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Metamath Proof Explorer


Theorem eq0rdv

Description: Deduction for equality to the empty set. (Contributed by NM, 11-Jul-2014) Avoid ax-8 , df-clel . (Revised by GG, 6-Sep-2024)

Ref Expression
Hypothesis eq0rdv.1 φ ¬ x A
Assertion eq0rdv φ A =

Proof

Step Hyp Ref Expression
1 eq0rdv.1 φ ¬ x A
2 1 alrimiv φ x ¬ x A
3 eq0 A = x ¬ x A
4 2 3 sylibr φ A =