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Metamath Proof Explorer

Theorem animorrl

Description: Conjunction implies disjunction with one common formula (4/4). (Contributed by BJ, 4-Oct-2019)

		Ref	Expression
	Assertion	animorrl	$⊢ (φ \land ψ) \to (ψ \lor χ)$

Step	Hyp	Ref	Expression
1		simpr	$⊢ (φ \land ψ) \to ψ$
2	1	orcd	$⊢ (φ \land ψ) \to (ψ \lor χ)$