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Metamath Proof Explorer

Theorem 3expb

Description: Exportation from triple to double conjunction. (Contributed by NM, 20-Aug-1995)

		Ref	Expression
	Hypothesis	3exp.1	$⊢ (φ \land ψ \land χ) \to θ$
	Assertion	3expb	$⊢ (φ \land (ψ \land χ)) \to θ$

Step	Hyp	Ref	Expression
1		3exp.1	$⊢ (φ \land ψ \land χ) \to θ$
2	1	3exp	$⊢ φ \to (ψ \to (χ \to θ))$
3	2	imp32	$⊢ (φ \land (ψ \land χ)) \to θ$