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Description: Lemma for dath . Rotate triangles Y = P Q R and Z = S T U to allow reuse of analogous proofs. (Contributed by NM, 19-Aug-2012)
| Ref | Expression | ||
|---|---|---|---|
| Hypotheses | dalema.ph | ⊢ ( 𝜑 ↔ ( ( ( 𝐾 ∈ HL ∧ 𝐶 ∈ ( Base ‘ 𝐾 ) ) ∧ ( 𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ 𝑅 ∈ 𝐴 ) ∧ ( 𝑆 ∈ 𝐴 ∧ 𝑇 ∈ 𝐴 ∧ 𝑈 ∈ 𝐴 ) ) ∧ ( 𝑌 ∈ 𝑂 ∧ 𝑍 ∈ 𝑂 ) ∧ ( ( ¬ 𝐶 ≤ ( 𝑃 ∨ 𝑄 ) ∧ ¬ 𝐶 ≤ ( 𝑄 ∨ 𝑅 ) ∧ ¬ 𝐶 ≤ ( 𝑅 ∨ 𝑃 ) ) ∧ ( ¬ 𝐶 ≤ ( 𝑆 ∨ 𝑇 ) ∧ ¬ 𝐶 ≤ ( 𝑇 ∨ 𝑈 ) ∧ ¬ 𝐶 ≤ ( 𝑈 ∨ 𝑆 ) ) ∧ ( 𝐶 ≤ ( 𝑃 ∨ 𝑆 ) ∧ 𝐶 ≤ ( 𝑄 ∨ 𝑇 ) ∧ 𝐶 ≤ ( 𝑅 ∨ 𝑈 ) ) ) ) ) | |
| dalemc.l | ⊢ ≤ = ( le ‘ 𝐾 ) | ||
| dalemc.j | ⊢ ∨ = ( join ‘ 𝐾 ) | ||
| dalemc.a | ⊢ 𝐴 = ( Atoms ‘ 𝐾 ) | ||
| dalemrot.y | ⊢ 𝑌 = ( ( 𝑃 ∨ 𝑄 ) ∨ 𝑅 ) | ||
| dalemrot.z | ⊢ 𝑍 = ( ( 𝑆 ∨ 𝑇 ) ∨ 𝑈 ) | ||
| Assertion | dalemrotyz | ⊢ ( ( 𝜑 ∧ 𝑌 = 𝑍 ) → ( ( 𝑄 ∨ 𝑅 ) ∨ 𝑃 ) = ( ( 𝑇 ∨ 𝑈 ) ∨ 𝑆 ) ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | dalema.ph | ⊢ ( 𝜑 ↔ ( ( ( 𝐾 ∈ HL ∧ 𝐶 ∈ ( Base ‘ 𝐾 ) ) ∧ ( 𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ 𝑅 ∈ 𝐴 ) ∧ ( 𝑆 ∈ 𝐴 ∧ 𝑇 ∈ 𝐴 ∧ 𝑈 ∈ 𝐴 ) ) ∧ ( 𝑌 ∈ 𝑂 ∧ 𝑍 ∈ 𝑂 ) ∧ ( ( ¬ 𝐶 ≤ ( 𝑃 ∨ 𝑄 ) ∧ ¬ 𝐶 ≤ ( 𝑄 ∨ 𝑅 ) ∧ ¬ 𝐶 ≤ ( 𝑅 ∨ 𝑃 ) ) ∧ ( ¬ 𝐶 ≤ ( 𝑆 ∨ 𝑇 ) ∧ ¬ 𝐶 ≤ ( 𝑇 ∨ 𝑈 ) ∧ ¬ 𝐶 ≤ ( 𝑈 ∨ 𝑆 ) ) ∧ ( 𝐶 ≤ ( 𝑃 ∨ 𝑆 ) ∧ 𝐶 ≤ ( 𝑄 ∨ 𝑇 ) ∧ 𝐶 ≤ ( 𝑅 ∨ 𝑈 ) ) ) ) ) | |
| 2 | dalemc.l | ⊢ ≤ = ( le ‘ 𝐾 ) | |
| 3 | dalemc.j | ⊢ ∨ = ( join ‘ 𝐾 ) | |
| 4 | dalemc.a | ⊢ 𝐴 = ( Atoms ‘ 𝐾 ) | |
| 5 | dalemrot.y | ⊢ 𝑌 = ( ( 𝑃 ∨ 𝑄 ) ∨ 𝑅 ) | |
| 6 | dalemrot.z | ⊢ 𝑍 = ( ( 𝑆 ∨ 𝑇 ) ∨ 𝑈 ) | |
| 7 | simpr | ⊢ ( ( 𝜑 ∧ 𝑌 = 𝑍 ) → 𝑌 = 𝑍 ) | |
| 8 | 1 3 4 | dalemqrprot | ⊢ ( 𝜑 → ( ( 𝑄 ∨ 𝑅 ) ∨ 𝑃 ) = ( ( 𝑃 ∨ 𝑄 ) ∨ 𝑅 ) ) |
| 9 | 5 8 | eqtr4id | ⊢ ( 𝜑 → 𝑌 = ( ( 𝑄 ∨ 𝑅 ) ∨ 𝑃 ) ) |
| 10 | 9 | adantr | ⊢ ( ( 𝜑 ∧ 𝑌 = 𝑍 ) → 𝑌 = ( ( 𝑄 ∨ 𝑅 ) ∨ 𝑃 ) ) |
| 11 | 1 | dalemkehl | ⊢ ( 𝜑 → 𝐾 ∈ HL ) |
| 12 | 1 | dalemtea | ⊢ ( 𝜑 → 𝑇 ∈ 𝐴 ) |
| 13 | 1 | dalemuea | ⊢ ( 𝜑 → 𝑈 ∈ 𝐴 ) |
| 14 | 1 | dalemsea | ⊢ ( 𝜑 → 𝑆 ∈ 𝐴 ) |
| 15 | 3 4 | hlatjrot | ⊢ ( ( 𝐾 ∈ HL ∧ ( 𝑇 ∈ 𝐴 ∧ 𝑈 ∈ 𝐴 ∧ 𝑆 ∈ 𝐴 ) ) → ( ( 𝑇 ∨ 𝑈 ) ∨ 𝑆 ) = ( ( 𝑆 ∨ 𝑇 ) ∨ 𝑈 ) ) |
| 16 | 11 12 13 14 15 | syl13anc | ⊢ ( 𝜑 → ( ( 𝑇 ∨ 𝑈 ) ∨ 𝑆 ) = ( ( 𝑆 ∨ 𝑇 ) ∨ 𝑈 ) ) |
| 17 | 6 16 | eqtr4id | ⊢ ( 𝜑 → 𝑍 = ( ( 𝑇 ∨ 𝑈 ) ∨ 𝑆 ) ) |
| 18 | 17 | adantr | ⊢ ( ( 𝜑 ∧ 𝑌 = 𝑍 ) → 𝑍 = ( ( 𝑇 ∨ 𝑈 ) ∨ 𝑆 ) ) |
| 19 | 7 10 18 | 3eqtr3d | ⊢ ( ( 𝜑 ∧ 𝑌 = 𝑍 ) → ( ( 𝑄 ∨ 𝑅 ) ∨ 𝑃 ) = ( ( 𝑇 ∨ 𝑈 ) ∨ 𝑆 ) ) |