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Metamath Proof Explorer


Theorem notnotd

Description: Deduction associated with notnot and notnoti . (Contributed by Jarvin Udandy, 2-Sep-2016) Avoid biconditional. (Revised by Wolf Lammen, 27-Mar-2021)

Ref Expression
Hypothesis notnotd.1 ( 𝜑𝜓 )
Assertion notnotd ( 𝜑 → ¬ ¬ 𝜓 )

Proof

Step Hyp Ref Expression
1 notnotd.1 ( 𝜑𝜓 )
2 notnot ( 𝜓 → ¬ ¬ 𝜓 )
3 1 2 syl ( 𝜑 → ¬ ¬ 𝜓 )