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Description: Step 28 of Meredith's proof of Lukasiewicz axioms from his sole axiom. (Contributed by NM, 14-Dec-2002) (Proof modification is discouraged.) (New usage is discouraged.)
| Ref | Expression | ||
|---|---|---|---|
| Assertion | merlem12 | ⊢ ( ( ( 𝜃 → ( ¬ ¬ 𝜒 → 𝜒 ) ) → 𝜑 ) → 𝜑 ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | merlem5 | ⊢ ( ( 𝜒 → 𝜒 ) → ( ¬ ¬ 𝜒 → 𝜒 ) ) | |
| 2 | merlem2 | ⊢ ( ( ( 𝜒 → 𝜒 ) → ( ¬ ¬ 𝜒 → 𝜒 ) ) → ( 𝜃 → ( ¬ ¬ 𝜒 → 𝜒 ) ) ) | |
| 3 | 1 2 | ax-mp | ⊢ ( 𝜃 → ( ¬ ¬ 𝜒 → 𝜒 ) ) |
| 4 | merlem4 | ⊢ ( ( 𝜃 → ( ¬ ¬ 𝜒 → 𝜒 ) ) → ( ( ( 𝜃 → ( ¬ ¬ 𝜒 → 𝜒 ) ) → 𝜑 ) → ( ( ( 𝜃 → ( ¬ ¬ 𝜒 → 𝜒 ) ) → 𝜑 ) → 𝜑 ) ) ) | |
| 5 | 3 4 | ax-mp | ⊢ ( ( ( 𝜃 → ( ¬ ¬ 𝜒 → 𝜒 ) ) → 𝜑 ) → ( ( ( 𝜃 → ( ¬ ¬ 𝜒 → 𝜒 ) ) → 𝜑 ) → 𝜑 ) ) |
| 6 | merlem11 | ⊢ ( ( ( ( 𝜃 → ( ¬ ¬ 𝜒 → 𝜒 ) ) → 𝜑 ) → ( ( ( 𝜃 → ( ¬ ¬ 𝜒 → 𝜒 ) ) → 𝜑 ) → 𝜑 ) ) → ( ( ( 𝜃 → ( ¬ ¬ 𝜒 → 𝜒 ) ) → 𝜑 ) → 𝜑 ) ) | |
| 7 | 5 6 | ax-mp | ⊢ ( ( ( 𝜃 → ( ¬ ¬ 𝜒 → 𝜒 ) ) → 𝜑 ) → 𝜑 ) |