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Metamath Proof Explorer


Theorem 3exp

Description: Exportation inference. (Contributed by NM, 30-May-1994) (Proof shortened by Wolf Lammen, 22-Jun-2022)

Ref Expression
Hypothesis 3exp.1 ( ( 𝜑𝜓𝜒 ) → 𝜃 )
Assertion 3exp ( 𝜑 → ( 𝜓 → ( 𝜒𝜃 ) ) )

Proof

Step Hyp Ref Expression
1 3exp.1 ( ( 𝜑𝜓𝜒 ) → 𝜃 )
2 1 3expa ( ( ( 𝜑𝜓 ) ∧ 𝜒 ) → 𝜃 )
3 2 exp31 ( 𝜑 → ( 𝜓 → ( 𝜒𝜃 ) ) )