This is an inofficial mirror of http://metamath.tirix.org for personal testing of a visualizer extension only.

Metamath Proof Explorer


Theorem ofeq

Description: Equality theorem for function operation. (Contributed by Mario Carneiro, 20-Jul-2014)

Ref Expression
Assertion ofeq
|- ( R = S -> oF R = oF S )

Proof

Step Hyp Ref Expression
1 id
 |-  ( R = S -> R = S )
2 1 ofeqd
 |-  ( R = S -> oF R = oF S )