌ 𝐶 〉 ) = ( ∅ ‘ 〈 ⦋ 𝐴 / 𝑥 ⦌ 𝐵 , ⦋ 𝐴 / 𝑥 ⦌ 𝐶 〉 ) ) |
| 22 | 0fv | ⊢ ( ∅ ‘ 〈 ⦋ 𝐴 / 𝑥 ⦌ 𝐵 , ⦋ 𝐴 / 𝑥 ⦌ 𝐶 〉 ) = ∅ | |
| 23 | 21 22 | eqtrdi | ⊢ ( ¬ 𝐴 ∈ V → ( ⦋ 𝐴 / 𝑥 ⦌ 𝐹 ‘ 〈 ⦋ 𝐴 / 𝑥 ⦌ 𝐵 , ⦋ 𝐴 / 𝑥 ⦌ 𝐶 〉 ) = ∅ ) |
| 24 | 19 23 | eqtr2id | ⊢ ( ¬ 𝐴 ∈ V → ∅ = ( ⦋ 𝐴 / 𝑥 ⦌ 𝐵 ⦋ 𝐴 / 𝑥 ⦌ 𝐹 ⦋ 𝐴 / 𝑥 ⦌ 𝐶 ) ) |
| 25 | 18 24 | eqtrd | ⊢ ( ¬ 𝐴 ∈ V → ⦋ 𝐴 / 𝑥 ⦌ ( 𝐵 𝐹 𝐶 ) = ( ⦋ 𝐴 / 𝑥 ⦌ 𝐵 ⦋ 𝐴 / 𝑥 ⦌ 𝐹 ⦋ 𝐴 / 𝑥 ⦌ 𝐶 ) ) |
| 26 | 17 25 | pm2.61i | ⊢ ⦋ 𝐴 / 𝑥 ⦌ ( 𝐵 𝐹 𝐶 ) = ( ⦋ 𝐴 / 𝑥 ⦌ 𝐵 ⦋ 𝐴 / 𝑥 ⦌ 𝐹 ⦋ 𝐴 / 𝑥 ⦌ 𝐶 ) |