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Metamath Proof Explorer

Theorem sylan9req

Description: An equality transitivity deduction. (Contributed by NM, 23-Jun-2007)

Ref Expression
Hypotheses sylan9req.1 ⊢ ( 𝜑 → 𝐵 = 𝐴 )
sylan9req.2 ⊢ ( 𝜓 → 𝐵 = 𝐶 )
Assertion sylan9req ( ( 𝜑 ∧ 𝜓 ) → 𝐴 = 𝐶 )

Proof

Step Hyp Ref Expression
1 sylan9req.1 ⊢ ( 𝜑 → 𝐵 = 𝐴 )
2 sylan9req.2 ⊢ ( 𝜓 → 𝐵 = 𝐶 )
3 1 eqcomd ⊢ ( 𝜑 → 𝐴 = 𝐵 )
4 3 2 sylan9eq ⊢ ( ( 𝜑 ∧ 𝜓 ) → 𝐴 = 𝐶 )