This is an inofficial mirror of http://metamath.tirix.org for personal testing of a visualizer extension only.
Description: Lemma for dath . Show the lines P S and Q T are different. (Contributed by NM, 9-Aug-2012)
| Ref | Expression | ||
|---|---|---|---|
| Hypotheses | dalema.ph | ⊢ ( 𝜑 ↔ ( ( ( 𝐾 ∈ HL ∧ 𝐶 ∈ ( Base ‘ 𝐾 ) ) ∧ ( 𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ 𝑅 ∈ 𝐴 ) ∧ ( 𝑆 ∈ 𝐴 ∧ 𝑇 ∈ 𝐴 ∧ 𝑈 ∈ 𝐴 ) ) ∧ ( 𝑌 ∈ 𝑂 ∧ 𝑍 ∈ 𝑂 ) ∧ ( ( ¬ 𝐶 ≤ ( 𝑃 ∨ 𝑄 ) ∧ ¬ 𝐶 ≤ ( 𝑄 ∨ 𝑅 ) ∧ ¬ 𝐶 ≤ ( 𝑅 ∨ 𝑃 ) ) ∧ ( ¬ 𝐶 ≤ ( 𝑆 ∨ 𝑇 ) ∧ ¬ 𝐶 ≤ ( 𝑇 ∨ 𝑈 ) ∧ ¬ 𝐶 ≤ ( 𝑈 ∨ 𝑆 ) ) ∧ ( 𝐶 ≤ ( 𝑃 ∨ 𝑆 ) ∧ 𝐶 ≤ ( 𝑄 ∨ 𝑇 ) ∧ 𝐶 ≤ ( 𝑅 ∨ 𝑈 ) ) ) ) ) | |
| dalemc.l | ⊢ ≤ = ( le ‘ 𝐾 ) | ||
| dalemc.j | ⊢ ∨ = ( join ‘ 𝐾 ) | ||
| dalemc.a | ⊢ 𝐴 = ( Atoms ‘ 𝐾 ) | ||
| dalem1.o | ⊢ 𝑂 = ( LPlanes ‘ 𝐾 ) | ||
| dalem1.y | ⊢ 𝑌 = ( ( 𝑃 ∨ 𝑄 ) ∨ 𝑅 ) | ||
| Assertion | dalem1 | ⊢ ( 𝜑 → ( 𝑃 ∨ 𝑆 ) ≠ ( 𝑄 ∨ 𝑇 ) ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | dalema.ph | ⊢ ( 𝜑 ↔ ( ( ( 𝐾 ∈ HL ∧ 𝐶 ∈ ( Base ‘ 𝐾 ) ) ∧ ( 𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ 𝑅 ∈ 𝐴 ) ∧ ( 𝑆 ∈ 𝐴 ∧ 𝑇 ∈ 𝐴 ∧ 𝑈 ∈ 𝐴 ) ) ∧ ( 𝑌 ∈ 𝑂 ∧ 𝑍 ∈ 𝑂 ) ∧ ( ( ¬ 𝐶 ≤ ( 𝑃 ∨ 𝑄 ) ∧ ¬ 𝐶 ≤ ( 𝑄 ∨ 𝑅 ) ∧ ¬ 𝐶 ≤ ( 𝑅 ∨ 𝑃 ) ) ∧ ( ¬ 𝐶 ≤ ( 𝑆 ∨ 𝑇 ) ∧ ¬ 𝐶 ≤ ( 𝑇 ∨ 𝑈 ) ∧ ¬ 𝐶 ≤ ( 𝑈 ∨ 𝑆 ) ) ∧ ( 𝐶 ≤ ( 𝑃 ∨ 𝑆 ) ∧ 𝐶 ≤ ( 𝑄 ∨ 𝑇 ) ∧ 𝐶 ≤ ( 𝑅 ∨ 𝑈 ) ) ) ) ) | |
| 2 | dalemc.l | ⊢ ≤ = ( le ‘ 𝐾 ) | |
| 3 | dalemc.j | ⊢ ∨ = ( join ‘ 𝐾 ) | |
| 4 | dalemc.a | ⊢ 𝐴 = ( Atoms ‘ 𝐾 ) | |
| 5 | dalem1.o | ⊢ 𝑂 = ( LPlanes ‘ 𝐾 ) | |
| 6 | dalem1.y | ⊢ 𝑌 = ( ( 𝑃 ∨ 𝑄 ) ∨ 𝑅 ) | |
