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Metamath Proof Explorer

Theorem animorlr

Description: Conjunction implies disjunction with one common formula (3/4). (Contributed by BJ, 4-Oct-2019)

Ref Expression
Assertion animorlr ( ( 𝜑 ∧ 𝜓 ) → ( 𝜒 ∨ 𝜑 ) )

Proof

Step Hyp Ref Expression
1 simpl ⊢ ( ( 𝜑 ∧ 𝜓 ) → 𝜑 )
2 1 olcd ⊢ ( ( 𝜑 ∧ 𝜓 ) → ( 𝜒 ∨ 𝜑 ) )