This is an inofficial mirror of http://metamath.tirix.org for personal testing of a visualizer extension only.
Description: Technical lemma for bnj60 . This lemma may no longer be used or have become an indirect lemma of the theorem in question (i.e. a lemma of a lemma... of the theorem). (Contributed by Jonathan Ben-Naim, 3-Jun-2011) (New usage is discouraged.)
| Ref | Expression | ||
|---|---|---|---|
| Hypotheses | bnj1234.2 | ⊢ 𝑌 = 〈 𝑥 , ( 𝑓 ↾ pred ( 𝑥 , 𝐴 , 𝑅 ) ) 〉 | |
| bnj1234.3 | ⊢ 𝐶 = { 𝑓 ∣ ∃ 𝑑 ∈ 𝐵 ( 𝑓 Fn 𝑑 ∧ ∀ 𝑥 ∈ 𝑑 ( 𝑓 ‘ 𝑥 ) = ( 𝐺 ‘ 𝑌 ) ) } | ||
| bnj1234.4 | ⊢ 𝑍 = 〈 𝑥 , ( 𝑔 ↾ pred ( 𝑥 , 𝐴 , 𝑅 ) ) 〉 | ||
| bnj1234.5 | ⊢ 𝐷 = { 𝑔 ∣ ∃ 𝑑 ∈ 𝐵 ( 𝑔 Fn 𝑑 ∧ ∀ 𝑥 ∈ 𝑑 ( 𝑔 ‘ 𝑥 ) = ( 𝐺 ‘ 𝑍 ) ) } | ||
| Assertion | bnj1234 | ⊢ 𝐶 = 𝐷 |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | bnj1234.2 | ⊢ 𝑌 = 〈 𝑥 , ( 𝑓 ↾ pred ( 𝑥 , 𝐴 , 𝑅 ) ) 〉 | |
| 2 | bnj1234.3 | ⊢ 𝐶 = { 𝑓 ∣ ∃ 𝑑 ∈ 𝐵 ( 𝑓 Fn 𝑑 ∧ ∀ 𝑥 ∈ 𝑑 ( 𝑓 ‘ 𝑥 ) = ( 𝐺 ‘ 𝑌 ) ) } | |
| 3 | bnj1234.4 | ⊢ 𝑍 = 〈 𝑥 , ( 𝑔 ↾ pred ( 𝑥 , 𝐴 , 𝑅 ) ) 〉 | |
| 4 | bnj1234.5 | ⊢ 𝐷 = { 𝑔 ∣ ∃ 𝑑 ∈ 𝐵 ( 𝑔 Fn 𝑑 ∧ ∀ 𝑥 ∈ 𝑑 ( 𝑔 ‘ 𝑥 ) = ( 𝐺 ‘ 𝑍 ) ) } | |
| 5 | fneq1 | ⊢ ( 𝑓 = 𝑔 → ( 𝑓 Fn 𝑑 ↔ 𝑔 Fn 𝑑 ) ) | |
| 6 | fveq1 | ⊢ ( 𝑓 = 𝑔 → ( 𝑓 ‘ 𝑥 ) = ( 𝑔 ‘ 𝑥 ) ) | |
| 7 | reseq1 | ⊢ ( 𝑓 = 𝑔 → ( 𝑓 ↾ pred ( 𝑥 , 𝐴 , 𝑅 ) ) = ( 𝑔 ↾ pred ( 𝑥 , 𝐴 , 𝑅 ) ) ) | |
| 8 | 7 | opeq2d | ⊢ ( 𝑓 = 𝑔 → 〈 𝑥 , ( 𝑓 ↾ pred ( 𝑥 , 𝐴 , 𝑅 ) ) 〉 = 〈 𝑥 , ( 𝑔 ↾ pred ( 𝑥 , 𝐴 , 𝑅 ) ) 〉 ) |
| 9 | 8 1 3 | 3eqtr4g | ⊢ ( 𝑓 = 𝑔 → 𝑌 = 𝑍 ) |
| 10 | 9 | fveq2d | ⊢ ( 𝑓 = 𝑔 → ( 𝐺 ‘ 𝑌 ) = ( 𝐺 ‘ 𝑍 ) ) |
| 11 | 6 10 | eqeq12d | ⊢ ( 𝑓 = 𝑔 → ( ( 𝑓 ‘ 𝑥 ) = ( 𝐺 ‘ 𝑌 ) ↔ ( 𝑔 ‘ 𝑥 ) = ( 𝐺 ‘ 𝑍 ) ) ) |
| 12 | 11 | ralbidv | ⊢ ( 𝑓 = 𝑔 → ( ∀ 𝑥 ∈ 𝑑 ( 𝑓 ‘ 𝑥 ) = ( 𝐺 ‘ 𝑌 ) ↔ ∀ 𝑥 ∈ 𝑑 ( 𝑔 ‘ 𝑥 ) = ( 𝐺 ‘ 𝑍 ) ) ) |
| 13 | 5 12 | anbi12d | ⊢ ( 𝑓 = 𝑔 → ( ( 𝑓 Fn 𝑑 ∧ ∀ 𝑥 ∈ 𝑑 ( 𝑓 ‘ 𝑥 ) = ( 𝐺 ‘ 𝑌 ) ) ↔ ( 𝑔 Fn 𝑑 ∧ ∀ 𝑥 ∈ 𝑑 ( 𝑔 ‘ 𝑥 ) = ( 𝐺 ‘ 𝑍 ) ) ) ) |
| 14 | 13 | rexbidv | ⊢ ( 𝑓 = 𝑔 → ( ∃ 𝑑 ∈ 𝐵 ( 𝑓 Fn 𝑑 ∧ ∀ 𝑥 ∈ 𝑑 ( 𝑓 ‘ 𝑥 ) = ( 𝐺 ‘ 𝑌 ) ) ↔ ∃ 𝑑 ∈ 𝐵 ( 𝑔 Fn 𝑑 ∧ ∀ 𝑥 ∈ 𝑑 ( 𝑔 ‘ 𝑥 ) = ( 𝐺 ‘ 𝑍 ) ) ) ) |
| 15 | 14 | cbvabv | ⊢ { 𝑓 ∣ ∃ 𝑑 ∈ 𝐵 ( 𝑓 Fn 𝑑 ∧ ∀ 𝑥 ∈ 𝑑 ( 𝑓 ‘ 𝑥 ) = ( 𝐺 ‘ 𝑌 ) ) } = { 𝑔 ∣ ∃ 𝑑 ∈ 𝐵 ( 𝑔 Fn 𝑑 ∧ ∀ 𝑥 ∈ 𝑑 ( 𝑔 ‘ 𝑥 ) = ( 𝐺 ‘ 𝑍 ) ) } |
| 16 | 15 2 4 | 3eqtr4i | ⊢ 𝐶 = 𝐷 |