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Metamath Proof Explorer

Theorem animorlr

Description: Conjunction implies disjunction with one common formula (3/4). (Contributed by BJ, 4-Oct-2019)

		Ref	Expression
	Assertion	animorlr	$⊢ (φ \land ψ) \to (χ \lor φ)$

Step	Hyp	Ref	Expression
1		simpl	$⊢ (φ \land ψ) \to φ$
2	1	olcd	$⊢ (φ \land ψ) \to (χ \lor φ)$