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Metamath Proof Explorer

Theorem neggcd

Description: Negating one operand of the gcd operator does not alter the result. (Contributed by Paul Chapman, 22-Jun-2011)

Ref Expression
Assertion neggcd 
|- ( ( M e. ZZ /\ N e. ZZ ) -> ( -u M gcd N ) = ( M gcd N ) )

Proof

Step Hyp Ref Expression
1 gcdneg 
 |-  ( ( N e. ZZ /\ M e. ZZ ) -> ( N gcd -u M ) = ( N gcd M ) )
2 1 ancoms 
 |-  ( ( M e. ZZ /\ N e. ZZ ) -> ( N gcd -u M ) = ( N gcd M ) )
3 znegcl 
 |-  ( M e. ZZ -> -u M e. ZZ )
4 gcdcom 
 |-  ( ( -u M e. ZZ /\ N e. ZZ ) -> ( -u M gcd N ) = ( N gcd -u M ) )
5 3 4 sylan 
 |-  ( ( M e. ZZ /\ N e. ZZ ) -> ( -u M gcd N ) = ( N gcd -u M ) )
6 gcdcom 
 |-  ( ( M e. ZZ /\ N e. ZZ ) -> ( M gcd N ) = ( N gcd M ) )
7 2 5 6 3eqtr4d 
 |-  ( ( M e. ZZ /\ N e. ZZ ) -> ( -u M gcd N ) = ( M gcd N ) )