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Description: Create an atom under an element covered by the lattice unity. Part of proof of Lemma B in Crawley p. 112. ( 1cvrat analog.) (Contributed by NM, 11-Jan-2015)
| Ref | Expression | ||
|---|---|---|---|
| Hypotheses | l1cvat.v | ⊢ 𝑉 = ( Base ‘ 𝑊 ) | |
| l1cvat.s | ⊢ 𝑆 = ( LSubSp ‘ 𝑊 ) | ||
| l1cvat.p | ⊢ ⊕ = ( LSSum ‘ 𝑊 ) | ||
| l1cvat.a | ⊢ 𝐴 = ( LSAtoms ‘ 𝑊 ) | ||
| l1cvat.c | ⊢ 𝐶 = ( ⋖L ‘ 𝑊 ) | ||
| l1cvat.w | ⊢ ( 𝜑 → 𝑊 ∈ LVec ) | ||
| l1cvat.u | ⊢ ( 𝜑 → 𝑈 ∈ 𝑆 ) | ||
| l1cvat.q | ⊢ ( 𝜑 → 𝑄 ∈ 𝐴 ) | ||
| l1cvat.r | ⊢ ( 𝜑 → 𝑅 ∈ 𝐴 ) | ||
| l1cvat.n | ⊢ ( 𝜑 → 𝑄 ≠ 𝑅 ) | ||
| l1cvat.l | ⊢ ( 𝜑 → 𝑈 𝐶 𝑉 ) | ||
| l1cvat.m | ⊢ ( 𝜑 → ¬ 𝑄 ⊆ 𝑈 ) | ||
| Assertion | l1cvat | ⊢ ( 𝜑 → ( ( 𝑄 ⊕ 𝑅 ) ∩ 𝑈 ) ∈ 𝐴 ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | l1cvat.v | ⊢ 𝑉 = ( Base ‘ 𝑊 ) | |
| 2 | l1cvat.s | ⊢ 𝑆 = ( LSubSp ‘ 𝑊 ) | |
| 3 | l1cvat.p | ⊢ ⊕ = ( LSSum ‘ 𝑊 ) | |
| 4 | l1cvat.a | ⊢ 𝐴 = ( LSAtoms ‘ 𝑊 ) | |
| 5 | l1cvat.c | ⊢ 𝐶 = ( ⋖L ‘ 𝑊 ) | |
| 6 | l1cvat.w | ⊢ ( 𝜑 → 𝑊 ∈ LVec ) | |
| 7 | l1cvat.u | ⊢ ( 𝜑 → 𝑈 ∈ 𝑆 ) | |
| 8 | l1cvat.q | ⊢ ( 𝜑 → 𝑄 ∈ 𝐴 ) | |
| 9 | l1cvat.r | ⊢ ( 𝜑 → 𝑅 ∈ 𝐴 ) | |
| 10 | l1cvat.n | ⊢ ( 𝜑 → 𝑄 ≠ 𝑅 ) | |
| 11 | l1cvat.l | ⊢ ( 𝜑 → 𝑈 𝐶 𝑉 ) | |
| 12 | l1cvat.m | ⊢ ( 𝜑 → ¬ 𝑄 ⊆ 𝑈 ) | |
| 13 | lveclmod | ⊢ ( 𝑊 ∈ LVec → 𝑊 ∈ LMod ) | |
| 14 | 6 13 | syl | ⊢ ( 𝜑 → 𝑊 ∈ LMod ) |
| 15 | lmodabl | ⊢ ( 𝑊 ∈ LMod → 𝑊 ∈ Abel ) | |
| 16 | 14 15 | syl | ⊢ ( 𝜑 → 𝑊 ∈ Abel ) |
| 17 | 2 | lsssssubg | ⊢ ( 𝑊 ∈ LMod → 𝑆 ⊆ ( SubGrp ‘ 𝑊 ) ) |
| 18 | 14 17 | syl | ⊢ ( 𝜑 → 𝑆 ⊆ ( SubGrp ‘ 𝑊 ) ) |
| 19 | 2 4 14 8 | lsatlssel | ⊢ ( 𝜑 → 𝑄 ∈ 𝑆 ) |
| 20 | 18 19 | sseldd | ⊢ ( 𝜑 → 𝑄 ∈ ( SubGrp ‘ 𝑊 ) ) |
| 21 | 2 4 14 9 | lsatlssel | ⊢ ( 𝜑 → 𝑅 ∈ 𝑆 ) |
| 22 | 18 21 | sseldd | ⊢ ( 𝜑 → 𝑅 ∈ ( SubGrp ‘ 𝑊 ) ) |
| 23 | 3 | lsmcom | ⊢ ( ( 𝑊 ∈ Abel ∧ 𝑄 ∈ ( SubGrp ‘ 𝑊 ) ∧ 𝑅 ∈ ( SubGrp ‘ 𝑊 ) ) → ( 𝑄 ⊕ 𝑅 ) = ( 𝑅 ⊕ 𝑄 ) ) |
| 24 | 16 20 22 23 | syl3anc | ⊢ ( 𝜑 → ( 𝑄 ⊕ 𝑅 ) = ( 𝑅 ⊕ 𝑄 ) ) |
| 25 | 24 | ineq1d | ⊢ ( 𝜑 → ( ( 𝑄 ⊕ 𝑅 ) ∩ 𝑈 ) = ( ( 𝑅 ⊕ 𝑄 ) ∩ 𝑈 ) ) |
| 26 | incom | ⊢ ( ( 𝑅 ⊕ 𝑄 ) ∩ 𝑈 ) = ( 𝑈 ∩ ( 𝑅 ⊕ 𝑄 ) ) | |
| 27 | 25 26 | eqtrdi | ⊢ ( 𝜑 → ( ( 𝑄 ⊕ 𝑅 ) ∩ 𝑈 ) = ( 𝑈 ∩ ( 𝑅 ⊕ 𝑄 ) ) ) |
| 28 | 10 | necomd | ⊢ ( 𝜑 → 𝑅 ≠ 𝑄 ) |
| 29 | 1 4 14 9 | lsatssv | ⊢ ( 𝜑 → 𝑅 ⊆ 𝑉 ) |
| 30 | 1 2 3 4 5 6 7 8 11 12 | l1cvpat | ⊢ ( 𝜑 → ( 𝑈 ⊕ 𝑄 ) = 𝑉 ) |
| 31 | 29 30 | sseqtrrd | ⊢ ( 𝜑 → 𝑅 ⊆ ( 𝑈 ⊕ 𝑄 ) ) |
| 32 | 2 3 4 6 7 9 8 28 12 31 | lsatcvat3 | ⊢ ( 𝜑 → ( 𝑈 ∩ ( 𝑅 ⊕ 𝑄 ) ) ∈ 𝐴 ) |
| 33 | 27 32 | eqeltrd | ⊢ ( 𝜑 → ( ( 𝑄 ⊕ 𝑅 ) ∩ 𝑈 ) ∈ 𝐴 ) |