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Description: Detach truth from conjunction in biconditional. Deduction form. (Contributed by Peter Mazsa, 24-Sep-2022)
| Ref | Expression | ||
|---|---|---|---|
| Hypotheses | mpbiran2d.1 | ⊢ ( 𝜑 → 𝜃 ) | |
| mpbiran2d.2 | ⊢ ( 𝜑 → ( 𝜓 ↔ ( 𝜒 ∧ 𝜃 ) ) ) | ||
| Assertion | mpbiran2d | ⊢ ( 𝜑 → ( 𝜓 ↔ 𝜒 ) ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | mpbiran2d.1 | ⊢ ( 𝜑 → 𝜃 ) | |
| 2 | mpbiran2d.2 | ⊢ ( 𝜑 → ( 𝜓 ↔ ( 𝜒 ∧ 𝜃 ) ) ) | |
| 3 | 2 | biancomd | ⊢ ( 𝜑 → ( 𝜓 ↔ ( 𝜃 ∧ 𝜒 ) ) ) |
| 4 | 1 3 | mpbirand | ⊢ ( 𝜑 → ( 𝜓 ↔ 𝜒 ) ) |