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Metamath Proof Explorer

Theorem chsscon1

Description: Hilbert lattice contraposition law. (Contributed by NM, 21-Jun-2004) (New usage is discouraged.)

Ref Expression
Assertion chsscon1 ( ( 𝐴 ∈ Cℋ ∧ 𝐵 ∈ Cℋ ) → ( ( ⊥ ‘ 𝐴 ) ⊆ 𝐵 ↔ ( ⊥ ‘ 𝐵 ) ⊆ 𝐴 ) )

Proof

Step Hyp Ref Expression
1 choccl ⊢ ( 𝐴 ∈ Cℋ → ( ⊥ ‘ 𝐴 ) ∈ Cℋ )
2 chsscon3 ⊢ ( ( ( ⊥ ‘ 𝐴 ) ∈ Cℋ ∧ 𝐵 ∈ Cℋ ) → ( ( ⊥ ‘ 𝐴 ) ⊆ 𝐵 ↔ ( ⊥ ‘ 𝐵 ) ⊆ ( ⊥ ‘ ( ⊥ ‘ 𝐴 ) ) ) )
3 1 2 sylan ⊢ ( ( 𝐴 ∈ Cℋ ∧ 𝐵 ∈ Cℋ ) → ( ( ⊥ ‘ 𝐴 ) ⊆ 𝐵 ↔ ( ⊥ ‘ 𝐵 ) ⊆ ( ⊥ ‘ ( ⊥ ‘ 𝐴 ) ) ) )
4 ococ ⊢ ( 𝐴 ∈ Cℋ → ( ⊥ ‘ ( ⊥ ‘ 𝐴 ) ) = 𝐴 )
5 4 adantr ⊢ ( ( 𝐴 ∈ Cℋ ∧ 𝐵 ∈ Cℋ ) → ( ⊥ ‘ ( ⊥ ‘ 𝐴 ) ) = 𝐴 )
6 5 sseq2d ⊢ ( ( 𝐴 ∈ Cℋ ∧ 𝐵 ∈ Cℋ ) → ( ( ⊥ ‘ 𝐵 ) ⊆ ( ⊥ ‘ ( ⊥ ‘ 𝐴 ) ) ↔ ( ⊥ ‘ 𝐵 ) ⊆ 𝐴 ) )
7 3 6 bitrd ⊢ ( ( 𝐴 ∈ Cℋ ∧ 𝐵 ∈ Cℋ ) → ( ( ⊥ ‘ 𝐴 ) ⊆ 𝐵 ↔ ( ⊥ ‘ 𝐵 ) ⊆ 𝐴 ) )