| 7 | 1 | dalemclpjs | ⊢ ( 𝜑 → 𝐶 ≤ ( 𝑃 ∨ 𝑆 ) ) |
| 8 | 1 | dalem-clpjq | ⊢ ( 𝜑 → ¬ 𝐶 ≤ ( 𝑃 ∨ 𝑄 ) ) |
| 9 | 8 | adantr | ⊢ ( ( 𝜑 ∧ ( 𝑃 ∨ 𝑆 ) = ( 𝑄 ∨ 𝑇 ) ) → ¬ 𝐶 ≤ ( 𝑃 ∨ 𝑄 ) ) |
| 10 | 1 | dalemkehl | ⊢ ( 𝜑 → 𝐾 ∈ HL ) |
| 11 | 1 | dalempea | ⊢ ( 𝜑 → 𝑃 ∈ 𝐴 ) |
| 12 | 1 | dalemsea | ⊢ ( 𝜑 → 𝑆 ∈ 𝐴 ) |
| 13 | 2 3 4 | hlatlej1 | ⊢ ( ( 𝐾 ∈ HL ∧ 𝑃 ∈ 𝐴 ∧ 𝑆 ∈ 𝐴 ) → 𝑃 ≤ ( 𝑃 ∨ 𝑆 ) ) |
| 14 | 10 11 12 13 | syl3anc | ⊢ ( 𝜑 → 𝑃 ≤ ( 𝑃 ∨ 𝑆 ) ) |
| 15 | 14 | adantr | ⊢ ( ( 𝜑 ∧ ( 𝑃 ∨ 𝑆 ) = ( 𝑄 ∨ 𝑇 ) ) → 𝑃 ≤ ( 𝑃 ∨ 𝑆 ) ) |
| 16 | 1 | dalemqea | ⊢ ( 𝜑 → 𝑄 ∈ 𝐴 ) |
| 17 | 1 | dalemtea | ⊢ ( 𝜑 → 𝑇 ∈ 𝐴 ) |
| 18 | 2 3 4 | hlatlej1 | ⊢ ( ( 𝐾 ∈ HL ∧ 𝑄 ∈ 𝐴 ∧ 𝑇 ∈ 𝐴 ) → 𝑄 ≤ ( 𝑄 ∨ 𝑇 ) ) |
| 19 | 10 16 17 18 | syl3anc | ⊢ ( 𝜑 → 𝑄 ≤ ( 𝑄 ∨ 𝑇 ) ) |
| 20 | 19 | adantr | ⊢ ( ( 𝜑 ∧ ( 𝑃 ∨ 𝑆 ) = ( 𝑄 ∨ 𝑇 ) ) → 𝑄 ≤ ( 𝑄 ∨ 𝑇 ) ) |
| 21 | simpr | ⊢ ( ( 𝜑 ∧ ( 𝑃 ∨ 𝑆 ) = ( 𝑄 ∨ 𝑇 ) ) → ( 𝑃 ∨ 𝑆 ) = ( 𝑄 ∨ 𝑇 ) ) | |
| 22 | 20 21 | breqtrrd | ⊢ ( ( 𝜑 ∧ ( 𝑃 ∨ 𝑆 ) = ( 𝑄 ∨ 𝑇 ) ) → 𝑄 ≤ ( 𝑃 ∨ 𝑆 ) ) |
| 23 | 1 | dalemkelat | ⊢ ( 𝜑 → 𝐾 ∈ Lat ) |
| 24 | 1 4 | dalempeb | ⊢ ( 𝜑 → 𝑃 ∈ ( Base ‘ 𝐾 ) ) |
| 25 | 1 4 | dalemqeb | ⊢ ( 𝜑 → 𝑄 ∈ ( Base ‘ 𝐾 ) ) |
| 26 | eqid | ⊢ ( Base ‘ 𝐾 ) = ( Base ‘ 𝐾 ) | |
| 27 | 26 3 4 | hlatjcl | ⊢ ( ( 𝐾 ∈ HL ∧ 𝑃 ∈ 𝐴 ∧ 𝑆 ∈ 𝐴 ) → ( 𝑃 ∨ 𝑆 ) ∈ ( Base ‘ 𝐾 ) ) |
| 28 | 10 11 12 27 | syl3anc | ⊢ ( 𝜑 → ( 𝑃 ∨ 𝑆 ) ∈ ( Base ‘ 𝐾 ) ) |
| 29 | 26 2 3 | latjle12 | ⊢ ( ( 𝐾 ∈ Lat ∧ ( 𝑃 ∈ ( Base ‘ 𝐾 ) ∧ 𝑄 ∈ ( Base ‘ 𝐾 ) ∧ ( 𝑃 ∨ 𝑆 ) ∈ ( Base ‘ 𝐾 ) ) ) → ( ( 𝑃 ≤ ( 𝑃 ∨ 𝑆 ) ∧ 𝑄 ≤ ( 𝑃 ∨ 𝑆 ) ) ↔ ( 𝑃 ∨ 𝑄 ) ≤ ( 𝑃 ∨ 𝑆 ) ) ) |
