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Description: Property of a disjoint collection: if B ( x ) and B ( Y ) = D have a common element Z , then x = Y . (Contributed by Thierry Arnoux, 6-Apr-2017)
| Ref | Expression | ||
|---|---|---|---|
| Hypotheses | disjif2.1 | ⊢ Ⅎ 𝑥 𝐴 | |
| disjif2.2 | ⊢ Ⅎ 𝑥 𝐶 | ||
| disjif2.3 | ⊢ ( 𝑥 = 𝑌 → 𝐵 = 𝐶 ) | ||
| Assertion | disjif2 | ⊢ ( ( Disj 𝑥 ∈ 𝐴 𝐵 ∧ ( 𝑥 ∈ 𝐴 ∧ 𝑌 ∈ 𝐴 ) ∧ ( 𝑍 ∈ 𝐵 ∧ 𝑍 ∈ 𝐶 ) ) → 𝑥 = 𝑌 ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | disjif2.1 | ⊢ Ⅎ 𝑥 𝐴 | |
| 2 | disjif2.2 | ⊢ Ⅎ 𝑥 𝐶 | |
| 3 | disjif2.3 | ⊢ ( 𝑥 = 𝑌 → 𝐵 = 𝐶 ) | |
| 4 | inelcm | ⊢ ( ( 𝑍 ∈ 𝐵 ∧ 𝑍 ∈ 𝐶 ) → ( 𝐵 ∩ 𝐶 ) ≠ ∅ ) | |
| 5 | 1 | disjorsf | ⊢ ( Disj 𝑥 ∈ 𝐴 𝐵 ↔ ∀ 𝑦 ∈ 𝐴 ∀ 𝑧 ∈ 𝐴 ( 𝑦 = 𝑧 ∨ ( ⦋ 𝑦 / 𝑥 ⦌ 𝐵 ∩ ⦋ 𝑧 / 𝑥 ⦌ 𝐵 ) = ∅ ) ) |
| 6 | equequ1 | ⊢ ( 𝑦 = 𝑥 → ( 𝑦 = 𝑧 ↔ 𝑥 = 𝑧 ) ) | |
| 7 | csbeq1 | ⊢ ( 𝑦 = 𝑥 → ⦋ 𝑦 / 𝑥 ⦌ 𝐵 = ⦋ 𝑥 / 𝑥 ⦌ 𝐵 ) | |
| 8 | csbid | ⊢ ⦋ 𝑥 / 𝑥 ⦌ 𝐵 = 𝐵 | |
| 9 | 7 8 | eqtrdi | ⊢ ( 𝑦 = 𝑥 → ⦋ 𝑦 / 𝑥 ⦌ 𝐵 = 𝐵 ) |
| 10 | 9 | ineq1d | ⊢ ( 𝑦 = 𝑥 → ( ⦋ 𝑦 / 𝑥 ⦌ 𝐵 ∩ ⦋ 𝑧 / 𝑥 ⦌ 𝐵 ) = ( 𝐵 ∩ ⦋ 𝑧 / 𝑥 ⦌ 𝐵 ) ) |
| 11 | 10 | eqeq1d | ⊢ ( 𝑦 = 𝑥 → ( ( ⦋ 𝑦 / 𝑥 ⦌ 𝐵 ∩ ⦋ 𝑧 / 𝑥 ⦌ 𝐵 ) = ∅ ↔ ( 𝐵 ∩ ⦋ 𝑧 / 𝑥 ⦌ 𝐵 ) = ∅ ) ) |
