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Description: Absorption into a composition by joining with trace. (Contributed by NM, 22-Jul-2013)
| Ref | Expression | ||
|---|---|---|---|
| Hypotheses | trlcoabs.l | ⊢ ≤ = ( le ‘ 𝐾 ) | |
| trlcoabs.j | ⊢ ∨ = ( join ‘ 𝐾 ) | ||
| trlcoabs.a | ⊢ 𝐴 = ( Atoms ‘ 𝐾 ) | ||
| trlcoabs.h | ⊢ 𝐻 = ( LHyp ‘ 𝐾 ) | ||
| trlcoabs.t | ⊢ 𝑇 = ( ( LTrn ‘ 𝐾 ) ‘ 𝑊 ) | ||
| trlcoabs.r | ⊢ 𝑅 = ( ( trL ‘ 𝐾 ) ‘ 𝑊 ) | ||
| Assertion | trlcoabs | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ ( 𝐹 ∈ 𝑇 ∧ 𝐺 ∈ 𝑇 ) ∧ ( 𝑃 ∈ 𝐴 ∧ ¬ 𝑃 ≤ 𝑊 ) ) → ( ( ( 𝐹 ∘ 𝐺 ) ‘ 𝑃 ) ∨ ( 𝑅 ‘ 𝐹 ) ) = ( ( 𝐺 ‘ 𝑃 ) ∨ ( 𝑅 ‘ 𝐹 ) ) ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | trlcoabs.l | ⊢ ≤ = ( le ‘ 𝐾 ) | |
| 2 | trlcoabs.j | ⊢ ∨ = ( join ‘ 𝐾 ) | |
| 3 | trlcoabs.a | ⊢ 𝐴 = ( Atoms ‘ 𝐾 ) | |
| 4 | trlcoabs.h | ⊢ 𝐻 = ( LHyp ‘ 𝐾 ) | |
| 5 | trlcoabs.t | ⊢ 𝑇 = ( ( LTrn ‘ 𝐾 ) ‘ 𝑊 ) | |
| 6 | trlcoabs.r | ⊢ 𝑅 = ( ( trL ‘ 𝐾 ) ‘ 𝑊 ) | |
| 7 | 1 3 4 5 | ltrncoval | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ ( 𝐹 ∈ 𝑇 ∧ 𝐺 ∈ 𝑇 ) ∧ 𝑃 ∈ 𝐴 ) → ( ( 𝐹 ∘ 𝐺 ) ‘ 𝑃 ) = ( 𝐹 ‘ ( 𝐺 ‘ 𝑃 ) ) ) |
| 8 | 7 | 3adant3r | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ ( 𝐹 ∈ 𝑇 ∧ 𝐺 ∈ 𝑇 ) ∧ ( 𝑃 ∈ 𝐴 ∧ ¬ 𝑃 ≤ 𝑊 ) ) → ( ( 𝐹 ∘ 𝐺 ) ‘ 𝑃 ) = ( 𝐹 ‘ ( 𝐺 ‘ 𝑃 ) ) ) |
| 9 | 8 | oveq1d | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ ( 𝐹 ∈ 𝑇 ∧ 𝐺 ∈ 𝑇 ) ∧ ( 𝑃 ∈ 𝐴 ∧ ¬ 𝑃 ≤ 𝑊 ) ) → ( ( ( 𝐹 ∘ 𝐺 ) ‘ 𝑃 ) ∨ ( 𝑅 ‘ 𝐹 ) ) = ( ( 𝐹 ‘ ( 𝐺 ‘ 𝑃 ) ) ∨ ( 𝑅 ‘ 𝐹 ) ) ) |
| 10 | simp1 | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ ( 𝐹 ∈ 𝑇 ∧ 𝐺 ∈ 𝑇 ) ∧ ( 𝑃 ∈ 𝐴 ∧ ¬ 𝑃 ≤ 𝑊 ) ) → ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ) | |
| 11 | simp2l | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ ( 𝐹 ∈ 𝑇 ∧ 𝐺 ∈ 𝑇 ) ∧ ( 𝑃 ∈ 𝐴 ∧ ¬ 𝑃 ≤ 𝑊 ) ) → 𝐹 ∈ 𝑇 ) | |
| 12 | 1 3 4 5 | ltrnel | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ 𝐺 ∈ 𝑇 ∧ ( 𝑃 ∈ 𝐴 ∧ ¬ 𝑃 ≤ 𝑊 ) ) → ( ( 𝐺 ‘ 𝑃 ) ∈ 𝐴 ∧ ¬ ( 𝐺 ‘ 𝑃 ) ≤ 𝑊 ) ) |
| 13 | 12 | 3adant2l | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ ( 𝐹 ∈ 𝑇 ∧ 𝐺 ∈ 𝑇 ) ∧ ( 𝑃 ∈ 𝐴 ∧ ¬ 𝑃 ≤ 𝑊 ) ) → ( ( 𝐺 ‘ 𝑃 ) ∈ 𝐴 ∧ ¬ ( 𝐺 ‘ 𝑃 ) ≤ 𝑊 ) ) |
| 14 | 1 2 3 4 5 6 | trljat3 | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ 𝐹 ∈ 𝑇 ∧ ( ( 𝐺 ‘ 𝑃 ) ∈ 𝐴 ∧ ¬ ( 𝐺 ‘ 𝑃 ) ≤ 𝑊 ) ) → ( ( 𝐺 ‘ 𝑃 ) ∨ ( 𝑅 ‘ 𝐹 ) ) = ( ( 𝐹 ‘ ( 𝐺 ‘ 𝑃 ) ) ∨ ( 𝑅 ‘ 𝐹 ) ) ) |
| 15 | 10 11 13 14 | syl3anc | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ ( 𝐹 ∈ 𝑇 ∧ 𝐺 ∈ 𝑇 ) ∧ ( 𝑃 ∈ 𝐴 ∧ ¬ 𝑃 ≤ 𝑊 ) ) → ( ( 𝐺 ‘ 𝑃 ) ∨ ( 𝑅 ‘ 𝐹 ) ) = ( ( 𝐹 ‘ ( 𝐺 ‘ 𝑃 ) ) ∨ ( 𝑅 ‘ 𝐹 ) ) ) |
| 16 | 9 15 | eqtr4d | ⊢ ( ( ( 𝐾 ∈ HL ∧ 𝑊 ∈ 𝐻 ) ∧ ( 𝐹 ∈ 𝑇 ∧ 𝐺 ∈ 𝑇 ) ∧ ( 𝑃 ∈ 𝐴 ∧ ¬ 𝑃 ≤ 𝑊 ) ) → ( ( ( 𝐹 ∘ 𝐺 ) ‘ 𝑃 ) ∨ ( 𝑅 ‘ 𝐹 ) ) = ( ( 𝐺 ‘ 𝑃 ) ∨ ( 𝑅 ‘ 𝐹 ) ) ) |