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Metamath Proof Explorer

Theorem 3exp

Description: Exportation inference. (Contributed by NM, 30-May-1994) (Proof shortened by Wolf Lammen, 22-Jun-2022)

		Ref	Expression
	Hypothesis	3exp.1	$⊢ (φ \land ψ \land χ) \to θ$
	Assertion	3exp	$⊢ φ \to (ψ \to (χ \to θ))$

Step	Hyp	Ref	Expression
1		3exp.1	$⊢ (φ \land ψ \land χ) \to θ$
2	1	3expa	$⊢ ((φ \land ψ) \land χ) \to θ$
3	2	exp31	$⊢ φ \to (ψ \to (χ \to θ))$