| 12 | 6 11 | orbi12d | ⊢ ( 𝑦 = 𝑥 → ( ( 𝑦 = 𝑧 ∨ ( ⦋ 𝑦 / 𝑥 ⦌ 𝐵 ∩ ⦋ 𝑧 / 𝑥 ⦌ 𝐵 ) = ∅ ) ↔ ( 𝑥 = 𝑧 ∨ ( 𝐵 ∩ ⦋ 𝑧 / 𝑥 ⦌ 𝐵 ) = ∅ ) ) ) |
| 13 | eqeq2 | ⊢ ( 𝑧 = 𝑌 → ( 𝑥 = 𝑧 ↔ 𝑥 = 𝑌 ) ) | |
| 14 | nfcv | ⊢ Ⅎ 𝑥 𝑌 | |
| 15 | 14 2 3 | csbhypf | ⊢ ( 𝑧 = 𝑌 → ⦋ 𝑧 / 𝑥 ⦌ 𝐵 = 𝐶 ) |
| 16 | 15 | ineq2d | ⊢ ( 𝑧 = 𝑌 → ( 𝐵 ∩ ⦋ 𝑧 / 𝑥 ⦌ 𝐵 ) = ( 𝐵 ∩ 𝐶 ) ) |
| 17 | 16 | eqeq1d | ⊢ ( 𝑧 = 𝑌 → ( ( 𝐵 ∩ ⦋ 𝑧 / 𝑥 ⦌ 𝐵 ) = ∅ ↔ ( 𝐵 ∩ 𝐶 ) = ∅ ) ) |
| 18 | 13 17 | orbi12d | ⊢ ( 𝑧 = 𝑌 → ( ( 𝑥 = 𝑧 ∨ ( 𝐵 ∩ ⦋ 𝑧 / 𝑥 ⦌ 𝐵 ) = ∅ ) ↔ ( 𝑥 = 𝑌 ∨ ( 𝐵 ∩ 𝐶 ) = ∅ ) ) ) |
| 19 | 12 18 | rspc2v | ⊢ ( ( 𝑥 ∈ 𝐴 ∧ 𝑌 ∈ 𝐴 ) → ( ∀ 𝑦 ∈ 𝐴 ∀ 𝑧 ∈ 𝐴 ( 𝑦 = 𝑧 ∨ ( ⦋ 𝑦 / 𝑥 ⦌ 𝐵 ∩ ⦋ 𝑧 / 𝑥 ⦌ 𝐵 ) = ∅ ) → ( 𝑥 = 𝑌 ∨ ( 𝐵 ∩ 𝐶 ) = ∅ ) ) ) |
| 20 | 5 19 | biimtrid | ⊢ ( ( 𝑥 ∈ 𝐴 ∧ 𝑌 ∈ 𝐴 ) → ( Disj 𝑥 ∈ 𝐴 𝐵 → ( 𝑥 = 𝑌 ∨ ( 𝐵 ∩ 𝐶 ) = ∅ ) ) ) |
| 21 | 20 | impcom | ⊢ ( ( Disj 𝑥 ∈ 𝐴 𝐵 ∧ ( 𝑥 ∈ 𝐴 ∧ 𝑌 ∈ 𝐴 ) ) → ( 𝑥 = 𝑌 ∨ ( 𝐵 ∩ 𝐶 ) = ∅ ) ) |
| 22 | 21 | ord | ⊢ ( ( Disj 𝑥 ∈ 𝐴 𝐵 ∧ ( 𝑥 ∈ 𝐴 ∧ 𝑌 ∈ 𝐴 ) ) → ( ¬ 𝑥 = 𝑌 → ( 𝐵 ∩ 𝐶 ) = ∅ ) ) |
| 23 | 22 | necon1ad | ⊢ ( ( Disj 𝑥 ∈ 𝐴 𝐵 ∧ ( 𝑥 ∈ 𝐴 ∧ 𝑌 ∈ 𝐴 ) ) → ( ( 𝐵 ∩ 𝐶 ) ≠ ∅ → 𝑥 = 𝑌 ) ) |
| 24 | 23 | 3impia | ⊢ ( ( Disj 𝑥 ∈ 𝐴 𝐵 ∧ ( 𝑥 ∈ 𝐴 ∧ 𝑌 ∈ 𝐴 ) ∧ ( 𝐵 ∩ 𝐶 ) ≠ ∅ ) → 𝑥 = 𝑌 ) |
| 25 | 4 24 | syl3an3 | ⊢ ( ( Disj 𝑥 ∈ 𝐴 𝐵 ∧ ( 𝑥 ∈ 𝐴 ∧ 𝑌 ∈ 𝐴 ) ∧ ( 𝑍 ∈ 𝐵 ∧ 𝑍 ∈ 𝐶 ) ) → 𝑥 = 𝑌 ) |