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Description: Detach truth from conjunction in biconditional. (Contributed by Glauco Siliprandi, 3-Mar-2021)
| Ref | Expression | ||
|---|---|---|---|
| Hypotheses | mpbirand.1 | ⊢ ( 𝜑 → 𝜒 ) | |
| mpbirand.2 | ⊢ ( 𝜑 → ( 𝜓 ↔ ( 𝜒 ∧ 𝜃 ) ) ) | ||
| Assertion | mpbirand | ⊢ ( 𝜑 → ( 𝜓 ↔ 𝜃 ) ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | mpbirand.1 | ⊢ ( 𝜑 → 𝜒 ) | |
| 2 | mpbirand.2 | ⊢ ( 𝜑 → ( 𝜓 ↔ ( 𝜒 ∧ 𝜃 ) ) ) | |
| 3 | 1 | biantrurd | ⊢ ( 𝜑 → ( 𝜃 ↔ ( 𝜒 ∧ 𝜃 ) ) ) |
| 4 | 2 3 | bitr4d | ⊢ ( 𝜑 → ( 𝜓 ↔ 𝜃 ) ) |