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Description: Value of the subword extractor as function with domain. (Contributed by Alexander van der Vekens, 28-Mar-2018) (Proof shortened by AV, 2-May-2020)
| Ref | Expression | ||
|---|---|---|---|
| Assertion | swrdvalfn | ⊢ ( ( 𝑆 ∈ Word 𝑉 ∧ 𝐹 ∈ ( 0 ... 𝐿 ) ∧ 𝐿 ∈ ( 0 ... ( ♯ ‘ 𝑆 ) ) ) → ( 𝑆 substr 〈 𝐹 , 𝐿 〉 ) Fn ( 0 ..^ ( 𝐿 − 𝐹 ) ) ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | swrdf | ⊢ ( ( 𝑆 ∈ Word 𝑉 ∧ 𝐹 ∈ ( 0 ... 𝐿 ) ∧ 𝐿 ∈ ( 0 ... ( ♯ ‘ 𝑆 ) ) ) → ( 𝑆 substr 〈 𝐹 , 𝐿 〉 ) : ( 0 ..^ ( 𝐿 − 𝐹 ) ) ⟶ 𝑉 ) | |
| 2 | 1 | ffnd | ⊢ ( ( 𝑆 ∈ Word 𝑉 ∧ 𝐹 ∈ ( 0 ... 𝐿 ) ∧ 𝐿 ∈ ( 0 ... ( ♯ ‘ 𝑆 ) ) ) → ( 𝑆 substr 〈 𝐹 , 𝐿 〉 ) Fn ( 0 ..^ ( 𝐿 − 𝐹 ) ) ) |