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Metamath Proof Explorer
Description: Equality deduction for the set-like predicate. (Contributed by Matthew
House, 10-Sep-2025)
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|
Ref |
Expression |
|
Hypotheses |
seeq12d.1 |
|
|
|
seeq12d.2 |
|
|
Assertion |
seeq12d |
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Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
seeq12d.1 |
|
| 2 |
|
seeq12d.2 |
|
| 3 |
|
seeq1 |
|
| 4 |
|
seeq2 |
|
| 5 |
3 4
|
sylan9bb |
|
| 6 |
1 2 5
|
syl2anc |
|