| 30 | 23 24 25 28 29 | syl13anc | ⊢ ( 𝜑 → ( ( 𝑃 ≤ ( 𝑃 ∨ 𝑆 ) ∧ 𝑄 ≤ ( 𝑃 ∨ 𝑆 ) ) ↔ ( 𝑃 ∨ 𝑄 ) ≤ ( 𝑃 ∨ 𝑆 ) ) ) |
| 31 | 30 | adantr | ⊢ ( ( 𝜑 ∧ ( 𝑃 ∨ 𝑆 ) = ( 𝑄 ∨ 𝑇 ) ) → ( ( 𝑃 ≤ ( 𝑃 ∨ 𝑆 ) ∧ 𝑄 ≤ ( 𝑃 ∨ 𝑆 ) ) ↔ ( 𝑃 ∨ 𝑄 ) ≤ ( 𝑃 ∨ 𝑆 ) ) ) |
| 32 | 15 22 31 | mpbi2and | ⊢ ( ( 𝜑 ∧ ( 𝑃 ∨ 𝑆 ) = ( 𝑄 ∨ 𝑇 ) ) → ( 𝑃 ∨ 𝑄 ) ≤ ( 𝑃 ∨ 𝑆 ) ) |
| 33 | 1 | dalemrea | ⊢ ( 𝜑 → 𝑅 ∈ 𝐴 ) |
| 34 | 1 | dalemyeo | ⊢ ( 𝜑 → 𝑌 ∈ 𝑂 ) |
| 35 | 3 4 5 6 | lplnri1 | ⊢ ( ( 𝐾 ∈ HL ∧ ( 𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ 𝑅 ∈ 𝐴 ) ∧ 𝑌 ∈ 𝑂 ) → 𝑃 ≠ 𝑄 ) |
| 36 | 10 11 16 33 34 35 | syl131anc | ⊢ ( 𝜑 → 𝑃 ≠ 𝑄 ) |
| 37 | 2 3 4 | ps-1 | ⊢ ( ( 𝐾 ∈ HL ∧ ( 𝑃 ∈ 𝐴 ∧ 𝑄 ∈ 𝐴 ∧ 𝑃 ≠ 𝑄 ) ∧ ( 𝑃 ∈ 𝐴 ∧ 𝑆 ∈ 𝐴 ) ) → ( ( 𝑃 ∨ 𝑄 ) ≤ ( 𝑃 ∨ 𝑆 ) ↔ ( 𝑃 ∨ 𝑄 ) = ( 𝑃 ∨ 𝑆 ) ) ) |
| 38 | 10 11 16 36 11 12 37 | syl132anc | ⊢ ( 𝜑 → ( ( 𝑃 ∨ 𝑄 ) ≤ ( 𝑃 ∨ 𝑆 ) ↔ ( 𝑃 ∨ 𝑄 ) = ( 𝑃 ∨ 𝑆 ) ) ) |
| 39 | 38 | adantr | ⊢ ( ( 𝜑 ∧ ( 𝑃 ∨ 𝑆 ) = ( 𝑄 ∨ 𝑇 ) ) → ( ( 𝑃 ∨ 𝑄 ) ≤ ( 𝑃 ∨ 𝑆 ) ↔ ( 𝑃 ∨ 𝑄 ) = ( 𝑃 ∨ 𝑆 ) ) ) |
| 40 | 32 39 | mpbid | ⊢ ( ( 𝜑 ∧ ( 𝑃 ∨ 𝑆 ) = ( 𝑄 ∨ 𝑇 ) ) → ( 𝑃 ∨ 𝑄 ) = ( 𝑃 ∨ 𝑆 ) ) |
| 41 | 40 | breq2d | ⊢ ( ( 𝜑 ∧ ( 𝑃 ∨ 𝑆 ) = ( 𝑄 ∨ 𝑇 ) ) → ( 𝐶 ≤ ( 𝑃 ∨ 𝑄 ) ↔ 𝐶 ≤ ( 𝑃 ∨ 𝑆 ) ) ) |
| 42 | 9 41 | mtbid | ⊢ ( ( 𝜑 ∧ ( 𝑃 ∨ 𝑆 ) = ( 𝑄 ∨ 𝑇 ) ) → ¬ 𝐶 ≤ ( 𝑃 ∨ 𝑆 ) ) |
| 43 | 42 | ex | ⊢ ( 𝜑 → ( ( 𝑃 ∨ 𝑆 ) = ( 𝑄 ∨ 𝑇 ) → ¬ 𝐶 ≤ ( 𝑃 ∨ 𝑆 ) ) ) |
| 44 | 43 | necon2ad | ⊢ ( 𝜑 → ( 𝐶 ≤ ( 𝑃 ∨ 𝑆 ) → ( 𝑃 ∨ 𝑆 ) ≠ ( 𝑄 ∨ 𝑇 ) ) ) |
| 45 | 7 44 | mpd | ⊢ ( 𝜑 → ( 𝑃 ∨ 𝑆 ) ≠ ( 𝑄 ∨ 𝑇 ) ) |