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Description: Two Hilbert lattice elements have the dual modular pair property if the second is an atom. Part of Exercise 6 of Kalmbach p. 103. (Contributed by NM, 22-Jun-2004) (New usage is discouraged.)
| Ref | Expression | ||
|---|---|---|---|
| Assertion | atmd2 | ⊢ ( ( 𝐴 ∈ Cℋ ∧ 𝐵 ∈ HAtoms ) → 𝐴 𝑀ℋ 𝐵 ) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | cvp | ⊢ ( ( 𝐴 ∈ Cℋ ∧ 𝐵 ∈ HAtoms ) → ( ( 𝐴 ∩ 𝐵 ) = 0ℋ ↔ 𝐴 ⋖ℋ ( 𝐴 ∨ℋ 𝐵 ) ) ) | |
| 2 | atelch | ⊢ ( 𝐵 ∈ HAtoms → 𝐵 ∈ Cℋ ) | |
| 3 | cvexch | ⊢ ( ( 𝐴 ∈ Cℋ ∧ 𝐵 ∈ Cℋ ) → ( ( 𝐴 ∩ 𝐵 ) ⋖ℋ 𝐵 ↔ 𝐴 ⋖ℋ ( 𝐴 ∨ℋ 𝐵 ) ) ) | |
| 4 | cvmd | ⊢ ( ( 𝐴 ∈ Cℋ ∧ 𝐵 ∈ Cℋ ∧ ( 𝐴 ∩ 𝐵 ) ⋖ℋ 𝐵 ) → 𝐴 𝑀ℋ 𝐵 ) | |
| 5 | 4 | 3expia | ⊢ ( ( 𝐴 ∈ Cℋ ∧ 𝐵 ∈ Cℋ ) → ( ( 𝐴 ∩ 𝐵 ) ⋖ℋ 𝐵 → 𝐴 𝑀ℋ 𝐵 ) ) |
| 6 | 3 5 | sylbird | ⊢ ( ( 𝐴 ∈ Cℋ ∧ 𝐵 ∈ Cℋ ) → ( 𝐴 ⋖ℋ ( 𝐴 ∨ℋ 𝐵 ) → 𝐴 𝑀ℋ 𝐵 ) ) |
| 7 | 2 6 | sylan2 | ⊢ ( ( 𝐴 ∈ Cℋ ∧ 𝐵 ∈ HAtoms ) → ( 𝐴 ⋖ℋ ( 𝐴 ∨ℋ 𝐵 ) → 𝐴 𝑀ℋ 𝐵 ) ) |
| 8 | 1 7 | sylbid | ⊢ ( ( 𝐴 ∈ Cℋ ∧ 𝐵 ∈ HAtoms ) → ( ( 𝐴 ∩ 𝐵 ) = 0ℋ → 𝐴 𝑀ℋ 𝐵 ) ) |
| 9 | atnssm0 | ⊢ ( ( 𝐴 ∈ Cℋ ∧ 𝐵 ∈ HAtoms ) → ( ¬ 𝐵 ⊆ 𝐴 ↔ ( 𝐴 ∩ 𝐵 ) = 0ℋ ) ) | |
| 10 | 9 | con1bid | ⊢ ( ( 𝐴 ∈ Cℋ ∧ 𝐵 ∈ HAtoms ) → ( ¬ ( 𝐴 ∩ 𝐵 ) = 0ℋ ↔ 𝐵 ⊆ 𝐴 ) ) |
| 11 | ssmd2 | ⊢ ( ( 𝐵 ∈ Cℋ ∧ 𝐴 ∈ Cℋ ∧ 𝐵 ⊆ 𝐴 ) → 𝐴 𝑀ℋ 𝐵 ) | |
| 12 | 11 | 3com12 | ⊢ ( ( 𝐴 ∈ Cℋ ∧ 𝐵 ∈ Cℋ ∧ 𝐵 ⊆ 𝐴 ) → 𝐴 𝑀ℋ 𝐵 ) |
| 13 | 2 12 | syl3an2 | ⊢ ( ( 𝐴 ∈ Cℋ ∧ 𝐵 ∈ HAtoms ∧ 𝐵 ⊆ 𝐴 ) → 𝐴 𝑀ℋ 𝐵 ) |
| 14 | 13 | 3expia | ⊢ ( ( 𝐴 ∈ Cℋ ∧ 𝐵 ∈ HAtoms ) → ( 𝐵 ⊆ 𝐴 → 𝐴 𝑀ℋ 𝐵 ) ) |
| 15 | 10 14 | sylbid | ⊢ ( ( 𝐴 ∈ Cℋ ∧ 𝐵 ∈ HAtoms ) → ( ¬ ( 𝐴 ∩ 𝐵 ) = 0ℋ → 𝐴 𝑀ℋ 𝐵 ) ) |
| 16 | 8 15 | pm2.61d | ⊢ ( ( 𝐴 ∈ Cℋ ∧ 𝐵 ∈ HAtoms ) → 𝐴 𝑀ℋ 𝐵 ) |