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Description: A subring of a zero ring is a zero ring. (Contributed by Thierry Arnoux, 5-Feb-2025)
| Ref | Expression | ||
|---|---|---|---|
| Hypotheses | 0ringsubrg.1 | |- B = ( Base ` R ) |
|
| 0ringsubrg.2 | |- ( ph -> R e. Ring ) |
||
| 0ringsubrg.3 | |- ( ph -> ( # ` B ) = 1 ) |
||
| 0ringsubrg.4 | |- ( ph -> S e. ( SubRing ` R ) ) |
||
| Assertion | 0ringsubrg | |- ( ph -> ( # ` S ) = 1 ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | 0ringsubrg.1 | |- B = ( Base ` R ) |
|
| 2 | 0ringsubrg.2 | |- ( ph -> R e. Ring ) |
|
| 3 | 0ringsubrg.3 | |- ( ph -> ( # ` B ) = 1 ) |
|
| 4 | 0ringsubrg.4 | |- ( ph -> S e. ( SubRing ` R ) ) |
|
| 5 | 1 | subrgss | |- ( S e. ( SubRing ` R ) -> S C_ B ) |
| 6 | 4 5 | syl | |- ( ph -> S C_ B ) |
| 7 | eqid | |- ( 0g ` R ) = ( 0g ` R ) |
|
| 8 | 1 7 | 0ring | |- ( ( R e. Ring /\ ( # ` B ) = 1 ) -> B = { ( 0g ` R ) } ) |
| 9 | 2 3 8 | syl2anc | |- ( ph -> B = { ( 0g ` R ) } ) |
| 10 | 6 9 | sseqtrd | |- ( ph -> S C_ { ( 0g ` R ) } ) |
| 11 | sssn | |- ( S C_ { ( 0g ` R ) } <-> ( S = (/) \/ S = { ( 0g ` R ) } ) ) |
|
| 12 | 10 11 | sylib | |- ( ph -> ( S = (/) \/ S = { ( 0g ` R ) } ) ) |
| 13 | eqid | |- ( 1r ` R ) = ( 1r ` R ) |
|
| 14 | 13 | subrg1cl | |- ( S e. ( SubRing ` R ) -> ( 1r ` R ) e. S ) |
| 15 | 4 14 | syl | |- ( ph -> ( 1r ` R ) e. S ) |
| 16 | n0i | |- ( ( 1r ` R ) e. S -> -. S = (/) ) |
|
| 17 | 15 16 | syl | |- ( ph -> -. S = (/) ) |
| 18 | 12 17 | orcnd | |- ( ph -> S = { ( 0g ` R ) } ) |
| 19 | 18 | fveq2d | |- ( ph -> ( # ` S ) = ( # ` { ( 0g ` R ) } ) ) |
| 20 | fvex | |- ( 0g ` R ) e. _V |
|
| 21 | hashsng | |- ( ( 0g ` R ) e. _V -> ( # ` { ( 0g ` R ) } ) = 1 ) |
|
| 22 | 20 21 | ax-mp | |- ( # ` { ( 0g ` R ) } ) = 1 |
| 23 | 19 22 | eqtrdi | |- ( ph -> ( # ` S ) = 1 ) |